Questions tagged [frobenius-method]

Use this tag when you want to solve a linear ordinary differential equation with variable coefficients via the Frobenius method.

The Frobenius method or, Method of Frobenius, attributed to the german mathemematican Ferdinand Georg Frobenius , is a generalization of the power series method for finding an infinite series solution for a linear ordinary differential equation (ODE) with variable coefficients. In fact, when an ODE has regular singular points, power series method fails to provide enough linearly independent solutions. In such a case, Frobenius method comes to our aid.

Method:

Assume that $~x_0=0~$ is regular singular point of the differential equation $$P(x)~y''(x)+Q(x)~y'+R(x)~y=0$$

A Frobenius series (generalized Laurent series) of the form $$y=x^r~\sum_{n=0}^{\infty}a_n~x^{n}=\sum_{n=0}^{\infty}a_n~x^{n+r},\qquad a_0\neq 0 $$

can be used to solve the differential equation. The parameter$~r~$ must be chosen so that when the series is substituted into the D.E. the coefficient of the smallest power of $~x~$ is zero. This is called the indicial equation. Next, a recursive equation for the coefficients is obtained by setting the coefficient of$~x^{n+r}~$equal to zero.

Caveat: There are some instances when only one Frobenius solution can be constructed.

References:

https://en.wikipedia.org/wiki/Frobenius_method

http://mathworld.wolfram.com/FrobeniusMethod.html

http://home.iitk.ac.in/~sghorai/TEACHING/MTH203/ode14.pdf

http://www.math.mcgill.ca/gantumur/math315w14/downloads/frobenius.pdf

234 questions
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Indical equation of Frobenius Method

So I'm getting ready for the exam by doing last years exam. It gives a DE which goes as following $$(x^2-x)y''+(4x-2)y'+2y=0$$ This gives…
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Frobenius Method: derivatives of y

http://mathworld.wolfram.com/FrobeniusMethod.html Was reading this and was wondering why the $n$ does not increase while computing the derivatives of $y$ in the frobenius method. In the first derivative for example, shouldn't the sum be from $n=1$…
Kon
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Frobenius method applied to $x^2y''+(x^2-x)y'+2y=0$

Using Frobenius method for solving the ODE $$x^2y''+(x^2-x)y'+2y=0$$ I am getting roots of inicial equation as $1 + i$ and $1 - i$ so I am not getting to solve when the roots are complex. Any help is appreciated.
nick
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Frobenius Method of a differential equation

I have the following differential equation $$4xy''+2(x+1)y'+y=0$$ I need to use the Frobenius method to determine the indicial equation, recurrance relation and the roots of the indicial equation. So far I have $$\sum_{n=0}^\infty…