Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

43700 questions
4
votes
2 answers

How find this $\lim_{x\to 0}\frac{(1+x)^{\frac{1}{x}}-(1+2x)^{\frac{1}{2x}}}{x}$

Evaluate $$I=\lim_{x\to 0}\dfrac{(1+x)^{\frac{1}{x}}-(1+2x)^{\frac{1}{2x}}}{x}$$ My try: Use L'Hôpital's rule. We have…
math110
  • 93,304
4
votes
2 answers

Limit of Sequence n/(n+1)

One of my homework problems asks, "Are the terms of the sequence n/(n+1) also getting closer and closer to π?" I'm confused because I thought that the limit was 1... Please help!
4
votes
3 answers

Help with limit calculation

Can anyone help me with this limit please: I have been trying to solve this for 2 hours with no success: $$\lim_{n\to \infty } \frac {1^3+4^3+7^3+...+(3n-2)^3}{[1+4+7+...+(3n-2)]^2}$$
Genadi
  • 381
4
votes
1 answer

How to find the limit of given function

How would I find this limit? $\lim_{n \to \infty}\ n\ \sin\ (2\pi en!)$, where $e$ is the exponential.
Struggler
  • 2,554
4
votes
2 answers

How find this limit $\lim_{x\to 1}\frac{f(2001)-f(2002)}{f(2002)-f(2003)}$

Let $$f(m)=\dfrac{m+1}{\dfrac{m+m+1}{\dfrac{m}{1-x^{m}}-\dfrac{m+1}{1-x^{m+1}}+\dfrac{1}{2}}+\dfrac{m+1+m+2}{\dfrac{m+1}{1-x^{m+1}}-\dfrac{m+2}{1-x^{m+2}}+\dfrac{1}{2}}}$$ Find this limit $$I=\lim_{x\to…
math110
  • 93,304
4
votes
2 answers

Limit of $(\arcsin x)^{\tan x}$ as $x$ tends to zero from the right

I came across an interesting limit I could not solve: $$ \lim_{x \to 0^{+}}\left[\arcsin\left(x\right)\right]^{\tan\left(x\right)} $$ Given we have not proven l'Hôpital's rule yet, I have to solve it without it. Also, I would rather not use advanced…
4
votes
1 answer

limit of $x \log y$ at $ (0,0)$

What is the limit of the function $x \log y $ at $(0,0)$? I believe the limit doesn't exist. But wolframalpha.com says the limit is 0. http://www.wolframalpha.com/input/?i=limit[+x+log%28y%29++%2C+x-%3E0%2C+y-%3E+0+]
Chao
  • 173
4
votes
2 answers

Find value of the limit: $\lim_{n\to \infty}\sqrt[n]{1^2+2^2+\cdots+n^2}$

Determine value of the limit: $$L=\lim_{n\to \infty}\sqrt[n]{1^2+2^2+\cdots+n^2}$$ My try: $$1^2+2^2+\cdots+n^2=\frac{n(n+1)(2n+1)}{6}$$ Hence: $$L=\lim_{n\to \infty} \sqrt[n]{\frac{n(n+1)(2n+1)}{6}}=?$$ But, come here, i do not know how, because…
Iloveyou
  • 2,503
  • 1
  • 16
  • 18
4
votes
1 answer

Clayton's copula limit to infinity

This is Clayton's copula: $C(u_1,u_2)=[u_1^{-\alpha} + u_2^{-\alpha} - 1]^{\frac{-1}{\alpha}}$ where $ (u_1,u_2) \in ]0,1]$ and $\alpha>0$ How do you prove the following limit to infinity ? $lim_{\alpha \to \infty}C(u_1,u_2)=min(u_1,u_2) $ What…
Pane
  • 143
4
votes
3 answers

How to solve this sum limit? $\lim_{n \to \infty } \left( \frac{1}{\sqrt{n^2+1}}+\cdots+\frac{1}{\sqrt{n^2+n}} \right)$

How do I solve this limit? $$\lim_{n \to \infty } \left( \frac{1}{\sqrt{n^2+1}}+\cdots+\frac{1}{\sqrt{n^2+n}} \right)$$ Thanks for the help!
4
votes
4 answers

How to solve $\lim_{x\to 16} \frac{4-\sqrt{x}}{16x-x^2}$

Solve the following question : \begin{eqnarray} \\\lim_{x\to 16} \frac{4-\sqrt{x}}{16x-x^2}\\ \end{eqnarray} The answer should be $\frac{1}{128}$. I try that: \begin{eqnarray} \\\lim_{x\to 16} \frac{4-\sqrt{x}}{16x-x^2} &=& \lim_{x\to 16}…
Casper
  • 1,039
4
votes
1 answer

Limits to infinite

$$20.\quad \lim_{x\to\infty}\frac{-6}{5x\sqrt[3]x} = -\frac65\lim_{x\to\infty}\frac1{x^{4/3}}= -\frac65\cdot 0 = 0$$ (Original scan of problem) I cant figure out how to resolve this problem. I would say that denominator tends to infinite and limit…
JorgeeFG
  • 493
4
votes
3 answers

Proving Limit False

I'm trying to prove that the limit of sin x as x->infinity is not equal to 1/2. I know that this is true, but I can't seen to figure out how to prove it using the precise definition of a limit. What I have so far is this, e>0, M>0 abs(sin x - 1/2)
ASAAR
  • 43
  • 3
4
votes
3 answers

Understanding limits and exact solutions

Consider the following equation: $\left(x^{2}-1\right)y=1-x$ Setting $y{=}0$ forces the LHS equal to zero, so $x$ must be 1 for the RHS to be zero too. However, if we now rearrange the equation as, $y=\frac{1-x}{x^2 - 1}$, and we apply L'Hopital's…
Anon
  • 41