Questions tagged [divisibility]

This tag is for questions about divisibility, that is, determining when one thing is a multiple of another thing.

If $a$ and $b$ are integers, $a$ divides $b$ if $b=ca$ for some integer $c$. This is denoted $a\mid b$. It is usually studied in introductory courses in number theory, so add if appropriate.

A common notation used for the phrase "$a$ divides $b$" is $a|b$. It is also common to negate the notation by adding a slash like this: "$c$ does not divide $d$" written as $c\nmid d$. Note that the order is important: for example, $2|4$ but "$4\nmid 2$".

This notion can be generalized to any ring. The definition is the same: For two elements $a$ and $b$ of a commutative ring $R$, $a$ divides $b$ if $ac=b$ for some $c$ in $R$.

Divisibility in commutative rings corresponds exactly to containment the poset of principal ideals. That is, $a$ divides $b$ if and only if $aR\subseteq bR$. For commutative rings like principal ideal rings, this means that divisibility mirrors exactly the poset of all ideals of the ring.

The topics appropriate for this tag include, for example:

  • Questions about the relation $\mid$.
  • Questions about the GCD and LCM.

There are divisibility rule that is a shorthand way of determining whether a given integer is divisible by a fixed divisor without performing the division, usually by examining its digits.

6170 questions
2
votes
3 answers

System of two simple modular equations

$$x \equiv -7 \mod 13$$ $$x \equiv 39 \mod 15$$ I need to find the smallest x for which these equations can be solved. I've been always doing this using Chinese Reminder Theorem, but it seems that it doesn't work here, I'm not sure why though. Let's…
khernik
  • 1,369
2
votes
0 answers

Finding value when divider equals $0$

I'm having trouble calculating the result of an equation. The equation consist of: $$n = \frac{(y - z)}{(b - a)}$$ I'm attempting to find $n$ when I have all of the other values. In some of my calculations, $b - a = 0$, which means that I end up…
Martin
  • 135
2
votes
4 answers

Prove divisibility using linear congruences

I need to prove that: $$10|(53^{53} - 33^{33})$$ I can and should only use linear congruences ($a \equiv b \mod n$) - how can I do this?
khernik
  • 1,369
2
votes
2 answers

What is the smallest natural number divisible by the first $n$ natural numbers?

For example, for the numbers 1 to 10, one can just find the necessary factors and multiply them: $5 \times 7 \times 8 \times 9 = 2520$, and all the other numbers in that range follow. But with larger ranges, larger numbers logically result. Is there…
Lee Sleek
  • 1,682
2
votes
3 answers

Are smaller divisors more "likely" to produce integer and near-integer quotients?

For example, if we divide 100 by 50, then 100 by 49.8, then 49.8, etc. down to 100 divided by 1, we will have a list of 491 quotients, 10 of which are integers (2, 4, 5, 8, 10, 20, 25, 40, 50, 100). For the first 250 divisors (50.0 through 25.1),…
user90664
  • 43
  • 4
2
votes
4 answers

find remainder $\frac{ 11111\ldots1111 \text{ (105 ones )}} {107}$

Find the remainder of $\dfrac{1111\ldots111 \mspace{10mu}}{107}$ (105 ones) into 107 . So I assumed that $1111\ldots \text{ (105 ones)}$ is going to be exactly divided by $11111 \text{ (5 ones)}$ $ 21 \text{ times}$ $(105/5 =…
Hrackadont
  • 545
  • 2
  • 7
2
votes
3 answers

Can divisibility rules for digits be generalized to sum of digits

Suppose that we are given a two digit number $AB$, where $A$ and $B$ represents the digits, i.e 21 would be A=2 , B=1. I wish to prove that the sum of $AB$ and $BA$ is always divisible by $11$. My initial idée was to use the fact that if a number…
user649348
2
votes
1 answer

How to divide by decimal quickly?

My friend asked me to help solve a problem in which she cannot use a calculator. $$ \require{enclose} \begin{array}{r} 32.45 \enclose{longdiv}{253.11} \\[-3pt] \end{array} $$ What is the best method to approach this in an exam situation - i.e.…
alicook
  • 21
2
votes
4 answers

Divisibility (Modular Arithmetics)

Consider you are given that $$4a2b$$ and this number can be divided by $36$. How would I evaluate the values for $a$ and $b$ that satifsy with our condition? Let us try to write it mathematically, whereupon we will have that $$4000+100a+20+b…
Busi
  • 572
2
votes
3 answers

Largest integer less than 999 with $(n-1)^2\mid n^{2016}-1$

What is the largest integer $n<999$ such that $(n-1)^2$ divides $n^{2016}-1$? I don't know how to approach this problem, I have tried factoring $n^{2016}-1$, do I randomly pick factors and try to guess the number?
SuperMage1
  • 2,486
2
votes
0 answers

Help: Is there a way to determine how many pairs of elements in a set of integers divide evenly?

I'm not a mathematician, so I may be asking this in an ambiguous way. I'll restate in a way that makes sense to me just in case. In the set [2, 5, 9] there are no pairs that can divide evenly. In the set [2, 4, 16] 2/4, 2/16, and 4/16, so there are…
2
votes
1 answer

divisibility by (n-1) in base n

I Just found out that if I want to check if a number in base $n$ is divisible by $n-1$, I just need to sum all the digits, again and again, until I get to a single character, and if this number is $n-1$, then this number is divisible by $n-1$. For…
sheldonzy
  • 667
2
votes
2 answers

All divisors of $24^{100}-1$ are written out. Prove that the sum of all the numbers written is a multiple of 24.

I am pretty much stuck, since smaller examples are impossible to find, nor does this seem like an induction question. I am thinking of using proof by contradiction, but don't know where to find the contradiction. I also struggle to recall the…
Gerard L.
  • 2,536
2
votes
2 answers

Does not $0\mid 0$ contradicts that divisibility by zero is undefined?

Does not $0\mid 0$ contradicts that divisibility by zero is undefined? Could anyone clarify this for me please?
Emptymind
  • 1,901
2
votes
2 answers

Facts about Divisibility

I know that if $a\mid b$ and $a\mid c$, then $a\mid sb+tc$ for all $s,t$. Is this line below true? $$a\mid c\land\forall s,t:a\mid sb+tc\implies a\mid b$$
xuoimai
  • 89