Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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Need to simplify a logarithmic expression

Can someone simplify this ($\log$ here refers to the common logarithm)? $$\sqrt{4\log2+(\log5)^2} + \sqrt{4\log5+(\log2)^2}$$ I know this has a simple solution but I cannot find it.
Anahit
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How to solve $x^{\log_3(x)} \geq \frac{1}{27}$

How to solve this? My problem is to solve: $$x^{\log_3(x-4)} \ge \frac{1}{27}.$$ The log base is $3$.
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Can I break up $\log(a - b)$?

For constants $a$ and $b$, I know that I can break up $\log(a/b)$ into $\log(a) - \log(b)$. Can I conveniently break up $\log(a - b)$ somehow into several terms?
David Faux
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Proving $\log x^2 = 2\log x$

How does $\log x^2 = 2\log x$? Can you do a proof please. I know that this is true but I don't know why.
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Spectral Centroid computation issue

I guess my problem is related to logarithmic <-> linear scales. I'm trying to create a colored wave form by using a Spectral centroid. So far I got the color but the scaling is incorrect. Why this ? It helps in identifying music, visually ... A…
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$e^{\ln((9)/\log(3))}=100$? Why is that?

I was messing around with my calculator and meant to put in $\log(9)/\log(3)$, which was supposed to be two. I look back, and I see my mistake, but curiously, I input that to the function $e^{(x)}$ and it comes out with $100$... Why is that? Why is…
user16795
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How do you solve this exponential equation?

$3(16)^x+2(81)^x=5(36)^x$ How do you change the bases to combine the terms? The correct answer should be 0 and 0.5. Edit: So this equation can't be solved algebraically? I have to use creative logic to solve it?
linksku
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Don't understand simple logarithm problem with fractional base

$$3\log_{\frac{4}{9}}\sqrt[4]{\frac{27}{8}}$$ $$\log_{\frac{3}{2}}\frac{16}{81}$$ I understand using the expansion property to expand the division into a subtraction but how do I proceed from there?
Kevin Li
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Solve for: $8\log_4\sqrt{x^2-9}+3\sqrt{2\log_4\left(x+3\right)^2}=10+\log_2\left(x-3\right)^2$

Solve for: $$8\log_4\sqrt{x^2-9}+3\sqrt{2\log_4\left(x+3\right)^2}=10+\log_2\left(x-3\right)^2$$ My try: $8\log_4\sqrt{x^2-9}+3\sqrt{2\log_4\left(x+3\right)^2}=10+\log_2\left(x-3\right)^2\\\Leftrightarrow…
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How to show that $\log (\frac{2a}{1-a^2}+\frac{2b}{1-b^2}+\frac{2c}{1-c^2})= \log\frac{2a}{1-a^2}+ \log \frac{2b}{1-b^2}+ \log \frac{2c}{1-c^2}$

If $\log (a +b +c) =\log a+\log b+\log c$ then show that $$\log \left(\frac{2a}{1-a^2}+\frac{2b}{1-b^2}+\frac{2c}{1-c^2}\right)= \log\frac{2a}{1-a^2}+ \log \frac{2b}{1-b^2}+ \log \frac{2c}{1-c^2}$$ Trial: If put $a=\frac{2a}{1-a^2}$ and the similar…
Argha
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Solve: $\frac{1}{2}\log_{\frac{1}{2}}\left(x-1\right)>\log_{\frac{1}{2}}\left(1-\sqrt[3]{2-x}\right)$

Solve: $$\dfrac{1}{2}\log_{\frac{1}{2}}\left(x-1\right)>\log_{\frac{1}{2}}\left(1-\sqrt[3]{2-x}\right)$$ My try: Conditions identify: $\left\{ \begin{array}{l} x-1>0\\1-\sqrt[3]{2-x}>0\end{array} \right.\Leftrightarrow \left\{ \begin{array}{l}…
AM - GM
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logarithm equation with different bases.

Why is this like it is? :D $$\dfrac{1}{\log_ae} = \ln(a)$$ I'm solving some exercises and I ran up to this? Maybe it's really banal, but please explain me...
A6SE
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$\frac{N\log{N}}{k\log{k}}\approx \log_{k!}{N!}$

What is the simple way to show that $$\frac{N\log{N}}{k\log{k}}\approx \log_{k!}{N!}\quad?$$ I tried to use the factorial and the log rules but.. Thanks.
user6163
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how to simplify $\log_{a/b}(n)$

This is stemming from a programming problem, and I am trying to figure out if there is an easier way to go about the issue. I need to get $\log_{a/b}(n)$, with $0 < a/b < 1$. Is is possible to rewrite $\log_{a/b}(n)$ as something along the lines of …
Doragon
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Simplifying Logarithms

I am Preparing for an Exam, and this is one of my Exercises that I tried to solve, I know that the answer is : $-2
Green Fire
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