Questions tagged [limits]

Questions on the evaluation and properties of limits in the sense of analysis and related fields. For limits in the sense of category theory, use the tag “limits-colimits” instead.

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.

The formal $\varepsilon$-$\delta$ definition of a finite limit at a point $a\in \mathbb{R}$ is:

$$\Big(\lim_{x\rightarrow a} f(x) = L \Big)\iff \Big(\forall \varepsilon >0\, \exists \delta > 0: \forall x\in D\quad 0<\vert x-a\vert <\delta \implies \vert f(x)-L\vert <\varepsilon \Big).$$

The concept of a limit of a sequence is further generalized to the concept of a limit of a topological net, and is closely related to the concepts of limit and direct limit in category theory.

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The decay of the series given by $x_n=x_{n-1}+\cos x_{n-1}$.

Let $x_n=x_{n-1}+\cos x_{n-1}$, $x_1=1$. It is easy to see that $x_n\to \dfrac{\pi}{2}$. However, how can we show that $n^n(x_n-\dfrac{\pi}{2})\to 0\ (n\to\infty)$? I find Stolz formula hard to use.
xldd
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Find constant numbers $a,b$ such that $\lim_{x \to 0}(x^{-3}\sin(3x)+ax^{-2}+b)=0$

Question : Find constant numbers $a,b$ such that $\lim_{x \to 0}(x^{-3}\sin(3x)+ax^{-2}+b)=0$ My try : I applied hopital, but it is again $\frac{0}{0}$ and the denominator becomes $x^6$ and $x^3$ which are a lot worse than the first…
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Calculate the limit $\lim_{(x,y,z)->(0,0,0)}{\frac{xyz}{\sqrt{x} + \sqrt{y} + \sqrt{z}}}$

$$\lim_{(x,y,z)->(0,0,0)}{\frac{xyz}{\sqrt{x} + \sqrt{y} + \sqrt{z}}}$$ I tried thinking about a solution using the epsilon-delta definition: I assumed that the limit is 0 but I couldn't figure out a inequality that would lead me to the solution.
oren revenge
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how can I find this limit

I have the bellow limit, and I know I need to use Cauchy-d’Alembert, and the limit is 1/e but have no idea how to get to it, I get to something like $\frac{\frac{\left(n+1\right)!}{n!}}{n}$, but is not right $$\lim _{n\to \infty…
John
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Evaluating $\displaystyle\lim_{x\rightarrow y}\frac{\sin^2x-\sin^2y}{x^2-y^2}$

I have to evaluate $\displaystyle\lim_{x\rightarrow y}\frac{\sin^2x-\sin^2y}{x^2-y^2}$ I tried several ways like replacing $x^2-y^2$ by $z$ and then solving and breaking the denominator into $(x+y)(x-y)$ and then replacing $(x-y)$ by $z$ and then…
Soham
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Prove that $ \lim_{x\to0} ({1^{(1/\sin^2x)} + 2^{(1/\sin^2x)} + 3^{(1/\sin^2x)} + ....+ n^{(1/\sin^2x)})^{\sin^2(x)}} = \frac{n(n+1)}{2} $

$$\lim_{x\to0} ({1^{(1/\sin^2x)} + 2^{(1/\sin^2x)} + 3^{(1/\sin^2x)} + ....+ n^{(1/\sin^2x)})^{\sin^2(x)}} = \frac{n(n+1)}{2}$$ Attempt: According to me, it has to be $1$, since the outermost exponent tends to $0$. But anyways, would taking the…
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Show that the equation $x^3 +1 = 15x$ has three solutions in the interval $[-4,4]$

Show that the equation $x^3 +1 = 15x$ has three solutions in the interval $[-4,4]$ There are many elementary ways to solve this. But this question came out in exam for calculus!! How do i solve it using calculus? Here's what I learnt so far...…
Yellow Skies
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Why isnt $\lim_{x\to 0}\frac{\sin x}{x} = 0$?

$$\lim_{x\to 0}\frac{\sin x}{x}$$ Can't we say this: $$\lim_{x\to 0}\left[\frac{1}{x}\right]\cdot\lim_{x\to 0}[\sin x]$$ So it would be infinity times 0, which would be 0. Why is this method wrong?
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If $\lim_{\{f(x),g(x)\}\to\infty}\frac{f(x)}{g(x)}=1$, then $\lim_{\{f(x),g(x)\}\to\infty}f(x)-g(x)=0$. Is that true?

I think that the following statement is true; If $\lim_{\{f(x),g(x)\}\to\infty}\frac{f(x)}{g(x)}=1$, then $\lim_{\{f(x),g(x)\}\to\infty}f(x)-g(x)=0$. But I haven't learned the rools of limits yet, so I don't know if it is. Can anyone make me sure…
76david76
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Find the limit of $(1-\frac2n)^n$

I am trying to find the limit of $$(1-\frac2n)^n$$ I know how $e$ is defined and I am sure the prove will involve substituting a term with $e$ at some point. But I do not really know where to start. I tried rewriting the term, simplifying it, using…
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Can there be 2 limits to an $x$ value?

Given function $g(x)$ and its graph below, I need to find $$\lim_{x\to 1}g(x)$$ Empty white dot means a limit. Judging from the graph it looks like there're 2 limits when $x\to 1$, that is $0$ and $2$. Is this correct?
Yos
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Find a limit of function: $\lim_{x\to 0}\frac{(-2)^{\lfloor x \rfloor}}{x} $

Find $\displaystyle \lim_{x\to 0}\left(\frac{(-2)^{\lfloor x \rfloor}}{x} \right)$ $\lfloor x \rfloor$ - is the floor function From graphic it seems that this limit is different from right and left.
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Did I break any limit laws here?

$$\lim_{n\to\infty} \frac{2^{100+5n}}{e^{4n-10}}= \lim_{n\to\infty} \frac{2^{100}2^{5n}}{e^{4n}e^{-10}}= 2^{100}e^{10}\lim_{n\to \infty}\frac{e^{-4n}}{2^{-5n}}= 2^{100}e^{10}\frac{\lim_{n\to \infty} e^{-4n}}{\lim_{n\to \infty}2^{-5n}} = 0$$ I think…
Lemon
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Convergent subsequence built from other subsequences

I want to build a convergent subsequence from two subsequences. Let $% \{n_{1_{l}}\}_{l=1}^{\infty }$ and $\{n_{2_{l}}\}_{l=1}^{\infty }$\ be increasing sequences of integers, not necessarily disjoint. Let $\{x_{n}\}$ have subsequences…
JBH
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Calculate $ \lim\limits_{n \to \infty} \sum\limits_{k=0}^n \frac{2^{k-1}}{a^{2k-1}+1} $

Let $a \in (1, \infty)$. Calculate $$ \lim\limits_{n \to \infty} \sum_{k=0}^n \frac{2^{k-1}}{a^{2k-1}+1} $$ Here's what I tried: Let $ x_n = \sum_{k=0}^n \frac{2^{k-1}}{a^{2k-1}+1} $. Let $a_n, b_n$ so that $a_n < x_n < b_n$. If $a_n \to l, b_n…
Victor
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