Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

A function $d: M\times M\to \mathbb R$ is called a metric if for all $x,y,z \in M$ we have

  1. $d(x,y)=0\iff x=y$
  2. $d(x,y)\geq 0$
  3. $d(x,y)=d(y,x)$
  4. $d(x,y)+d(y,z)\geq d(x,z)$.

It is a generalisation of "distance". A metric space is now defined as an ordered pair $(M,d)$, where $M$ is a set and $d:M\times M\to R$ is a metric.

An $\varepsilon$-neighbourhood of $x$ is defined as the set $$B_\epsilon(x):=\{y\in M\mid d(x,y)<\varepsilon\}.$$ $B_\varepsilon(x)$ is commonly also known as the open ball of radius $\varepsilon$ around $x$. All open balls form a base for a topology on $M$. Although all metric spaces are topological spaces, the converse is generally not true.

Some different types of metric space include

  1. Complete metric spaces (every Cauchy sequence converges)

  2. Bounded metric spaces (every metric is bounded by a finite value)

  3. Compact metric spaces (every sequence has a convergent subsequence)

  4. Locally compact metric spaces (every point has a compact neighbourhood)

  5. Separable metric spaces (it possesses a countable dense subset).

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metric space $X$ in which a finite set is dense

My question is,what can you say about a metric space $X$ in which a finite set is dense? My thought: Let $A$ be any finite set in $X$.If $X$ is infinte then for any $x$ in $X$ and for any $p>0$, $d(a,x)
jimm
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Proper superset of a union of the closure of countably many uncountable sets

Consider a countable collection of uncountable subsets $A_1, A_2, A_3, \ldots$ and the subset $B = \cup_{i = 1}^\infty A_i$ of a metric space $X$. $\bar{A}$ denotes the closure of the set $A$. I came up with the following example of a set $B$ as…
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Is this following define a metrics?

Is this following define a metrics $d((x, y), (x’, y’)) = \min\{|x – x’|, |y – y’|\}$ on $\mathbb{R}^2$. As i found the answer Which of the following define a metric? but not getting in my head my attempts :i found all the metric properties …
user476275
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Is the following metric space compact?

$M = [-1,1]\times[-1,1], d((x,y),(a,b))=\begin{cases}|x-a|& y=b\\ |x|+|a|+|y-b| & y\not= b\end{cases}$ I feel like this is not compact and have being trying to show this by showing it's not sequentially compact. If we take a sequence…
user438263
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Open sets are unions of compact sets

Let $O$ be open in $\mathbb{R}^n$. Show that O is the union of a sequence of compact sets $(C_n)$ such that $C_n\subset (C_{n+1})^o$. The answer seems pretty simple when O is bounded, since $cl(O)$ will be compact, and I can construct the sequence…
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A property that implies completeness in metric spaces

Consider the following property in a metric space $(X,d)$: If $A,B$ are closed and disjoint, then $dist(A,B)>0$. Does this imply $(X,d)$ is complete? My guess is yes. I begin by considering a Cauchy sequence $(x_n)$ in $X$ that does not converge.…
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An uncountable family of coverings gives a countable subcovering

Let $A\subseteq \mathbb{R}^n$ and consider a family of open balls $(B(x_i,r_i))_i$ indexed on a set $I$ such that $$A\subseteq \cup_{i\in I}B(x_i,r_i)$$ Prove that there exists an (at most) countable subset $I*\subset I$ such that $$A\subseteq…
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Is there such a thing as the standard metric on $\mathbb{R}^N$?

I've recently seen the Heine–Borel theorem stated as "In $\mathbb{R}^N$ with the standard metric, a set $k$ is compact if and only if it is closed and bounded" however I've never heard of "the standard metric on $\mathbb{R}^N$". Is this simply a…
J. Min
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Suppose that (X, d) is complete and that A is a closed subset. Show A must be complete

Suppose that (X, d) is complete and that A is a closed subset. Show A must be complete. As a beginner with metric Spaces can someone help out with this? I know both the definitions of complete and closed but in applying them I struggle slightly so…
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If $(X,d)$ is a metric space, then $diam(U_R(a))=2R$?

Let $(X,d)$ be a metric space and $a\in X$. Does it hold that $diam(U_R(a))=2R$? Here $U_R(a):=\{x\in X : |x-a|
Marc
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A function $d:M\times M \rightarrow \mathbb R$ defines a metric under certain conditions

Let us consider the function on the set $M$ $$d:M\times M \rightarrow \mathbb R.$$ I want to show that it defines a metric space on $M$ if the following two conditions are hold: $d(x,y) =0 \iff x=y$ $d(x,y)\leq d(x,z)+d(y,z)$ So we need to prove…
Marc
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Show that for every compact subset $B$ of $X$ disjoint from $A$ $\mathrm{dist}(A,B)>0$.

Let$(X,d)$ be a metric space, $A$ nonempty, compact subset of $X$. Let $$\mathrm{dist}(A,B)=\inf_{\substack{a\in A\\b\in B}}d(a,b).$$ I want to show that for every compact subset $B$ of $X$ disjoint from $A$ $\mathrm{dist}(A,B)>0$. I tried to show…
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Is 'det' a metric space?

suppose d is a metric on space X. I want to know that is det which define as follow a metric space or not? $$det(x,y)=\frac{d(x,y)}{1+(d(x,y))^2}$$ hint: I know that $d^{\prime}(x.y)=\frac{d(x,y)}{1+d(x,y)}$ is a metric space
ebad
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Proving an integral is continuous in a metric space:

Prove that the function $I(f)=\int_{-1}^1 f(x)\, dx$ is continuous on the metric space: $(C([-1,1],\mathbb R), d)$, where $d(f,g) = \sup_{x \in [-1,1]}|f(x) - g(x)|$
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Prove that $\{x_n\} \rightarrow x $ iff every subsequence of $\{x_n\}$ has a subsequence converging to x.

Let $\big $ $\{x_n\} \rightarrow x \quad$ iff every subsequence of $\{x_n\}$ has a subsequence converging to $x\in X$. Note also the proposition: $\{x_n\} \rightarrow x\quad$ iff every subsequence of $\{x_n\} $ converges to $x\in X$ When…
Leyla Alkan
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