Questions tagged [lambert-w]

For questions related to the Lambert W or product log function, the inverse of $f(z)=ze^z$.

Equations involving exponentials multiplied to linear terms, such as $x+2=e^x$, cannot be solved using elementary functions in general. However, they may be solved in closed form using the Lambert W function, the inverse of $f(z)=ze^z$. In the given example: $$x+2=e^x$$ $$(-x-2)e^{-x-2}=-e^{-2}$$ $$-x-2=W(-e^{-2})$$ $$x=-W(-e^{-2})-2$$ There are two real branches of the Lambert W: $$W_0(z)\text{ for }z\in[-1/e,\infty)$$ $$W_{-1}(z)\text{ for }z\in[-1/e,0)$$

There are also branches $W_n(z)$, with $n\in\mathbb{Z}$, which are defined only on the complex plane, but which still respect the property of solving $W_n(z)e^{W_n(z)}=z$.

The regions of the complex plane where the inverse relationship occurs are bounded by the curve $x=-y\cot(y)$.

As discussed in the Corless et al. reference, the use of $W$ follows early Maple usage. Exact solutions to some mathematical models in the natural sciences, such as Michaelis–Menten kinetics, use this function.

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Solving an equation using Lambert function

Could anyone help me solve this equation in terms of $x$ using the Lambert $W$ function or even other methods: $$x^{-a}e^{ - kx} =c(n-x)^{-a}e^{ - k(n-x)}$$ Where $k$, $c$, and $n$ are constants, and $a$ is the path loss exponent of the system with…
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Approximations and limits for Lambert $W$ of decreasing functions

I'm aware of the following approximation that approaches the Lambert W Function: $$ W(f(x))\approx\ln\left(f(x)\right)-\ln\left(\ln(f(x))\right) $$ However, this approximation fails to capture the Lambert $W$ function if $f(x)$ is a decreasing…
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Positive solution for $e^x-x=c$

In my problem I get the equation (1): $e^{x}-x=c$ with $c > 1$. With my knowledge the analytical solution will be (2): $x = -W(-e^{-c})-c$. With $c = 5.5555$, and this is my problem I only find the approximate solution: $x = -5.55112$ Though, I know…
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Method to solve slightly modified lambert function

As an engineer, my math knowledge is not rigour and I'm trying to solve the equation: $$ e^{-w}(w+1)=z $$ I know that it depends on the lambert function. But, I don't know how to get the equation above to the form in wikipedia. I chucked into…
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How is $W_{-1}(-\frac{2}{3}\cdot e^{-\frac{2}{3}}) = -1.429$ if $W(x)$ is inverse of $f(x)=x\cdot e^x;x<-1$?

$$ f(x)=x\cdot e^x \space ;\space x<-1 \\ W_{-1}(x)=f^{-1}(x) \\ W_{-1}(x\cdot e^x)=f^{-1}(x\cdot e^x)=x $$ But $W_{-1}(-\frac{2}{3}\cdot e^{-\frac{2}{3}}) = -1.429$ not $-0.66 \dot 6$? It may be a stupid question, sorry about that.But please help…
UWU gg
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Solving equation in a form x(alnx + b) = c for x using Lambert W function

I don't know how to solve an equation in a form of x(alnx + b) = c for x using Lambert W function. a, b and c stand for constants. I tried using Wolfram Alpha, but it does not provide step by step solution. Any comments will be welcomed. Kind…
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Find $W_1$ branch of Lambert $W$-function

The given equation: $$\frac{8} {\ln(2)} \cdot \ln(x) = x.$$ Some algebra, and then we get the solutions: $$x = e^{W_0(-\frac{\ln(2)} {8})}\approx 1.1 ,\;\; x = e^{W_{-1}(-\frac{\ln(2)} {8})} \approx 43.5593.$$ I found $W_{0}$ with Taylor…
NateD
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Are the branches of the Lambert W function disjoint?

On the Wikipedia side on the Lambert W function it says "The functions $W_k(z), k ∈ \mathbb{Z}$ are all injective and their ranges are disjoint." Is there any other source to find that information about the disjointness of the branches? Ich would…
putti.123
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Solving Equation: $-x^{-2}-(1-y)^x\ln(1-y)=0$ for $0 1$

For the equation $-x^{-2}-(1-y)^x\ln(1-y)=0$ for $0 1$, I'm trying to solve for $y$ in terms of $x$, but not sure if I'm doing it right. Let $1-y=a$, we get  $-x^{-2}-a^x\ln(a)=0$  =>  $x^{-2}=-a^x\ln(a)$ Let $a=e^{xt}$, we get…
Welan
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Practice Questions Lambert W function/Product Log

I am not too sure if I should be posting this, if it's not appropriate, I'll delete it as soon as I can. I have learnt about the Lambert W function recently (also called product log) and I was looking for some practice questions online. With most…
Poobean
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Solving $x + r\ln(x) = c$ using Lambert's W function?

A very elementary question, I am sure. I would like to solve $x + r \ln(x) = c$ where $c>1$ and $r<1$. (There is a unique solution for $c>1,$ and the LHS is convex, btw.) By "solve", I mean not numerically, but expressing the solution in terms of…
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A Lambert W-function with no real solution?

Recently I have created this question: $$(x+1)^xe^{x+1}=(2x)^x$$ And the solution $$(x+1)^xe^{x+1}=(2x)^x$$$$(x+1)e^{1+\frac 1 x}=2x$$$$(1+\frac 1 x)e^{1+\frac 1 x}=2$$$$1+\frac 1 x=W(2)$$ $$x=\frac 1 {W(2)-1}$$ But Desmos shows no solution, can…
xxxx036
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How to solve for $x$ : $ae^{bx}+x = c$

How to solve for $x$ : $ae^{bx}+x = c$ I've tried to solve it with the Lambert W function, but, in all of the methods I tried, I had $x$ as the Lambert W function parameter. Can I solve it without graphs? Thank you for your help.
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Lambert W function largest solution

I'm trying to understand a demonstration on a paper and since my math knowledge is limited i can't understand how do i deduce the value of $\,\gamma$ given a value for $k$ and $n$. The equation is the following: $\gamma =…
dinoroba
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Solve $e^{-x} + \frac{x}{5} = 1$

I know there are similar questions, but I want to discuss something I am missing to capture. The obvious solution to this is $x = 0$ and the other one is given by $x = 5 + W(-5/e^5)$, where $W(x)$ is the W-Lambert function. But this second solution…