Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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Quick true and false question check

a) False. Counter example $\frac{1}{x}$ b) False. Has to be positive by comparison theorem definition (Cant think of a counter example) c) True by definite integral properties. d) True by comparison theorem definition
user349557
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Rewriting an improper integral confusion

I was struggling with the following integral: $$\displaystyle I=\int\limits_{0}^{+\infty}\dfrac{\arctan \pi x-\arctan x}{x}dx$$ And I found a question about it on this site where the answer said that we can rewrite the above integral as…
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Integral where limit of bounds both goes to infinity

does the following expression goes to zero? $$\lim_{x \rightarrow + \infty} \int_{x}^{+\infty} F(x)dx$$ My thinking process is that since the bounds of the integral are converging to the same "value", it should collapse. Is this correct? Thank you!
cosmia1
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Improper integral or should i solve it?

The problem is: But as u can see, answers dont ask me to solve it, so i sure that, there`re another way to get the answer
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Need help with an exercise (Improper integral).

The exercise: if $ f(x)$ is continuous in $[a,\infty]$ and $\lim_{x\to\infty} \int_{x}^{2x} f(t)dt = 0$ then $\int_{a}^\infty f(t)dt$ converges. I belive the statement is true and can be proven using Cauchy's test for integral convergence. Thanks.
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$\lim_{\sigma \to +\infty} \int f(x + \varepsilon) \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{\varepsilon^2}{2\sigma^2}}\mathrm{d}\varepsilon$ is a line.

I would like to show that given a function $f:\mathbb{R}\to \mathbb{R}$ such that is continuos, $|f(x)| < M$ and $\exists z \in \mathbb{R} $ such that $$-\infty < \lim_{\sigma \to +\infty} \int_{-\infty}^{+\infty} f(z + \varepsilon)…
Sam
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The Limit Comparison Test for Improper Integrals

The test says that if $0\le f(x)\le g(x)$ and if $L=\lim_{x\to \infty}\frac{f(x)}{g(x)}$ When $0
newhere
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Proving that $\int_{1}^{\infty} \frac{\sin^{2}(3x)}{x} dx$ diverges

I have to prove that $$\int_{1}^{\infty} \frac{\sin^{2}(3x)}{x}\,dx$$ diverges. Can anyone give a hand? I'm totally stuck.
Chen Mor
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Convergence of an integral involving tan function

How would i prove that integral $$\int_0^{1}{\frac{\tan^2(x)}{\sqrt{x^5}}}$$ converges? By using some plotting apps, I managed to find that $\tan^2(x) \le 3x^2$ for $x \in (0, 1)$ (which would complete the proof easily) but I have no clue how to…
windircurse
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Quick question about improper integral

What do I do if in the point of lower bound of some first-odered improper intagral integrand doesn't exists? For instance, $$\int _1^{\infty }\frac{dx}{x\log ^2x} $$
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Study the convergence of this improper integral

$$ \int_o^\infty t^ae^{bt}dt $$ for a,b reals. I guess I would have to separate this integral in many cases for different values of a and b. I know that if b < 0, $$ \int_o^\infty t^ae^{bt}dt > \int_o^\infty {t^a}dt $$, which diverges for any a.…
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Finding an integral for an expression

I have the equation below. If I work backwards and integrate the second line w.r.t. t and then evaluate at t = x, I can get the first line. However, how do I go from the first expression to the second? I don't think it's differentiating w.r.t. t,…
Rayne
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Improper integral of $\frac{1}{x} \sin \frac{1}{x}$

Let $f(x)= \frac{1}{x} \sin \frac{1}{x}$ when $x \in (0, 1]$and $f(0)=0$. Prove that $\int_{0}^1 f(x)dx$ exists. Can someone give me a hint to solution?
mrnobody
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Improper integration limits

Suppose I have a function $f(x)$ such that $\int\limits_{-\infty}^{\infty}f(x) dx = c$. Also, $f$ is even. Is the following equation correct? $$\int\limits_{a}^{b}f(x)dx = \int\limits_{a}^{\infty}f(x)dx -\int\limits_{b}^{\infty}f(x)dx$$
Joshhh
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Calculating improper integral limits

I am trying to calculate $\int_{-\infty }^1 {dx\over x^{1/3}}$. I have come up with $\int_{-\infty }^1 {dx\over x^(1/3)}$=$\int_{-\infty }^0 {dx\over x^{1/3}}$+$\int_{0}^1 {dx\over x^{1/3}}$. Then I am trying to calculate $\int_{-\infty }^0 {dx\over…
Wanderer
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