Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

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Is this subset of a finite metric space already named?

Given a finite set, $X$, with a metric, $d(x,y)$ defined on it, I am interested in the following subsets: $S_k\subseteq X$ s.t. $\forall x\in X,\exists s\in S_k:d(x,s)\geq k$ Do such constructions have a particular name I should be searching for or…
Stan
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Showing a metric space is complete.

On the space of continuous functions on $[0,1]$, I have a metric $$d(f,g) = \sup | \alpha(x) (f(x) -g(x))|,$$ where $\alpha(x)$ is a continuous function and $\alpha(x) \ne 0$. I'm trying to find whether this space is complete. I think it is complete…
Wooster
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Showing an open ball is open

Let X be a metric space with metric d. I'm trying to show that U(xo;e) is an open set. What I note so far is to talk about a subset U that for each xo an element of U, there is a corresponding e > 0 s.t. U(xo;e) is contained in U. Does this finish…
Buddy Holly
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Write an open set in terms of a closed set

$(X,d)$ is a metric space. We fix a point, $a \in X$, and we let $A = \bigcap_{n\in\mathbb{N}} \left\{x: d(x,a) < r + \frac{1}{n} \right\} \in X$. Is $A$ open or closed? If it is closed. What is the proof that it is closed? Thank you for your…
Mikkel Rev
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Is the following statement true?

Let $(X_1, d_1),\ldots,(X_n, d_n )$ be metric spaces, $ X: = X_1 \times \cdots\times X_n$ be their Cartesian product with metric $d$. Let $ \pi_i : X \to X_i$ be the projection for $ 1 \le i \le n$. Suppose $(X,d)$ satisfies: for any metric space…
user112564
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Are these metrics complete?

Determine if these subsets of R are complete with the Euclidean metric? a) $[0,\infty)$ b) $(0,\infty)$ I know the definitions of completeness and I know the Euclidean metric, but don't know how to test this...
kiwifruit
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If $X$ is complete, then every subset of $X$ that is closed and totally bounded is also compact. Does the converse hold?

Let $X$ denote a metric space. Supposing every subset of $X$ that is closed and totally bounded is also compact, is $X$ necessarily complete? What I've got so far. Assume every $X$ subset of $X$ that is closed and totally bounded is also compact,…
goblin GONE
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Open Subsets of open sets

How does one go about proving/disproving that given $(X,d)$ a metric space that a subset $S$ is open. Given the following definitions: A set $X$ is open $\iff \forall x \in X, x\in int(X)$ i.e. x is interior point where an interior point is defined…
Mathman
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Prove that $\cup_{\alpha} A_{\alpha}$ has finite diameter

Prove that $\cup_{\alpha} A_{\alpha} $ has finite diameter if $\cap_{\alpha} A_{\alpha}≠∅$ and there exists a constant $M$ such that $diam(A_{\alpha}) ≤ M$ for all $\alpha$. Each $A$ is a subset of metric space $(X,d)$, and each $A$ has a finite…
Kate
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compactness and seq.compact of metric space

prove that a sequentially compact subspace of a metric space $X$ is closed in $X$? I wil solve this question from defination of sequentially compact but I dont know how?.(I dont want to solve it from compactness)
armin
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Is there a continuous, strictly increasing function $f: [0,\infty)\to [0,\infty)$ with $f(0) = 0$ such that $\tilde d = f\circ d$ is not a metric?

Is there a continuous, strictly increasing function $f \colon [0,\infty)→ [0,\infty)$ with $f(0) = 0$ such that $\tilde d = f\circ d$ is not a metric? You may take $(X,d)$ to be $\mathbb R$ with the standard metric for this part. My thoughts are…
Sam
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Completeness & Closedness in Metric Spaces

If every (proper) closed subset of a metric space is complete, then is the whole space necessarily complete as well?
12455421
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On the definition of Jordan curves

I read that the definition of Jordan curve is that it is homeomorphic to $S^1$. Is this equivalent to say that the curve is closable, continuous and non-self-intersecting? I'm not sure if closable is the correct term but I mean that if we have a…
Student
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metric spaces, $B_r(x)=B_s(y)$, is $y=x$ and $r=s$?

Let if $B_r(x)$=$B_s(y)$ for some $x$,$y$ in metric space $M$ and $r$,$s$ $\in$ $R$. Is true $x=y$? Is true $r=s$?
armin
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Showing the unit ball in $l^{\infty}$ is not compact.

If $l^{\infty}$ is the set of bounded sequences of real numbers with norm $||x||_{\infty}$. To do this I have tried to use the fact that a metric space is compact iff it is sequentially compact. So now I am trying to find a sequence with no…
Wooster
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