Questions tagged [continuity]

Intuitively, a continuous function is one where small changes of input result in correspondingly small changes of output. Use this tag for questions involving this concept. As there are many mathematical formalizations of continuity, please also use an appropriate subject tag such as (real-analysis) or (general-topology)

Analytic Definition: Let $(X, d_X)$ and $(Y, d_Y)$ be metric spaces. A map $f : X \to Y$ is said to be continuous at $x_0$ if for every $\varepsilon > 0$, there is $\delta > 0$ such that $d_Y(f(x_0), f(x)) < \delta$ whenever $d_X(x_0, x) < \varepsilon$. A map $f : X \to Y$ is said to be continuous if it is continuous at $x_0$ for all $x_0 \in X$.

Topological Definition: Let $(X,\mathcal T_X)$ and $(Y, \mathcal T_Y)$ be topological spaces. A map $f : X \to Y$ is said to be continuous if $U \in \mathcal T_Y$ implies that $f^{-1}(U) \in \mathcal T_X$.

In the case of metric spaces, the metric induces a topology, and the two notions of continuity coincide. Note that multiple metrics can induce the same topology, and that not all topologies are metrizable (can be generated from some metric).

Continuity is a sufficient condition for the intermediate value theorem. It is also a necessary condition for the extreme value theorem, as well as differentiability.

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Show that $f(x,y)=\begin{cases} \frac{\phi(x) - \phi(y)}{x-y} & x \not = y\\ \phi'(x) & x=y \end{cases}$ is continuous

Let $\phi \in C^1(\Bbb R; \Bbb R) $ and $f: \Bbb R^2 \to \Bbb R;$ $f(x,y)=\begin{cases} \frac{\phi(x) - \phi(y)}{x-y} & x \not = y\\ \phi'(x) & x=y \end{cases}$ Show that $f$ is continuous. My attempt: Clearly $f$ is continous on $\Bbb R^2…
Travis
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Is $g(x)= \frac{x}{1-\left | x \right |}$ uniformly continuous?

I was asked to prove that the function: $$ g: B \subset \mathbb{R}^n \rightarrow \mathbb{R}^n $$ Is uniformly continuous on $B$, where $B$ is the open ball $B(0,1) \subset \mathbb{R}^n$ y $g(x)= \frac{x}{1-\left | x \right |}$ My attempt I tried to…
Chia
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Checking Continuity of functions

Consider a function $\sqrt {x-1}$+$\sqrt{1-x}$.From here we can see that domain of the function is just 1 and range is 0.Still the function is continious at x=1 even though RHL and LHL limit doesn't exist. Can you guys tell me how this is possible.…
user501655
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How to show that for a continuous function on $\mathbb{R}$ that satisfies $-f(-x)=f(x)$ for all $x \neq0$ then $f(0)=0$

How to show that for a continuous function on $\mathbb{R}$ that satisfies $-f(-x)=f(x)$ for all $x \neq0$ then $f(0)=0$ For $-f(-x)=f(x)$ to be true, it appears we must have an odd function without a constant at the end. You can tell this from…
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Using modulus to answer: "How close to $\pi$ do we need $x$ to be for $x^2$ to be within $10^{−100}$ of $\pi ^2$?"

I'm studying the book: "The Princeton companion to mathematics", I'm in the part of fundamentals: continuity. There is an example I don't get: How close to $\pi$ do we need $x$ to be for $x^2$ to be within $10^{−100}$ of $\pi ^2$? To answer this,…
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Discontinuity of f(x) = {0 in 0 and 1 for x>0}

Given this function: Domain = $\{x\in \Bbb R: x\geq 0\}$ $f(0)=0$ and $f(x)=1$ for $x > 0$ The function is discontinued in $x=0$ but what kind of discontinuity? Calssification: https://en.wikipedia.org/wiki/Classification_of_discontinuities I…
asv
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Study the continuity of the following function that is called Riemann function

I have the following function $$f(x)= \begin{cases} |x|& \text{if $x$ is irrational or } x =0 , \\[6pt] \frac {p}{q+1} & \text{if } x=\frac pq, p\in\mathbb Z,q\in\mathbb N ,\,\, \gcd(p,q)=1.\end{cases}$$ I'd like to determine the set of points of…
user62498
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Checking the continuity of a function at a point.

$$f(x)= \begin{cases} x ; x\le 1 \\ 5;x \gt 1 \end{cases}$$ For example, if I have to check the continuity at $x=0$, I'd simply do, $$f(0)=0$$ also,$$\lim_{x \to 0}x=0=f(0)$$ Hence, $f$ is continuous at $x=0$. But the solution manual does…
Raknos13
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The square function is not continuous?

I understand that $f:X\rightarrow Y$ is continuous if the pre-image of an open in $Y$ is open in $X$. Take $f(x)=x²$ as a function $\mathbb{R}\rightarrow \mathbb{R}$. Then $f^{-1}((-1,1))=[0,1)$ so the square function is not continuous(?). However…
John
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Proving a simple functional is continuous

I recently took real analysis at my school, and enjoyed it thoroughly. I decided to use some of my Summer to study variational calculus, and wanted some verification of my work (or correct work if I'm wrong) for this example. Let the functional…
infinitylord
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Why unit vector function is continuous?

I wonder why $\dfrac{x}{\|x\|}$ is a continuous function, $x$ is a vector in $\mathbb{R}^{n}$. I have read in this site that the quotient of two continuous functions is continuous, but in books, there is no theorem that says that in case that we…
HeMan
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$f:(0,\infty)\rightarrow \Bbb R$, $x\mapsto 1/x$ show that f is continuous

$f:(0,\infty)\rightarrow \Bbb R$, $x\mapsto 1/x$ show that $f$ is continuous. To prove the continuity on the given domain, for each $x_0\in(0,\infty)$ and $\epsilon>0$ we need to determine a $\delta(x_0,\epsilon)$ which satisfies…
delog
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Show that $f(x) =x\sin(1/x)$ if $x>0$, $f(x)=0$ if $x\leq 0$, is continuous

How to show that the following function is continuous: $$f(x) = \cases{x\sin\frac{1}{x}\quad x>0\\ 0\quad\quad \quad\,\,x\leq 0}$$ $f(x)$ is continuous at $x=a$ iff $$\forall \epsilon >0,\quad\exists\delta:|x-a|<\delta\implies|f(x)-f(a)|<\epsilon$$…
mrnovice
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continuous function from subspace $\mathbb{Q}$ to $\mathbb{R}$

f:$\mathbb{R} \rightarrow \mathbb{R}$ such that f(x)=a, for all x$\in\mathbb{R}$ is continuous function. $\mathbb{Q}$ is a subspace of $\mathbb{R}$ and hence f:$\mathbb{Q} \rightarrow \mathbb{R}$ such that f(x)=a, for all x$\in\mathbb{Q}$ is also…
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projection onto first coordinate continuous

Show $f:\mathbb{R}^2\to\mathbb{R}, f(x_1,x_2)=x_1$ is continuous. How should I proceed? Fix $\epsilon>0 |f(x_1,x_2)-f(x_3,x_4)|<\epsilon\Rightarrow |x_1-x_3|<\epsilon\Rightarrow$ choose $\delta=\epsilon$ $A$ is open in $\mathbb{R}$,…
Myshkin
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