Questions tagged [logarithms]

Questions related to real and complex logarithms.

The logarithm is generally defined to be an inverse function for the exponential. If $x > 0$ is a real number and $b > 0$, $b \ne 1$, then the base-$b$ logarithm is defined by

$$\log_b(x) = y \iff b^y = x$$

The most commonly used bases are base $10$ and $2$ (which frequently arises in computer science), and particularly base $e$. The natural logarithm $\ln$ is defined to be $\log_e$.

Alternatively, the natural logarithm can be defined to be a primitive of the function $$f(t) = \frac{1}{t}$$ subject to the condition that $\ln{1} = 0$.

In the study of complex numbers, the solutions $a$ of $e^{a} = z$ are called complex logarithms. This uniquely specifies the modulus of $a$, but not its argument; as such, we define the principal logarithm $\operatorname{Log}(re^{i\theta}) = \ln{r} + i \theta$, with the restriction $-\pi < \theta \le \pi$ (or alternatively, $0 \le \theta < 2\pi$). This leads to a branch cut, or discontinuity - alternatively, the complex logarithm can be viewed as a multi-valued function.

Reference: Logarithm.

This tag often goes along with .

10168 questions
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show that $0.5 - \frac{ln(x)}x > 0$

I try to show that $$ \frac{1}{2} - \frac{ln(x)} x > 0 $$ on $x \in (0, \infty)$ , any help would be appreciated, but the simplest way will be the best
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If $f(x) = ax +b$, is $\ln{f(x)} \equiv \ln(ax+b)$ or $\ln{ax}+\ln{b}$?

If $f(x) = ax +b$, is $\ln{f(x)} \equiv \ln(ax+b)$ or $\ln{ax}+\ln{b}$? If it is $\ln(ax+b)$ how should I go about splitting or simplifying $\ln{(ae^{c}+b)}$?
Tobi
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Why does $(\log_x y)(\log_y x) = 1$?

I just noticed that the product of two different logs with the bases switched around will always equal one. $(\log_x y)(\log_y x) = 1$ Why is this the case? What is the algebraic proof? Thanks!
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Solving a logarithmic equation: got two answers but one is rejected. Why?

the answer in the textbook is 10^[1-√(3)]/2. how does the other root not satisfy the original equation?
Raknos13
  • 572
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Is this logarithmic true?

$$x^{\log_{10}\left(\frac{y}{z}\right)}y^{\log_{10}\left(\frac{z}{x}\right)}z^{\log_{10}\left(\frac{x}{y}\right)}=1$$ for $x, y, z>0$. Please help me I couldn't figure this out for the life of me.
Le Meme
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How do you prove that $\log n \cdot \log n$ grows no faster than $\sqrt{n}$

I had to graph it to see it. How can I prove it?
Samu
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Logarithmic simplification

I don't understand the last simplification $9^{\log n} = n^{\log 9}$: $$3^{\log(n^2)} = 3^{2\log n} = 9^{\log n} = n^{\log 9}$$ Can someone please show me how they did it? Is there a rule that I have missed?
Samu
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Logs of negative numbers

$\log_{-2}(-8) = \frac{\log8+i\pi}{\log2+i\pi}$ (which is definitely not 3) But what if we allowed all values (not just the principal value) of $\log(-1)$? i.e, $\log(-1) = i(2n+1)\pi$ (n is an integer) $\Rightarrow \log_{-2}(-8) =…
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Logarithm Calculation

It was part of my graph theory homework solution. The topic was about random graphs. I have difficulty understanding one step about log calculation. Hope someone could help me answer this: $\frac{\log(1-\frac{c\log n}{n})}{-\frac{c\log…
adosdeci
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Solving Logarithmic equations- $\log(3x) = 3x - 8$

I had this problem on a worksheet and tried a bunch of different log properties on it, but ended up getting stuck. Any help would be appreciated! $$\log(3x) = 3x - 8$$
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How to convert a number to $10^n$?

How to convert a number to $10^n$? For example, $9.3\times10^{-6}=10^{-5.03}$. How do you do this conversion to calculate the exponent of $10$? How does one calculate the $-5.03$ exponent?
eam
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Simplifying natural logarithmic equations

Write as a single logarithm and simplify your answer. I am totally unsure as to how far this can be simplified. Should I be factoring the quadratic and then using the product/quotient rules? Any help would be amazing!
edward
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Identity (logarithms)

There is a simple question for identity: $\log_{ab}X = \frac{\log(a)X \times \log(b)X}{\log(a)X + \log(b)X}$ To proof, I goes for $ab$ base for right, but seems Im wrong. Can anyone help? Thank you!
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Center of range on logaritmic range

Suppose I have a range between 500 and 20.000. How do I find the centre of this range on a logaritmhic scale? Thanks in advance
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Show that $x \ln(ex) - \sqrt{x}\geq 0$ for all $x\geq 1$

How do I continue to prove this? Show that $$ x \ln(ex) - \sqrt{x}\geq 0 $$ for all $$ x \geq1 $$ My try: $$\begin{eqnarray*} \\ \ln(e^x) + \ln(x^x) &\geq& \sqrt{x} \\ \\ \ln(e^x) &\geq& \sqrt{x} - \ln(x^x) \\ \\ e^x &\geq & e^\sqrt{x}…
Curtain
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