Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

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what would be a example in a general metric space about closedness and boundedness not imply sequential compactness?

Unlike in $R^n$, closed and bounded doesn't guarantee sequential compactness. Textbook examples includes sup metric and R^infinite metric. I am wondering what would be a example of closed and bounded doesn't imply sequential compactness in more…
user48601
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subset of the set of all bounded functions of vanishing variation

Let $(X,d)$ be a metric space, we define the following: $D_b(X)$ is the set of all bounded functions $f:X\rightarrow \mathbb{C}$ $f\in $$D_b(X)$ is said to vanish at infinity if for each $\epsilon$>0 there is a bounded set $K\subseteq$ X such that…
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Metric problems

I am taking the GRE in less than 10 days, and I have never taken analysis. And I would like to tackle metric problems and I was wondering if anyone could show me a certain strategy to solve problems as the following. For every set $S$ and every…
hyg17
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Metric Spaces Past paper qestion

Let $(X, d)$ be a metric space. For each $a ∈ X$ let $f_a : X → \mathbb{R}$ be the function $f_a(x) = d(x, a)$. (a) Prove that for all $a, b ∈ X$ $$\sup_{x∈X}|f_a(x) − f_b(x)| = d(a, b).$$ (b) Fix a point $c ∈ X$. For each point $a ∈ X$ define the…
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Any closed and bounded set $X$ of $\mathbb{R}^n$ is contained in some hypercube

Let be $X$ a closed and bounded set of $\mathbb{R}^n$: how to prove that there exsist $a,b\in\mathbb{R}$ such that $X\subseteq[a,b]^n$? As reference I said that I know that if $X$ is bounded then there exist some $x_0\in\mathbb{R}^n$ and some $r>0$…
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Distance between compact subsets of open sets

If $G$ is an open set and $K$ a compact set with $K\subset G$, show that there is a $\delta>0$ such that $\{x:\textrm{dist}(x,K)<\delta\}\subset G.$
PCeltide
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Are weighted metrics still metrics?

I am trying to find any result regarding the properties of metrics that are weighted: are they still metrics? If the weights are fixed, it's clear they would still satisfy the properties of a metric. However, what about weights that are dependent on…
rsttest
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Prove $d(x,y)=\left|\frac{x}{1+\sqrt{1+x^2}}-\frac{y}{1+\sqrt{1+y^2}}\right|$ is a metric on $\mathbb{R}$.

I have to prove that $d(x,y)=\left|\frac{x}{1+\sqrt{1+x^2}}-\frac{y}{1+\sqrt{1+y^2}}\right|$ is a metric on $\mathbb{R}$. I managed to prove the non-negativity, symmetry and triangle inequality, but I am stuck on proving $d(x,y)=0\Leftrightarrow…
Melissa
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Baire's theorem problem

Let $X$ be a complete metric space without isolated points and $A \subseteq X$ a numberable dense subspace. I want to probe that $A$ is not a $G_{\delta}$ I thought about constructing $A$ as de union of it's points, that are closed set with empty…
Silkking
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Equivalence on metric space

I made a typo, so my question is repeating, but it is edited. Can someone help me to solve this problem? Let $(M,d)$ be a metric space and let function $d$ be only $0, 1,3$. We say that element $x \in M $ is equivalent with element $y \in M $ if…
user714814
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Diameter of closed nested sets whose intersection is a single point

Let $(X,d)$ be a complete metric space and let $C_n$ be a sequence of connected, closed sets such that $C_{n+1} \subset C_n$ for every $n \in \mathbb{N}$. Assume that $\bigcap\limits_{n =1}^\infty C_n$ consists of one single point. I would like to…
javi1996
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Let $(X,d)$ be a metric space and assume that $B_r^d(x)=B_s^d(y)$. is $r=s$ and $x=y$

Let $(X,d)$ be a metric space and assume that $B_r^d(x)=B_s^d(y)$ where: $$B_r^d=\{ a \in X | d(a,x) < r\}$$ Now, is it always true that (a) $r=s$ (b) $x=y$ I made an elaborate argument on this question why both these statements should be true.…
Slugger
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Is the mapping $ d : X\times X \mapsto \mathbb {R} $ continuous?

Where $ (X, d) $ is a metric space. I want to prove it using sequential criteria. How do I tackle it?
Andy
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Is this a metric on $C[0,1]$?

At $C[0,1]$ we define the function $$d(f,g)=\int_{0}^{1}\vert(f(t)-g(t))(2f(t)+3g(t))\vert dt. $$ Is $d$ a metric on $C[0,1]$?
Kostas
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Sequence of totally bounded sets

I've been trying to solve this question for a while now: If $\{E_n\}$ is a sequence of totally bounded sets such that diam $E_n \rightarrow 0$, show that $\cup_{n=1}^{\infty} E_n$ is totally bounded. I don't seem to understand what to do or how…
PCeltide
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