Questions tagged [determinant]

Questions about determinants: their computation or their theory. If $E$ is a vector space of dimension $d$, then we can compute the determinant of a $d$-uple $(v_1,\ldots,v_d)$ with respect to a basis.

The determinant is a value that can be computed from the entries of a square matrix. This value is different from $0$ if and only if the matrix has an inverse and the determinant of the identity matrix is equal to $1$. For instance, for a $2\times 2$ matrix whose entries of the first line are $a$ and $b$ and whose entries of the second line are $c$ and $d$, the determinant is $ad-bc$.

If $f\colon\mathbb{R}^n\longrightarrow\mathbb{R}^n$ is a linear map and if $b$ is a basis of $\mathbb{R}^n$, then the determinant of the matrix of $f$ with respect to $b$ does not depend upon the choice of $b$; this number is called the determinant of $f$. The linear map $f$ has an inverse if and only if its determinant is not $0$.

Determinants are useful in the analysis of systems of linear equations and in the study of endomorphisms of finite-dimensional vector spaces.

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If $A$ is an invertible matrix of order 2, then $|A^*|$ is (where $A^*$ is inverse of matrix $A$)

I am having some formula without proof (u can find it by ur self) $\def\adj{\operatorname{adj}}$ $A^* = 1/|A| \cdot \adj A $ and $|\adj A| = |A|^{n-1}$ where $n$ is order of matrix By using these formulae $$\begin{align} |A^*| &= 1/|A| \cdot |\adj…
5 Dots
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Let $A$ be a $3×3$ matrix such that $A^2 = 2A$. Prove that $det(A)$ must be either $0$ or $8$.

I have no clue about how to start this problem. Could someone help me with this?
XDXDXD
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Understanding matrix of cofactors

Suppose we're working within the vector space of $2 \times 2$ matrices over $\mathbb{R}$. For any matrix, $$A = \begin{pmatrix} a & b \\ c & d \end{pmatrix},$$ it should be the case that, irrespective of whether or not $A$ is invertible, there…
user465188
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Any element $A^{i}_{j}$ of $A$ is a $1\times1$ minor of $A$

In a textbook is said "Any element $A^{i}_{j}$ of $A$ is a $1\times1$ minor of $A$" How is this should be understood? As I know minor of $A^{i}_{j}$ element is the determinant of the matrix left after removing $i^{th}$ row and $j^{th}$ column.
Tursinbay
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Find all $x \in \mathbb{R}$ that matrix $A$ is invertible

I have to find all $x \in \mathbb{R}$ that matrix $A$ is invertible. $$ \begin{vmatrix} 1&1&1&1\\ 1&2x&3&4\\ 2&3&4x&5\\ 3&4&5&6x \end{vmatrix} $$ I know that matrix is invertible, when $det(A)$ is not $0$. So I got to this point…
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3rd order determinant is formed using 0 & 1 as its elements. How many determinant will give value 0.

The value of determinant can either be -2,-1,0,1,2 where number of determinant with value 2 will be equal to that of determinant with value -2. Same goes with 1 and -1.
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value of k so that equation have non zero soution

\begin{equation} x+ky-z=0 \end{equation} \begin{equation} 3x-ky+z=0 \end{equation} \begin{equation} x-3y+z=0 \end{equation} the problem that I am having is that it's in the form homogeneous equation so $x=y=z=0$. Thus, my answer is that it can take…
B Luthra
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Problem with determinants and polynomials $\left|\begin{smallmatrix}P(a)&&Q(a)&&R(a)\\P(b)&&Q(b)&&R(b)\\P(c)&&Q(c)&&R(c)\end{smallmatrix}\right|=1$

Let $P,Q,R$ be polynomials of degree less than 2 and $a,b,c \in \mathbb{C}$ such that $D(a,b,c)=\begin{vmatrix}P(a)&&Q(a)&&R(a)\\P(b)&&Q(b)&&R(b)\\P(c)&&Q(c)&&R(c)\end{vmatrix}=1$ Prove that $D(1,b,c)+D(a,1,c)+D(a,b,1)=D(a,b,c)$. My…
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defining the determinant of a matrix combined of function

I have the following question: f1(x),....fn(x) belong to polynomial space with a degree less or equal to n-2 a1,....an belong to the real numbers. what is the determinant of matrix A ?
KIMKES1232
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What is the simplest way to calculate this determinant using properties of determinants?

A=$\begin{bmatrix} \frac ab & \frac bc & \frac ca\\a & b & c\\ab & bc & ca\end{bmatrix}$ Or maby there is no shorcut to calculate the det(A)?
mBart
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value of $\det(P^2+Q^2)$

If $P$ and $Q$ be $3\times 3$ matrices and $P\neq Q. $ If $P^3=Q^3$ and $P^2Q=Q^2P.$ Then $\det(P^2+Q^2)$ is Try: From $P^3-Q^3=O\Rightarrow (P-Q)(P^2+PQ+Q^2)=O$ So either $P=Q$ or either $P^2+PQ+Q^2=O$ So $P^2+Q^2=-PQ$, Now i did not understand…
DXT
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Can you "split" a determinant along multiple rows or columns?

I know that a matrix A given by: $$ \begin{vmatrix} (a + x) & (b + y) & (c + z) \\\ p & q & r \\\ s & t & u \end{vmatrix} $$ can be split as $$ \begin{vmatrix} a & b & c \\\ p & q & r \\\ s & t & u \end{vmatrix} + \begin{vmatrix} x & y & z \\\ p & q…
WorldGov
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Factoring the determinant of a particular matrix that depends on three parameters

Show that $a+b+c$ is a factor of $$\det \begin{pmatrix} b+c & a & a^3\\ c+a & b & b^3\\ a+b & c & c^3 \end{pmatrix}$$ and express the determinant as a product of five factors. I was able to get the first phase of the question but the second…
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Prove the determinant $[b_{ij}]_{n \times n}=(-1)^{n-1}(n-1)[a_{ij}]_{n \times n}$

If $b_{ij}=(a_{i1}+a_{i2}+\cdots+a_{in})-a_{ij}$, show that: $\begin{vmatrix} b_{11} & \cdots & b_{1n} \\ \vdots &&\vdots\\b_{n1} & \cdots & b_{nn} \end{vmatrix} = (-1)^{n-1}(n-1)\begin{vmatrix} a_{11} & \cdots & a_{1n} \\ \vdots &&\vdots\\a_{n1}…
weilam06
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