Questions tagged [laplacian]

The properties of the Laplace differential operator, denoted $\Delta$ or $\nabla^2$, and defined as the divergence of the gradient. For Laplace equation, see (harmonic-functions)

Laplacian Operator is a derivative operator which is used to find edges in an image.

Mathematically, the Laplacian operator is defined as: $$\nabla^2 \equiv \frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2}$$

  • The Laplacian is a scalar operator. If it is applied to a scalar field, it generates a scalar field.

  • If the scalar Laplacian operator is applied to a vector field, it acts on each component in turn and generates a vector field.

Note that the operator $~\nabla ^2~$ is commonly written as $~\Delta~$ by mathematicians.

Differences with other operators:

The major difference between Laplacian and other operators like Prewitt, Sobel, Robinson and Kirsch is that these all are first order derivative masks but Laplacian is a second order derivative mask. Another difference between Laplacian and other operators is that unlike other operators Laplacian didn’t take out edges in any particular direction but it take out edges in following classification.

$1.\quad$ Inward Edges $\qquad$ $2.\quad$ Outward Edges

Applications:

The Laplacian is extremely important in mechanics, electromagnetics, wave theory, and quantum mechanics, and appears in

$1.\quad$ Laplace's equation $$\nabla^2 \phi=0$$

$2.\quad$ The Helmholtz differential equation$$\nabla^2 \phi+k^2 \phi=0$$

$3.\quad $ The wave equation$$\nabla^2 \phi=\frac{1}{c^2}\frac{\partial^2 \phi}{\partial t^2}$$

$4.\quad$ The Schrödinger equation$$i \hbar \frac{\partial }{\partial t}\psi(x,y,z,t)=\left[-\frac{\hbar^2}{2m}\nabla^2+V(x)\right]\psi(x,y,z,t)$$

Laplacian, Various Coordinates :

$1.\quad$ In rectangular coordinates $~(x,y,z)~$: $$\nabla^2\equiv \nabla \cdot \nabla \equiv \frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2}$$

$2.\quad$ In cylindrical polar coordinates $~(r,\theta,z)~$:$$\nabla^2\equiv \frac{\partial^2}{\partial r^2}+\frac{1}{r}\frac{\partial}{\partial r}+\frac{1}{r^2}\frac{\partial^2}{\partial \theta^2}+\frac{\partial^2}{\partial z^2}$$

$3.\quad$ In spherical polar coordinates $~(r,\theta,\phi)~$:$$\nabla^2\equiv \frac{\partial^2}{\partial r^2}+\frac{2}{r}\frac{\partial}{\partial r}+\frac{1}{r^2}\frac{\partial^2}{\partial \theta^2}+\frac{\cos \theta}{r^2\sin \theta}\frac{\partial}{\partial \theta}+\frac{1}{r^2\sin^2\theta}\frac{\partial^2}{\partial \phi^2}$$

Note: This tag is also for questions concerning the properties, such as self-adjointness, compactness of inverse, and spectral structure of the Laplace differential operator. The operator, denoted $\Delta$ or $\nabla^2$, is defined as the divergence of the gradient, and generalized to the Laplace-Beltrami and Laplace-deRham operators.

References:

https://en.wikipedia.org/wiki/Laplace_operator

http://mathworld.wolfram.com/Laplacian.html

https://nptel.ac.in/courses/115101005/downloads/lectures-doc/Lecture-5.pdf

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laplacian of $\ln$ in 2-D

Simple question: Why the below formula is right?(I want to know the proof) The equivalent in 2D geometry is $$ \nabla^2 \ln \mid\vec\theta-\vec\theta'\mid = 2\pi\delta^2(\vec\theta-\vec\theta')\ ,$$ where $\delta^2$ is the 2D delta…
BAO
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Weak solution in Laplace operator is classical solution?

Let $\Delta:D(\Delta)\subset L^2\to L^2$ where $D(\Delta)=\left\{u\in L^2:\Delta u\in L^2\right\}$. Let $f\in L^2$. Let $u\in L^2$ a weak solution of $\Delta u=f$, then $$(u,\Delta^*v)=(f,v),\quad \forall v\in D(\Delta^*)$$ Because…
eraldcoil
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Electrostatic Potential and Compactly Supported Functions

I found the following expression in IMRN International Mathematics Research Notices 2005, No. 34, page# 2064. Let $\phi$ be a $C_c^{\infty}(\mathbb{C})$ then $$\int_{\mathbb{C}}\frac{1}{2\pi}\log|z|\Delta\phi(z)dxdy = \phi(0).$$ Here $\Delta \phi$…
Tapan
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Is $u''$ always synonymous to $\Delta u$?

Is $u''$ always synonymous to $\Delta u$? Or if not, then what does $u''$ refer to? This is in contexts of giving PDE problems e.g. as: $$\Delta u = 0$$ Sometimes I see $$u'' = 0$$ Can I assume in this case that $$\Delta u = u''$$
mavavilj
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Laplace's equation, separation of variables

Ok so I have a question with tutorial solutions but there are a few points I don't understand. Q: Find the solution to Laplace's equation $$(∇^2)u=0$$ in the unit square $d=\{(x,y):0≤x≤1,0≤y≤1\}$ subject to the boundary conditions…
SFL
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Harmonic functions question

Consider a function which is harmonic in V (ie $\nabla^2 \Phi({\bf x}) = 0$ in V). If $\Phi({\bf x})$ is known on an arbitrary closed surface within V is the potential on the surface of V uniquely determined?
D_J_S
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Laplace operator in half sphere space

The laplace operator is defined for the sphere as : \begin{equation} \frac{\partial^2 f}{\partial r^2} +\frac{2}{r} \frac{\partial f}{\partial r} +\frac{1}{r^2\sin\theta} \frac{\partial }{\partial \theta}\left( \sin\theta\frac{\partial…
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Name for a two vector laplacian-like operator?

In the arXive paper Control Functionals for Monte Carlo Integration, $\S$ 2.3.1 presents theorem $1$ on p. 7: Assume $\phi\in\mathcal{H}^{d}$ and $(A1,3)$. Then $\psi$ belongs to $\mathcal{H}_{0}$, the reproducing kernel Hilbert space with kernel…
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Apparent Contradictory Algebra in the Derivation of the Laplacian in Spherical Coordinates

For any transformation from Rectangular (Cartesian) to spherical coordinates in three dimensions, we use the transformation equation $x = r\cos(\theta)\sin(\phi)$ among others, where $\theta$ is the azimuth and $\phi$ is the polar…
kapple
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Simple Laplacian operator on the sphere $\mathbb{S}^2$

Let \begin{cases} x=\sin \theta \cos \varphi \\ y= \sin \theta \sin \varphi \\ z= \cos \theta \end{cases} Then we obtain $$g_{\mathbb{S}^2} = \begin{pmatrix} 1& 0 \\ 0 & \sin^2 \theta \end{pmatrix}$$ Hence, $$\det…
user350845
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Laplace operator

The question is that Derive a formula for $\Delta(\frac{f}{g})$ in terms of $f, g, \nabla f, \nabla g, \Delta f, \Delta g$. Naturally, I apply the rules of gradient and divergence, and yield $$\Delta(\frac{f}{g}) = \frac{\Delta f}{g} + 2 \nabla f…
MonkeyKing
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