Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

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If $d_1,d_2$ are not equivalent metrics, is it true $(X,d_1)$ is not homeomorphic to $(X,d_2)$?

Consider the statement: If $(X,d_1)$ and $(X,d_2)$ are metric spaces and $d_1,d_2$ are not equivalent metrics, then $(X,d_1)$ is not homeomorphic to $(X,d_2)$. I think this is true, however I can't seem to prove it. Since the metrics are not…
fosho
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Distance from a point to empty set.

Let $(X,d)$ be a metric space and let $A \subseteq X$. We define the distance from a point $x \in X$ to $A$ by $d(x,A)= \inf \{ d(x,a) : a \in A \} $. What will be the value of $d(x, \emptyset )$? I am confused between $+ \infty $ and $- \infty$.…
deditus
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Topological equivalence between $\Bbb R^n$ and itself.

To start with, let me just state this theorem: THEOREM 1 Let $(X_i,d_i)$,$(Y_i,d_i^{\,\prime})$ be metric spaces for $i=1,\dots,n$. Let $f_i:X_i\to Y_i$ be continuous for each $i$ as functions from the metric spaces $X_i$ to $Y_i$. Define the…
Pedro
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Open ball cartesian product on metric space: $B(a,r) = B(a_1, r)\times \cdots \times\ B(a_n,r)$

I need to prove that $$B(a,r) = B(a_1, r)\times \cdots \times B(a_n,r)$$ in $M=M_1\times\cdots \times M_n$ where $M_i$ is a metric space and the metric is $d''(z,z') = \max\{d_i(x_i,y_i), i \in \{1,\ldots,n\}\}$ where $d_i$ is the metric for…
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Relation between metrics

Let $$\eqalign{ & d\left( {x,y} \right) = \mathop {\max }\limits_{1 \leqslant i \leqslant n} \left\{ {\left| {{x_i} - {y_i}} \right|} \right\} \cr & d'\left( {x,y} \right) = \sqrt {\sum\limits_{i = 1}^n {{{\left( {{x_i} - {y_i}} \right)}^2}} }…
Pedro
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Is $\mathbb{R}$ an open ball in $\mathbb{R}$?

If we write $B(0,\infty)$ as the open ball then $\mathbb{R}$ is an open ball in $\mathbb{R}$. Is it correct?
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Euclidean metric in $\mathbb{R}^n$; the singleton is not open in such a metric space

I am trying to prove this but just don't see it. We are talking about openness in the metric sense, yes? So, my attempt is Let $x \in \mathbb{R}^n$ and $d$ represent the Euclidean metric, $d(x,y)=\sqrt{\sum(x_i-y_i)^2}$. An open ball around a point…
Melba1993
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Is the empty set an open ball in a metric space?

Problem Let $(X,d)$ be a metric space where $X$ is a non-empty set. Is the empty set an open ball in $X$? I think that it is true because if $X=\mathbb{R}$ with the usual metric then for all $a\in\mathbb{R}$ we can say that the set $(a,a)$ is an…
user170039
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Is it always possible to find a "pre-metric" from a metric?

Problem Let $X$ be a non-empty set. Let $f:X\times X\to \mathbb{R}$ satisfying the following properties, $f(x,y)=0\iff x=y$ for all $x,y\in X$. $f(x,y)=-f(y,x)$ for all $x,y\in X$. $f(x,y)=f(x,z)+f(z,y)$ for all $x,y,z\in X$. If such a…
user170039
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A proof that the closure of a set A is equal to the union of A and its limit points

Wanted to check if this proof is valid (not completely sure about the end): We claim that $$\bar A = A \cup A'$$ Proof: Take some a $\in A \cup A'.$ If $a \in A$ then $a \in \bar A$. If $a \in A'$ then consider a sequence $(a_n) \rightarrow a$,…
megiddo
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descending sequence of balls in a complete ultrametric space

A metric space $(X,d)$ where $X$ is a set and $d:X\times X\rightarrow\mathbb{R}_{\geq 0}$ is a distance function satisfying the usual axioms for a distance function, together with the strict triangle inequality…
Rupert
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Why metric defined on $\mathbb{R}^2\times \mathbb{R}^2$ by $(a,b)\mapsto | a_1 - b_1| +| a_2 - b_2| $ is known as taxicab metric?

$\mathbb{R}^2$ with the function defined on $\mathbb{R}^2\times \mathbb{R}^2$ by $(a,b)\mapsto | a_1 - b_1| +| a_2 - b_2| $ where $a = (a_1, a_2)$ and $b = (b_1, b_2)$ is a metric. I wonder why it is known as taxicab metric. Could anyone explain…
Srijan
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Why does the distance function (between $x\in A$ and $A\subseteq X,$ $X$ a metric space) use $\inf$ and not $\sup$?

Given a subset $A\subset X$ of a metric space (X, d) and $x\in X$. The distance between the point x and the set A is the infimum of the distances between the point and those in the set: $$d(x,A) = \inf_{a\in A} \{d(x, a)\}.$$ I need explanation…
Srijan
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Bounded and unbounded homeomorphic metric spaces

I'm struggling to come up with an example of homeomorphic metric spaces such that one is bounded and one is not
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Complement of any finite set in metric space.

I am asked to show that in a metric space the complement of any finite set is open. That means I have to show that finite set is closed. I just tried to cope up with this problem using closure definition but dont know whether my approach is correct…
Kavita
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