Questions tagged [fubini-tonelli-theorems]

For questions related to the Fubini-Tonelli theorem, a theorem for interchanging integrals.

The Fubini–Tonelli theorem, a combination of Fubini's theorem and Tonelli's theorem, states that if $X$ and $Y$ are $σ$-finite measure spaces, and if $f$ is a measurable function, then $$\int_X \left( \int_Y |f(x, y)| dy \right) dx = \int_Y \left( \int_X |f(x, y)| dx \right) dy = \int_{X \times Y} |f(x, y)| \, d(x, y)$$

If any of the three above integrals are finite, then $$\int_X \left( \int_Y f(x, y) dy \right) dx = \int_Y \left( \int_X f(x, y) dx \right) dy = \int_{X \times Y} f(x, y) \, d(x, y)$$

The advantage of the Fubini–Tonelli over Fubini's theorem is that the repeated integrals of the absolute value of $|f|$ may be easier to study than the double integral. As in Fubini's theorem, the single integrals may fail to be defined on a measure $0$ set.

Source: Wikipedia

344 questions
2
votes
1 answer

Why are we allowed to replace the integral with respect to the product measure $\mu$ with iterated integrals?

I was reading this question here Fubini's Theorem double integral with sin and $e^{-x}$ but I do not know why are we allowed to replace the integral with respect to the product measure $\mu$ with iterated integrals? could anyone explain this for me…
Emptymind
  • 1,901
0
votes
0 answers

Clarification with regards to Fubini

In Wikipedia, https://en.wikipedia.org/wiki/Fubini%27s_theorem, it has been stated that: The advantage of the Fubini–Tonelli over Fubini's theorem is that the repeated integrals of $|f|$ may be easier to study than the double integral. As in…
Yair
  • 501
0
votes
1 answer

How does one check the integral condition of Fubini's?

How does one check the integral condition of Fubini's? I.e. that $$\int_{A \times B} |f(x,y)|d(x,y) < \infty$$ Isn't the use of Fubini's to avoid having to calculate this? I don't understand how to calculate such integral w/o iterated.
mavavilj
  • 7,270