Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

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Show that the set $A:=\{f\in{C[0,1]}: |f(t)|<1 \forall{t\in{[0,1]}}\}$ is an open set in $C[0,1]$ with the supremum metric.

By definition, I need to show that every point in $A$ is an interior point in $A$. Do I go about this by showing $A'$ is closed? Please help. Correction in the title: For all $t\in{[0,1]}$.
mmh0015
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Do all subsets of metric spaces have boundry points?

I am learning about metric spaces. I failed to find an aunambiguous answer to my question on Google. So this is the right place to ask: Assume (X,d) is a metric space, and $A \subset X$. If I understand correctly, as long as $(X,d)$ is a metric…
Mikkel Rev
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Preimage of a sequence of cauchy

Let $X,Y$ metric spaces. If $f:X\to{Y}$ is continuous, and $\{y_n\}$ is a Cauchy sequence in $Y$. Then, my question is $\{f^{-1}(y_n)\}$ is a Cauchy sequence in $X$? I´m sorry, in a second thought, f is surjective and suppose X is complete. Any…
user126033
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Distance function (without absolute value nor square root)

I'm trying to invent or find a distance function in a two-dimensional space that only makes use of the basic arithmetic operations (+,-,*,/) as I want to use that function in a "programming language" that only supports these operations (and no…
Pold
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Let $(X,d)$ be a metric space.Which of the following statements are true?

Let $(X,d)$ be a metric space.Which of the following statements are true? (a)A sequence {$x_n$} converges to $x$ in$X$ iff the sequences {$y_n$} is a cauchy sequence in $X$ , where, for $k\ge1$ , $y_{2k-1}=x_k$ and $y_{2k}=x$. (b)if $f:X \to X$…
jadugar
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Define a subset of a metric space that is both open and closed.

Define a nonempty subset of a metric space that is both open and closed. The real line with the Euclidean metric $d(x,y)=|x-y|$ is open and closed. If you take two real lines, not connected together, and invent a metric that works for any pair of…
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How is this not a metric?

I would probably get this answer eventually, I pose this question because of the time I have spent looking for why it is not. The metric is: $$d_p(x,y)=(|x_1-y_1|^p+|x_2-y_2|^p)^\frac{1}{p}$$ for $p\in(0,1)$ I've just realised I actually…
Alec Teal
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Prove this set is compact

Let $\{a_{n}\}_{n \in \mathbb{N}}$ be a sequence with the property that $\{a_{n}\}$ converges to $0$ when $n \rightarrow \infty$. Now let's consider this set: $$K=\{\{x_{n}\}_{n\in\mathbb{N}} \in l_{\infty} : |x_{n}|\leq|a_{n}| \text{ } \forall …
Maxi
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Topologically equivalent metrics but not strongly equivalent in $\mathrm{Lip}_M(\mathbb{R})=\{f:[0,1]\rightarrow\mathbb{R}:|f(y)-f(x)|\leq M·|y-x|\}$

Let's consider this set $\mathrm{Lip}_{M}(\mathbb{R})=\{f: [0,1] \rightarrow \mathbb{R} : |f(y)-f(x)|\leq M\cdot|y-x| \}$ (i.e Lipschitz functions in $[0,1]$). How can I prove that $(\mathrm{Lip}_{M}(\mathbb{R}), d_{\infty})$ and…
Maxi
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$\mathbb Q$-metric spaces: how much is lost?

I want to know how weak (literally "punctured") the theory of metric spaces becomes if we impose the condition that the distance function can assume only rational (nonnegative) values.
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Are all metric translations isometries

Let $(M, d)$ be a metric space. I define a translation of $M$ to be a function $f$ from $M$ to $M$ such that $d(x, f(x)) = d(y, f(y))$ for all $x$ and $y$ in $M$. My conjecture is that every translation on $M$ is an isometry under the same metric.…
user107952
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Tell that sequence $(x_n)$ converges if and only if there $n_0\in \Bbb N$ such that $x_n=x_{n_0}$ for all $n\geq n_0.$*

I do not know how to solve the following example so if any of you can help me solve. Please. The example is as follows: Let $(X,d)$ a discrete metric space and $(x_n)$ is a sequence in $X$. Tell that sequence $(x_n)$ converges if and only if there…
Madrit Zhaku
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Finding the closure of $\mathbb{Z}$ and $\mathbb{Q}$ in $\mathbb{R}$

Let be $A$ subset of a metric space $(X,d)$ Definiton. Point $x\in X$ is adherent point (it can also have any other definition but sorry and forgive me if I wrong) of set $A$ if $$T(x,r)\cap A\neq \phi, $$ for all r>0. Set of all adherent points of…
Madrit Zhaku
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Whether a function$d(m,n)=\left\vert\frac{1}{m}-\frac{1}{n}\right\vert$ metrics

I saw in a magazine the following example" Whether a function $d(m,n)=\left\vert\frac{1}{m}-\frac{1}{n}\right\vert,$ where $m,n\in\mathbb{N}$ metrics. I know that map $d:XxX\rightarrow\mathbb{R}$ that has property: $M1)$ $d(x,y)=0\Leftrightarrow…
Madrit Zhaku
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Showing that a set is open

Endow $R^2$ with the metric $d(a,b)$ ={ $max{|a_1-b_1|,|a_2-b_2|}$} where $a$=$(a_1,a_2)$ and $b$=$(b_1,b_2)$. Show that $S$={${a \in R^2|a_1^2+a_2^2<1}$} is open in $R^2$ with this metric. $S$ is definitely open with respect to the euclidean metric…
johny
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