Questions tagged [hermite-polynomials]

Hermite polynomials are a class of orthogonal polynomials that are defined as follows:

  • Probabilist's Hermite polynomials:

$$\text{He}_n(x)=(-1)^n e^{\frac{x^2}{2}}\frac{\mathrm{d}^n}{\mathrm{d}x^n} e^{-\frac{x^2}{2}}$$

  • Physicist's Hermite polynomials: $$\text{H}_n(x)=(-1)^{n}e^{x^{2}}\frac{\mathrm{d}^n}{\mathrm{d}x^n} e^{-x^{2}}$$

These polynomials are orthogonal with respect to the weight function

$$\int_{-\infty}^{\infty}\text{H}_m(x)H_n(x)\ e^{-x^2}\mathrm{d}x=\sqrt {\pi}\ 2^n n!\ \delta_{nm}$$

$$\int_{-\infty}^{\infty}\text{He}_m(x)\text{He}_n(x)\ e^{-\frac{x^2}{2}}\mathrm{d}x=\sqrt{2\pi}\ n!\ \delta_{nm}$$

263 questions
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Hermite polynomials from binomial theorem

Hello I want to obtain the explicit formula for the Hermite polynomial: $$ H_n(x)=\sum_{k=0}^{[n/2]}\frac{(-1)^k n!}{k! (n-2k)!} (2x)^{n-2k} $$ by expanding the exponential in the generating function $$ e^{2xz-z^2}=\sum_{n=0}^\infty…
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New Hermite polynomial identity?

I am trying to prove an identity involving Hermite polynomials using other identities from Wikipedia, but I can't find the way. I have checked the identity in Mathematica for many values of $n$ and it holds for all values of $n$ I have tried. The…
MBolin
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Asymptotic analysis of Hermite polynomials (Airy case)

Using the well known integral formula for the Hermite polynomials ( see Szego, Orthogonal Polynomials 1967 ): $H_n(x)=\frac{n!}{2\pi i} \int_{\mid w \mid =1} e^{2xw-w^2-(n+1)logw}dw $ I am trying to compute the main order asymptotics of $H_n(x)$, as…
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Hermite polynomial expression

I want to expand $e^{-a^2 x^2}$ to a series with the hermite polynomials $H_{2n}(x)$ but i can't find out how. I've already expanded $x^{2n}$,$x^{2n+1}$ and $e^{ax}$ to a series of$H_n(x)$ but i can't relate them. Any help?
user405715
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Expectation Hermite polynomials product $H_n(X) H_k(Y)$ when $X,Y$ are dependent Gaussians

If $X,Y\sim N(0,1)$ with $E XY=\rho$ covariance, what is the expectation of their product after applying probabilist's Hermite polynomials $E_{X,Y} H_n(X) H_k(Y)$? My initial guess is $\rho^{2k}\delta_{nk}$ where $\delta$ is dirac's delta. This…
kvphxga
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Hermite Polynomials for Integration

Use the Hermite interpolating polynomial of $f$ at distinct nodes $x_{0}, \ldots, x_{n}$ to approximate the integral $\int_{-1}^{1} f(x) d x$. It seems that the key idea to approach the problem would be the divided-difference method and applying…
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Can $\frac{d^k}{dx^k} e^{\frac{x^2}{2}}$ be written in terms of Hermite polynomials?

We know that $\frac{d^k}{dx^k} e^{-\frac{x^2}{2}}$ can be written in terms of Hermite polynomials as \begin{align} \frac{d^k}{x^k} e^{-\frac{x^2}{2}}= (-1)^k e^{-\frac{x^2}{2}} H_{e_k}(x) \end{align} It appears that in this case, we have to use…
Lisa
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Seem to be able to construct function on the whole real line from the value in a finite interval. What is wrong with the argument?

I have a question I am phrasing in terms of expansion of a function in terms of Hermite polynomials but it applies to other expansions as well. First I establish my convention for Hermite polynomials which is $$ (-1)^n \partial_z^n \varphi(z)=…
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Integral involving Hermite polynomials

Is there any way to calculate the following integral ? $\int_{-\infty}^{+\infty} H_n(x)H_m(x)e^{-\alpha x^2} d x$ with $\alpha > 0$ and $(H_n,H_m)_{w = e^{-x^2}} = 2^n n! \sqrt{\pi}\delta_{nm}$ (without using Gauss-Hermite quadrature)
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Asymptotic expansion of scaled Hermite polynomial

I have a scaled probabilist's Hermite polynomial: \begin{equation} H_n(ax)e^{-bx^2} \end{equation} where $a$ and $b$ are both complex numbers. What is the asymptotic limit of this expression as $n \to \infty$? Thank you in advance!
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Proving that the $2n$ Hermite polynomial is $H_{2n}(x)=(-1)^n\sum_{s=0}^{n}(-1)^{2s}(2x)^{2s}\cfrac{(2n)!}{(2s)!(n-s)!}$

I want to prove that the $2n$ Hermite polynomial is $H_{2n}(x)=(-1)^n\sum_{s=0}^{n}(-1)^{2s}(2x)^{2s}\cfrac{(2n)!}{(2s)!(n-s)!}$ So I resort to…
AlmaH
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Hermite Polynomial question

"If $f(x)$ is a polynomial of degree $m$, show that $f(x)$ may be written in the form $$f(x)=\Sigma_{r=0}^{m}c_rH_r(x),$$ where $$c_r=\frac{1}{2^rr!\sqrt {\pi} }\int_{-\infty}^{\infty}e^{-x^2}f(x)H_r(x)dx.$$ Deduce that…
J. Hunt
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