Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

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Prove $\sin(1/n)<1/n$ for all $n$

I need to prove $\sin(1/n)<1/n$ for all $n \in \Bbb N$ using mathematical induction. Dont know how to start. Please help!
mopdf
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Proof by induction, 1 · 1! + 2 · 2! + ... + n · n! = (n + 1)! − 1

So I'm supposed to prove that $$1 · 1! + 2 · 2! + \dots + n · n! = (n + 1)! − 1$$ using induction. What I've done Basic Step: Let $n=1$, $$1\cdot1! = 1\cdot1 = 1 = (n+1)!-1 = 2!-1 = 2-1 = 1$$ Induction Step: Assume $f(k) = 1\cdot1! + 2\cdot2! +…
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Explaining why a function is well-defined

How can I explain that a function is well-defined, if it's defined recursively by specifying $f(1)$, and a rule for finding $f(n)$ from $f(n-1)$? My reasoning: If the function for $f(n)$ can be derived from $f(n-1)$, then the function must give a…
Matt
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Induction without a base case

I am looking for an example where you have $P(n)$ implying $P(n+1)$. However there is no base case. For which there is therefore no solution at all for the induction problem even though the inductive step itself works.
Prankster
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Induction for statements with more than one variable.

I'm going through the first chapters of Tao's Analysis text and I'm not entirely sure about one thing, namely why we're allowed to 'fix' variables when inductively proving statements pertaining to more than one variable. This is not explained in the…
Spine Feast
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Prove 7 divides $15^n+6$ with mathematical induction

Prove that for all natural numbers statement n, statement is dividable by 7 $$15^n+6$$ Base. We prove the statement for $n = 1$ 15 + 6 = 21 it is true Inductive step. Induction Hypothesis. We assume the result holds for $k$. That is, we assume…
Templar
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Prove that $4^{2n} + 10n -1$ is a multiple of 25

Prove that if $n$ is a positive integer then $4^{2n} + 10n - 1$ is a multiple of $25$ I see that proof by induction would be the logical thing here so I start with trying $n=1$ and it is fine. Then assume statement is true and substitute $n$ by…
DewinDell
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Prove by Induction: $8^n - 3^n$ is divisible by $5$ for all $n \geq 1$

Prove by Induction that for all $n \geq 1$ we have $$8^n - 3^n \text{is divisible by 5} ...(*)$$ My proof so far Step 1: For $n=1$ we have $8^1 - 3^1 = 8 - 3 = 5$ which is divisible by 5. Step 2: Suppose (*) is true for some $n=k\geq 1$ that is…
lucidgold
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Induction on finite subset of natural numbers

Can we use induction to prove that a statement $P(n)$ is true for all $n \in \mathbb{N} $ such that $n \leq s$, where $s \in \mathbb{N}$? Specifically, in the second induction step, is it enough to show that $$P(n) \implies P(n+1),$$ by assuming…
Valentina
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$3^n+4^n<5^n$ for all $n>2$

I'm doing the following induction proof and wanted to know if this was valid. I think it is, but I'm seeing more complicated solutions than what I did. What I did seems much easier. Prove that $3^n+4^n<5^n$ for all $n>2$. When $n=3$ we get $91<125$.…
ddswsd
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Is "Strong Induction" not actually stronger than normal induction?

I'm proving something via induction (which has turned into strong induction) and there's something I've never really fully understood about strong induction. The name "strong induction" does make it sound like a more 'powerful' version of induction…
Noble.
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Strong Induction: Example Using All of P(1) and … and P(k - 1) and P(k) to Prove P(k + 1)

I'm trying to understand how to do "real" strong induction, but my textbook seems to be of no help. It defines strong induction as follows: Let $P(n)$ be a property that is defined for integers $n$, and let $a$ and $b$ be fixed integers with $a\leq…
Mirrana
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An Induction Problem, What Am I Supposed To Prove?

I have encountered an induction problem which I don't understand. What I don't understand is what it is asking me to prove. I don't want a solution. The problem is: If $u_1=5$ and $u_{n+1}=2u_n-3(-1)^n$, then $u_n=3(2^n)+(-1)^n$ for all positive…
user590211
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In the induction proof for $(1+p)^n \geq 1 + np$, a term is dropped and I don't understand why.

In What is Mathematics, pg. 15, a proof of $(1+p)^n \geq 1 + np$, for $p>-1$ and positive integer $n$ goes as follows: Substitute $r$ for $n$, then multiply both sides by $1+p$, obtaining: $(1+p)^{r+1}\geq 1+rp+p+rp^2$ "Dropping the positive term…
Chris Gregg
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Is principle of mathematical induction an example of inductive or deductive reasoning?

Is principle of mathematical induction an example of inductive or deductive reasoning? According to wikipedia it says it is deductive as it is just a mathematical proof but according to the definition of inductive reasoning it should be inductive…
Matt
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