Questions tagged [hilbert-spaces]

For questions involving Hilbert spaces, that is, complete normed spaces whose norm comes from an inner product.

Let $H$ a vector space over the field $\mathbb C$, and $\langle \cdot,\cdot\rangle\colon H\times H\to \mathbb{C}$ a map which satisfies

  1. $\langle x,x\rangle =0\Longrightarrow x=0$ and $\langle x,x\rangle\geqslant 0$ for all $x\in H$,
  2. $(\forall x,y\in H):\langle x,y\rangle=\overline{\langle y,x\rangle}$,
  3. $(\forall x_1,x_2,y\in H)(\forall\alpha_1,\alpha_2\in\mathbb C):\langle \alpha_1 x_1+\alpha_2 x_2,y\rangle=\alpha_1\langle x_1,y\rangle+\alpha_2\langle x_2,y\rangle$.

The map $\lVert\cdot\rVert\colon H\to\mathbb R_+$, defined by $\lVert x\rVert =\langle x,x\rangle^{\frac 12}$ is a norm.

If $(H,\lVert \cdot\rVert)$ is complete, then $H$ is called a Hilbert space.

Example: The space $H$ of all sequences $x_0,x_1,x_2,\ldots$ of complex numbers such that $\sum_{n=0}^\infty|x_n|^2<\infty$, with the inner product $$\bigl\langle(x_0,x_1,x_2,\ldots),(y_0,y_1,y_2,\ldots)\bigr\rangle =\sum_{n=0}^{+\infty}x_n\overline{y_n}$$is a Hilbert space.

8254 questions
1
vote
1 answer

Every element of a Hilbert space is not orthogonal to at most countably many elements of an uncountable orthonormal system

Let $\{ e_r \}_{r>0}$ an uncountable orthonormal system in a Hilbert space $H$, prove that for every $v \in H$ $\langle v, e_r \rangle \neq 0$ for at most countably many $r>0$. If we assume $\{ e_r \}_{r>0}$ is complete then because we are in a…
1
vote
0 answers

Basis of $\mathcal{M}_d(\mathbb{C})$ composed of unitary operators

In this PDF https://www-m5.ma.tum.de/foswiki/pub/M5/Allgemeines/MichaelWolf/QChannelLecture.pdf on page 14, the author says right after equation (1.11) Note that by using a basis of Hilbert-Schmidt orthogonal unitaries $\{U_j\}_{j=1,...,d^2}$ we…
StarBucK
  • 689
1
vote
1 answer

Projection Operator Self-Adjointness

Is it right to say that projection operator is not self-adjoint(Hermitian) if it is not orthogonal projection operator?
feriob
  • 11
1
vote
0 answers

Confused about Bessel's inequality

I know that if $H$ is a Hilbert space and $(e_{j})_{j\in\mathbb{N}}$ is an orthonormal system in $H$ and $f\in H$. Then one has Bessel's inequality $$\sum_{j=1}^{\infty}|\langle f,e_{j}\rangle |^{2}\leq||f||^{2}<\infty.$$ If I want a similar…
Lech121
  • 333
  • 1
  • 8
1
vote
0 answers

Sobolev spaces of $L^2$-type on $\mathbb{R}$

DEFINITION: Let $s\in \mathbb{R}$. Then $$ H^{s}(ℝ)=\left\{f\in S'(\mathbb{R}):(1+|\xi|^2)^\frac{s}{2}, \hat{f} \in L^{2}(\mathbb{R}) \right\} $$ OBSERVATION: $f \in H^{s}(\mathbb{R})$ means that $\hat f$ is a measurable function. We introduce…
1
vote
3 answers

About the operator theory in Hilbert space

Let $H$ be a hilbert space. $L(H)$ be the set of linear operators on $H$. Suppose that $S,T\in L(H)$ and $S\geq0$, $\|Sx\|=\|Tx\|$ for every $x\in H$. Can I conclude that $S=\sqrt{T^*T}$?
user8484
  • 801
1
vote
1 answer

an equivalent condition for $B(H,K)$ to be a Hilbert space

How can I prove that $B(H,K)$ with operator norm is a Hilbert space if and only if $\dim H=1$ or $\dim K=1$, where $H$ and $K$ are Hilbert spaces? Any hint is appreciated.
Math 1988
  • 378
1
vote
1 answer

Is $\operatorname{tr}|A|=\operatorname{tr}|A^\dagger|$?

Is it true that $\operatorname{tr}|A|=\operatorname{tr}|A^\dagger|$ for any operator in a Hilbert space? I can prove this statement for normal operators such that $[A,A^\dagger]=0$. I want to know is there any proof or counter example for general…
mathvc_
  • 309
  • 1
  • 10
1
vote
1 answer

Disjoint isometric copy of countable-dimensional vector subspace of Hilbert space

Let $H$ be a complex separable Hilbert space. Let $A \subset H$ be a vector subspace of countable dimension. Does there exist unitary operator $U$, such that $A \cap U(A) = \{ 0 \} $ ?
1
vote
1 answer

Hilbert Space: infinite or finite? - All real inner product spaces are Hilbert spaces?

I am confused about Hilbert spaces. I want to understand them better. If I understand correctly a Hilbert space is an inner product space that has either finite or infinite dimension over real or complex numbers. The background to this question is…
tom
  • 139
1
vote
1 answer

Strict inequality in a Hilbert Space

Let $H$ be a Hilbert Space and let $x$ and $y$ be two distinct points in $H$ such that $||x|| = ||y|| = 1$. Then show that $||tx+(1-t)y||<1$, where $0
JackT
  • 581
1
vote
0 answers

Hilbert basis of $L^2([-1,1])$?

Could you please specify hilbert basis of $L^2([-1,1])$? How will be the representation of a function f $\in L^2([-1,1])$ by means of its Fourier series? My solution: $E_k=1/\sqrt2 e^{kit\pi}, k\in Z$ $f=\sum_{k \in Z} c_kE_k$ $c_k=
1
vote
1 answer

Closed subset of a Hilbert space

$Y_0\subset Y $ is a closed Hilbert subspace of $Y$ with finite codimension and a subspace $ Y_1 $ satisfies $ Y_0 \subset Y_1 \subset Y $. Is $ Y_1 $ also closed?
Tatjana
  • 13
1
vote
0 answers

Significance of finite dimensional vector space or Hilbert space

What has any operator got to do with dimensionality of the Hilbert space in which it is represented? Does a finite dimensional Hilbert space make sure that we have independent eigenvectors for the eigenvalues? If the Hilbert space is not finite,…
Cool_5275
  • 133
1
vote
1 answer

Inner product's property in a Hilbert space on $\mathbb{C}$

Recently, I have just learnt about the concept of a Hilbert space. As far as I can understand, a Hilbert space is a generalized Euclidean space. When talking about an Euclidean space $E$, indeed there must be a mapping from $E \times E$ to the…
ElementX
  • 922