Questions tagged [induction]

For questions about mathematical induction, a method of mathematical proof. Mathematical induction generally proceeds by proving a statement for some integer, called the base case, and then proving that if it holds for one integer then it holds for the next integer. This tag is primarily meant for questions about induction over natural numbers but is also appropriate for other kinds of induction such as transfinite, structural, double, backwards, etc.

Mathematical induction is a form of deductive reasoning. Its most common use is induction over well-ordered sets, such as natural numbers or ordinals. While induction can be expanded to class relations which are well-founded, this tag is aimed mostly at questions about induction over natural numbers.

In general use, induction means inference from the particular to the general. This is used in terms such as inductive reasoning, which involves making an inference about the unknown based on some known sample. Mathematical induction is not true induction in this sense, but is rather a form of proof.

Induction over the natural numbers generally proceeds with a base case and an inductive step:

  • First prove the statement for the base case, which is usually $n=0$ or $n=1$.
  • Next, assume that the statement is true for an input $n$, and prove that it is true for the input $n+1$.

The following variant goes without a base case: Assuming the statement is true for all $n\in\mathbb N$ with $n < N$, prove that is true for $N$, too. This has to be done for all $N\in\mathbb N$.

10150 questions
0
votes
3 answers

Question regarding an induction proof

I am stuck on a question regarding induction. I know that we are supposed to solve it using 3 steps: the base step, the n= p step and n = p+1. The question is prove that $$\displaystyle\sum_{i=1}^n\dfrac{i}{2^i}= 2- \dfrac{n+2}{2^n}$$ For $n = 1$…
addde
  • 449
0
votes
2 answers

how to prove $2^n = {n \choose 0} +{n \choose 1} + \cdots {n \choose n}$

I have studying my maths book induction chapter and I found things to solve this but I am failed, somebody help me to solve this problem by simple method of mathematical induction. $$2^n = {n \choose 0} +{n \choose 1} + \cdots {n \choose n}$$ How…
0
votes
3 answers

using mathematical induction problem with n variable as exponent

I am a first year Math student and I am looking at problem in my text book which does not have any answers and I have completely no idea how to do this paticular problem. Show, using mathematical induction, that for all natural numbers n ≥ 3, $$…
0
votes
3 answers

How to prove $2^n < n!$ using Mathematical Induction?

Possible Duplicate: Proof the inequality $n! \geq 2^n$ by induction I have the following: Prove that for all $n \in Z^+,\space n > 3 \implies 2^n < n!$ Please provide the steps and, if possible, an explanation. Best,
0
votes
3 answers

Find a formula for $ 1\times3^0 + 3\times3^1 + 5\times3^2 + ... +(2n+1)\times3^n$.

The original exercise is to find a formula for this and prove it via induction. However, I am having a problem deriving such a formula. How do you normally approach this types of problems, is it a matter of experience, guessing or something else?…
alexgiorev
  • 1,262
0
votes
1 answer

How to go about induction that deals with inequalitites

The only thing i've been able to do is to prove it for 1. How do i go about prvoing it for k+1?
Ali Naqvi
  • 177
0
votes
1 answer

How to perform induction step in this question?

Q:Prove By induction $2^{n+1} > n^2$ for all positive integers. Step 1: Base case: $n=1$, we get $4>2$ Step 2: Induction hypothesis: $n=k, 2^{k+1} > k^2$ Step 3: Induction Step: to prove: $2^{(k+1)+1} > (k+1)^2$ Left hand side=$2^{k+1}.2$ How to…
ema
  • 25
0
votes
1 answer

Prove by induction $n^{1/n} ≤ \frac{n+1}{2}$

The problem Prove by induction: $n^{1/n} ≤ \frac{n+1}{2}$ Attempt at solution I started off with the usual steps for an MI problem. We start with the $P_1$ case: for $P_1$, LHS = 1 and RHS = 1 $\implies$ $P_1$ is true. Assume that $P_k$ is true for…
0
votes
2 answers

Union-closed families of sets (A problem about induction)

$A$ and $B$ are two sets If $A,B \in F,$ then $A \cup B \in F$. Prove by induction that this property applies to a countable number of sets. If $A_i \in F,i \in \mathbb{N}$, then $ \bigcup_{i\in\mathbb{N}}^{}A_i \in F$. I understand it, but I don't…
dudha
  • 77
0
votes
1 answer

How to prove this proposition with induction

Let $P(x)$ be a polynomial of degree $n$ in the field $\mathbb{R}$ such that $a_n,\ldots,a_0$ are the coefficients. How can I show through induction that if there is at least one coefficient $a_i$ that is not $0$ then there are at most $n $…
0
votes
5 answers

How to Prove with Mathematical Induction $3^n > n^2$

How do I prove that $3^n > n^2$ with mathematical induction? I thought I had the correct answer but my teacher says its wrong. I let $n=1$ for the initial case and it works. I then assumed $n=k$ works and went onto the $n=k+1$ case, but after that…
gerard
  • 1
0
votes
1 answer

basic mathematical induction problem

Prove that for some $b \in \mathbb{N}$, $(\sqrt{2})^n > n$ for every $n \geq b$ Find such a $b \in \mathbb{N}$. Prove that $\forall$$n \geq b$, $(\sqrt{2})^n > n$ How would I approach these problems and problems similar to these?
user123
  • 83
0
votes
1 answer

Show that $\sum_{r=1}^nu_r=u_{n+1}-(n+2)$ given $u_1=2\,,u_{k+1}=2u_k+1\,,u_n=3\times2^{n-1}-1$

The sequence $u_1$, $u_2$, $u_3$,... is defined by $$u_1=2\,,\,\,\,\,\,\,\,\,\,u_{k+1}=2u_k+1$$ $$u_n=3\times2^{n-1}-1$$ Show that $$\sum_{r=1}^nu_r=u_{n+1}-(n+2)$$ Prove that it is true for $n=1$ thus prove that…
0
votes
1 answer

Is this a valid strong induction proof? (2 base cases)

I am a university student and I was self-teaching myself induction methods. I did question (3)(b). The answer to (3)(a) is g n = 2^n + 1 for n is a positive natural number. My solution differs from the given solution by the university. Mine has 2…
0
votes
1 answer

How to use Induction properly?

I would like to prove the following equation using induction. However that seems somehow impossible at least for me: $\sum\limits_{k=1}^{2n} {(-1)^k \cdot k^2}=(2n+1)\cdot n$ I tried to show that some property $E()$ holds for $n=1$, $E(1)$ but I…
Mamba
  • 803
1 2 3
99
100