Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

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Finding $\lim_{x\to0}\tan(x)^{1/x}$

I'm not sure how to evaluate this limit. $$ \lim_{x\to0^{+}} \tan(x)^{\frac{1}{x}} $$ I've attempted to use L'Hopital's rule, but I'm not sure if the indeterminate form (which I'll show below) from which I differentiate the numerator and…
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Evaluating $\lim_{n\to \infty} \sin(\sqrt{n^2+1}\pi)$. (WolframAlpha says it doesn't exist; I get $0$.)

I have tried to solve limit, which wolfram says that DNE, but according to my calculations it is equal to 0. Limit is given below $$\begin{align} \lim_{n\to \infty} \sin(\sqrt{n^2+1}\pi) &=\sin(\sqrt{n^2+1}\pi-n\pi+n\pi)…
paweta
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Evaluation of Trigonometric Limit having 5 terms

Evaluation of $\displaystyle \lim_{h\rightarrow 0}\bigg[\frac{\sin(60^\circ+4h)-4\sin(60^\circ+3h)+6\sin(60^\circ+2h)-4\sin(60^\circ+h)+\sin(60^\circ)}{h^4}\bigg]$ Here above limit is in $(0/0)$ form So we have using D, L Hopital rule $\displaystyle…
jacky
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Limit of $\sqrt[3]{(n+1)(n+2)(n+3)}-n$

I came up with a Solution for $\displaystyle\lim_{n\to\infty}\sqrt[3]{(n+1)(n+2)(n+3)}-n$ That's my Solution: $\sqrt[3]{(n+1)(n+2)(n+3)}-n$ \begin{aligned} &=\frac{\left(\sqrt[3]{n^3+6 n^2+11 n+6}-n\right)\left(n^2+n \sqrt[3]{n^3+6 n^2+11…
Luap2003
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What's wrong in this evaluation $\lim_{x\to\infty}x^{\frac{1}{x}}$ and why combinatorial arguments cannot be made?

The answers (as well as the premise) of this question have me confused. Please point out the error: $$\displaystyle \lim_{x\to\infty}x^{\frac{1}{x}}=\lim_{x\to\infty}e^{\frac{\log x}{x}} $$ By L' Hospital rule $$ \exp\left( \lim_{x\to\infty}…
kuch nahi
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Limit of $n^2\sqrt{1-\cos(1/n)+\sqrt{1-\cos(1/n)+\ldots}}$ when $n \to \infty$

Compute the limit: $$\lim_{n \to \infty} n^2\sqrt{1-\cos(1/n)+\sqrt{1-\cos(1/n)+\sqrt{1-\cos(1/n)+\ldots}}}$$
Simar
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How to Find the Limit Correctly?

I am refreshing my Calculus memory, and bump into this example (need feedback): $$f(x)= \begin{cases} -x, & \text{if } x < 0 \\ x, & \text{if } 0 \le x < 1 \\ 1 + x, & \text{if } x \ge 1 \end{cases}$$ I have to find the…
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Is my understanding of limits correct?

I want to explain the basic concept of limits to see if my understanding is correct or not. If we have a function in the form of a fraction and for a value of $x$ the numerator and denominator $=0$ , the graph of the function will have a…
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Evaluating $\lim_{x\to0}(x\tan x)^x$

Any suggestions for evaluating the limit $$\lim_{x\to0}(x\tan x)^x$$ I have tried writing $\tan$ as $\dfrac{\sin}{\cos}$ and then got the Taylor series of them but it didn't lead me somewhere. Thanks a lot
darkchampionz
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Calculate $\lim_{N\to+\infty}\left(\sum_{n=1}^N \frac{1}{n^2}-\frac{\pi^2}{6}\right)N$

How to calculate the limit $$\lim_{N\to+\infty}\left(\sum_{n=1}^N \frac{1}{n^2}-\frac{\pi^2}{6}\right)N?$$ By using the numerical method with Python, I guess the right answer is $-1$ but how to prove? I have no idea.
Stephen
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How can I find the limit of the following?

What is the limit of this $$\lim_{x\to+\infty}\left(1+\frac{4}{2x+3}\right)^x$$ I know that $$\lim_{x\to+\infty}\left(1+\frac{4}{2x}\right)^x$$ will give me $$e^2$$ but the I dont know what to do with the 3. I have tried bringing them to a common…
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Finding $\lim_{n\to\infty} \frac{((1!)(2!)(3!).....(n!))^{1/n^2}}{n^{\alpha}}$

if $\alpha ,\beta$ belong to $\mathbb{R}$, $\beta$ is not equal to zero, $n$ belong to $\mathbb{N}$ and $$\lim_{n\to\infty} \frac{((1!)(2!)(3!).....(n!))^{1/n^2}}{n^{\alpha}} = \beta$$ then please help me. Any help will be appreciated. Thanks I…
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Calculating the limit $\lim\limits_{\theta \to 0} \frac{\sin \theta}{\tan \theta}$

I'm calculating this limit and would kindly appreciate feedback on my solution $\lim\limits_{\theta \to 0}\dfrac{\sin \theta}{\tan \theta}$ What I've tried: given that $\tan \theta = \dfrac{\sin \theta}{\cos \theta}\;,$ then I rearrange the equation…
Meilton
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$\lim_{n\rightarrow\infty}\sum_{k=1}^{n}{2n\choose k}\frac{1}{4^{n}}$ and $\lim_{n\rightarrow\infty}\sum_{k=1}^{2n}{2n\choose k}\frac{1}{4^{n}}$ is?

$\lim_{n\rightarrow\infty}\sum_{k=1}^{n}{2n\choose k}\frac{1}{4^{n}}=\lim_{n\rightarrow\infty}(1+\frac{1}{4^n})^{2n}$ using…
Daman
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$\lim_{n\to\infty} \frac{10^n}{\sqrt{(n+1)!} + \sqrt{n!}}\,.$

$\lim_{n\to\infty} \frac{10^n}{\sqrt{(n+1)!} + \sqrt{n!}}\,.$ I used the ratio criterion for the calculation and I got to this, can I say now that it is zero or is it still an undefined…
user886372