Questions tagged [lebesgue-measure]

For questions about the Lebesgue measure, a measure defined on the Borel or Lebesgue subsets of the real line or $\mathbb R^d$ for some integer $d$. Use it with (tag: measure-theory) tag and (if necessary) with (tag:lebesgue-integral).

Lebesgue measure is the classical notion of length and area to more complicated sets, and its assigns a measure to subsets of $n$-dimensional Euclidean space. Some examples of Lebesgue any closed interval, any cartesian product of intervals, any Borel set, and any countable set of real numbers (which has Lebesgue measure zero).

7551 questions
0
votes
1 answer

If disjoint $S$ and $T$ are „locally“ either both null sets or not, can they have positive measure?

Let $S,T\subseteq \mathbb R^n$ be disjoint such that for every compact $K\subseteq \mathbb R^n$ we have that $K\cap S$ is a null set if and only if $K\cap T$ is a null set. Can both have positive Lebesgue measure? Intuitively, if one of them had…
0
votes
0 answers

What's the reason for the pre-image def. of Lebesgue measurable?

What's the reason for the pre-image def. of Lebesgue measurable? I.e. $f$ Lebesgue measurable if $\{ x : f(x) > c \in \mathbb{R}\}$ is measurable. Like why is it significant that $f(x) > c$?
mavavilj
  • 7,270
0
votes
0 answers

How do I prove that counting measure is subadditive?

How do I prove that counting measure is subadditive? Particularly, I'm confused about, what cases do I need to explore? $$\mu^* \bigg(\bigcup_{i=1}^{\infty} E_i \bigg)$$ then since each $E_i$ is either some finite natural number or $\infty$, then do…
mavavilj
  • 7,270
0
votes
1 answer

If $A$ is lebesgue measurable, $B \subset A$ and $A-B$ is lebesgue measurable then B is measurable.

I am trying to prove this statement that seems very easy but i am struggling with it. If $B-A$ is measurable then $B^c\cup A$ is also measurable but that does not help really. I am pretty sure the end goal is to manipulate this to get $A$ by itself…
Sorfosh
  • 3,266
0
votes
0 answers

Can one construct a set $E$, $m^*(rE)\neq rm^*(E)$

Can one construct a set $E$, $m^*(rE)\neq rm^*(E)$. Well , we know that if $E$ is measurable then $$m^*(rE)= rm^*(E)$$,so what is the case of a none-measurable set ? Well,I think it holds for any set $E$, we assume that $$m^*(E)=\sum_n |I_n|$$ Where…
0
votes
1 answer

Collection of all $T\subseteq\mathbb{R}$ such that $λ^{*}(T) =λ^{∗}(T∩A)$ for all $A\subseteq\mathbb{R}$.

Hi I am doing a past paper and I am stuck on the following question. Let $\theta$ be the collection of all $T\subseteq\mathbb{R}$ such that $λ^{*}(T) =λ^{∗}(T∩A)$ for all $A\subseteq\mathbb{R}$ , show that $\theta$ can be written as $\theta$ =…
RJSS
  • 9
0
votes
1 answer

In Lebesgue measure, why do we do outer approximations by open sets instead of closed sets?

So from Caratheodory's condition we can show that a set is measurable if it can be enclosed in an open set whose measure is equal / arbitrarily greater than the original set. What is the reason that we are only considering outer approximations by…
user49404
  • 471
0
votes
1 answer

Find Lebesgue Null Set A so that A-A is a Neighbourhood of zero

I try to solve the following question: Show that there is a Lebesgue null set A so that A-A is a neighbourhood of zero; where $A-A :=\{x-y|x,y\in A\}$. I really don't no how to do this. Thanks to everyone who can help.
user608381
0
votes
1 answer

Lebesgue Measure of Cantor Set

For a presentation, I am learning about the Cantor Set and how it is homeomorphic to the p-adic numbers. I was reading section two of this paper. In it it states that the Cantor Set has a vanishing Lebesgue measure. Wikipedia says: Given a subset…
bkarthik
  • 430
0
votes
1 answer

Show that λ defined as λ(E)=μ(A∩E) is a measure on Ω for E in Ω

Let μ be a measure in Ω and A be afixed set in Ω .Then show that λ defined as λ(E)=μ(A∩E) is a measure on Ω for E in Ω. How to prove this?
Shammu
  • 1
0
votes
1 answer

Showing a function is lebesgue measurable

I am given that $(\Omega, \Sigma, \mu)$ is a measure space. Also I am given that $f$ is a nonnegattive $\Sigma$-measurable function on $\Omega$. Now let a function $g:\mathbb{R} \rightarrow[0,\infty]$ and $g(t)=\mu(\{f>t\})$ if $t\geq0$ and $g(t)=0$…
LanaDR
  • 503
0
votes
1 answer

Extension of Holder's Inequality

I found the proof of Generalization of Hölder's inequality from Wikipedia I get the other part, but I don't get why in case 1: we have the inequality $\Vert f_1f_2\cdots f_n \Vert_r \leq \Vert f_1f_2 \cdots f_{n-1} \Vert_r \Vert f_n \Vert_\infty…
Andy
  • 1,109
0
votes
1 answer

Cardinality of the continuum and Lebesgue measure of zero

How to construct a set with cardinality of continuum and a Lebesgue measure of zero? For instance, a set of all rational numbers within (0,1) is a countable set with Lebesgue measure of zero. What about continuum?
Stepan
  • 1,093
0
votes
2 answers

Finite Sets in the sense of Lebesgue Measure

Show that the sets $S(x)=\{(m,n):m\in\mathbb{Z},n\in\mathbb{N}^+,|x-\frac{m}{n}|\leq\frac{1}{n^3}\}$ where $x\in\mathbb{R}$ are finite for almost all $x\in\mathbb{R}$ in the sense of Lebesgue measure.
mathman
  • 117