Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

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Switching the base of scientific notation without solving for the number or exponent.

Assuming I have a number of the form $a * 2^b$, I want to represent it in the form $c * 10^d$. I want to do this conversion without calculating neither $a*2^b$ or $2^b$ Currently, as per this question I'm using: $d = ⌊b * (ln(2)/ln(10))⌋$ to…
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Approximate the logarithm of any base

I'm currently in the process of approximating the logarithm of any base. I know that $\ln(x)$ or $\log_e(x)$ can be approximated with this formula: $$\ln(x)=2\sum_{k=0}^\infty\frac1{2k+1}\left(\frac{x-1}{x+1}\right)^{2k + 1}$$ This was taken from…
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$\log(x^2)$ is not equal to $2\log(x)$

on internet we usually see: $$2\log(x) = \log(x^2) $$ (example)but how is this true? one is defined for $x>0$ and the other one for $x\neq0$
anon
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A basic level log question

Answer is 3/2 to this question: But how? And why?
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Questions on proofs that a number's digits = $\lfloor \log_{10} n \rfloor +1$?

Please expound in Simple English. My child is 14. User797616 answered $n \le \color{red}{9 \cdot 10^{k - 1} + 9 \cdot 10^{k - 2} + \ldots + 9 \cdot 10 + 9} \color{limegreen}{= 10^k - 1} < 10^k.$ I use formula to sum this finite geometric…
user53259
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Solve for $x:\log_x(\frac52-\frac1x)\gt\frac52-\frac1x$

Question: Solve for $x:\log_x(\frac52-\frac1x)\gt\frac52-\frac1x$ My approach: I tried taking two cases when $x\gt1$ or when $0\lt x\lt1$. For the first case, I wrote $\frac52-\frac1x>x^{\frac52-\frac1x}$. But for this case, the book wrote…
aarbee
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Got 4 answers for logarithm question but calculator only gives 2

Logarithm question is $\log_9(\sqrt[3]{(x^2-1)^2}) = \frac{1}{3}$ When I solved the question I rewrote the question as $\sqrt[3]{9} = \sqrt[3]{(x^2-1)^2}$, canceled the cube roots and then took the square root of both sides to get $x^2-1 = \pm3$ and…
chair
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how to solve the following logarithm with both base and value in $x$

$\log_{x - 1} \frac{N}{x} = \log_{49} \frac{N}{2450}$, where $N$ can be considered a constant. I tried using base changing formula by changing the base on both sides to $49$ but the equation gets overcomplicated. I am wondering if there is a simple…
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Series of ln(x) for x>=1

I need to develop $\mathrm{ln}(x)$ into series, where $x \geq 1$, and I don`t know how? In literature I only found series of $\mathrm{ln}(x)$, where: $|x-1| \leq 1 \land x \neq 0$, $ \,\,\,\,\, \mathrm{ln}(x) = x - 1 - \dfrac{(x-1)^2}{2} +…
nick_name
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How to solve for x when x is found in both the exponent and multiplied to a term a (without using Lambert W function, if possible)

We are currently discussing logarithms and exponential equations. I am currently answering a problem set until I stumbled upon this question: $2(2^{2x})=4x+64$ I tried using the usual methods such as log and ln but I could not get past the $4x+64$.…
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Logarithmic properties to expand $\ln\left(2b \sqrt\frac{b+1}{b-1}\right)$.

I am having a hard time with logarithmic properties, and I was wondering how to expand this equation by using the properties. The equation and the steps I have done so far are $$\ln\left(2b \sqrt\frac{b+1}{b-1}\right)$$ $$\text{Quotient…
Benp404
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Solving $ U=\frac{2\cdot λ_g}{\pi\cdot B+d_f}\cdot \ln\left(\frac{\pi\cdot B}{d_f}+1\right) $ for $d_f$

Can anyone help me solve this equation to isolate $d_f$? $$ U=\frac{2\cdot λ_g}{\pi\cdot B+d_f}\cdot \ln\left(\frac{\pi\cdot B}{d_f}+1\right) $$ (original equation from ISO13370) I can get the values from the natural log with inverse log, but then…
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Why does raising the logarithm of a number by its base equal the number?

I found the following rule while reviewing logarithms: "Raising the logarithm of a number by its base equals the number.", i.e., $$ b^{\log_b (k)} =k.$$ Why is this true? (Wording of rule credit:…
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Prove: $\log_{a}{\frac{a^n+b^n}{a^m+b^m}}+\log_{b}{\frac{a^n+b^n}{a^m+b^m}} \geq 2(n-m)$

How to prove: $$\log_{a}{\frac{a^n+b^n}{a^m+b^m}}+\log_{b}{\frac{a^n+b^n}{a^m+b^m}} \geq 2(n-m),$$ where $n>m$, $a,b \in (1, \infty)$. I tried some methods such as $$ a^n +b^n \leq (a+b)^n$$ but with no result, at least not right. or $$…
Mark Ben
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Solve equation with log factor inside exp

I'm sure this is trivial. I want to reform the basis of a logarithm, so that I transform a factor 10.0/log(10.0) into a factor 1.0/log(x) so I want to solve x in 1.0/log(x) = 10.0/log(10.0) I reciprocate and exponentiate x = exp(log(10.0)/10.0) …
Emit Taste
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