Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
5
votes
7 answers

Polynomial : $ P(x+1)-2P(x)+P(x-1)=6x $

Find all polynomials $P(x) \in \mathbb{R}[x]$ satisfying $$ P(x+1)-2P(x)+P(x-1)=6x $$ My attempt : Since $ P(x+1)+P(x-1)-2P(x)=6x $, so $P(x)$ is not constant polynomial. Let $P(x+1)-P(x)= Q(x)$ so $Q(x)-Q(x-1)=6x, \;\; \forall x \in \mathbb{R}$ by…
user403160
  • 3,286
5
votes
1 answer

Can we find the coefficients of $P(x)=a_4 x^4+a_3 x^3+a_2 x^2 +a_1 x +a_0$ by computing $P(100)$?

Can we find the coefficients of $P(x)=a_4 x^4+a_3 x^3+a_2 x^2 +a_1 x +a_0$ by computing $P(100)$? Example 1: Let $$P_1(x)=(x+1)(x+2)(x+3)(x+4).$$ Expanded form of $P_1(x)$ is $$P_1(x)= x^4 + 10 x^3 + 35 x^2 + 50 x + 24.$$ For $x=100$, we…
5
votes
2 answers

Why is polynomial convolution equivalent to multiplication in $F[x]/(x^n-1)$?

(Context: polynomial multiplication using DFT/FFT) Let $f = \sum\limits_{i=0}^{n-1} f_i x^i$ and $g = \sum\limits_{j=0}^{n-1} g_j x^j$ be polynomials in $F[x]$ for some field $F.$ The convolution of $f$ and $g$ is given by $$f \ast g =…
user2468
5
votes
4 answers

Prove that an expression is divisible by a polynomial

Question: Show that the polynomial $f(x)=(x+1)^{2n} +(x+2)^n - 1$ is divisible by $g(x) = x^2+3x+2$, where $n$ is an integer. I have tried to use mathematical induction. The basis case wasn't that difficult, but when it comes to the inductive step…
Artem
  • 1,208
5
votes
2 answers

Find the minimal $a+b$.

Let $x$ be real number such that $\frac{(1+x)^3}{1+x^3} = \frac{9}{13}$. If $\frac{(1+x)^5}{1+x^5} = \frac{a}{b}$ where $a, b$ are positive integers. What is the minimal value of $a+b$. My attempted work : $\frac{(1+x^3)(1+x)^2}{(1+x)^5} =…
user403160
  • 3,286
5
votes
1 answer

A generalisation of the fundamental theorem of algebra

We already know the following theorem by d'Alembert and Gauss, often called fundamental theorem of algebra. Theorem Let $P$ be in $\mathbb C[X]$ of degree $1$ or greater. There exists $\alpha\in \mathbb C$ such that $P(\alpha)=0$. Can we give the…
E. Joseph
  • 14,843
5
votes
1 answer

Prove a polynomial identity

Define a sequence of polynomials in the following way: $P_m(t)=\frac {1} {m!}\cdot t\cdot (t-1)\cdot...\cdot (t-m+1) $. (Where $P_0(t)=1$). I'm trying to prove the following identity: $\frac d {dt} P_{m+1}(t) = \sum_{k=0}^{m} \frac {(-1)^{m-k}}…
5
votes
2 answers

Prove $u\left( x\right)=W\left( x\right)+W'\left( x\right)+W''\left( x\right)+ \cdots \ge 0.$

Let $W\left( x\right) \ge 0$ for $x \in \mathbb{R}$ be a polynomial. Prove $$u\left( x\right)=W\left( x\right)+W'\left( x\right)+W''\left( x\right)+ \cdots \ge 0.$$ Is there a simple way?
piteer
  • 6,310
5
votes
2 answers

Let $a$ be a root of the cubic $x^3-21x+35=0$. Prove that $a^2+2a-14$ is a root of the cubic.

Let $a$ be a root of the cubic $x^3-21x+35=0$. Prove that $a^2+2a-14$ is a root of the cubic. My effort Working backwards I let $P(x)$ be a polynomial with roots $a,a^2+2a-14$ and $r$. Thus, $$P(x)=(x-a)(x-r)(x-(a^2+2a-14))$$ Expanding, I get…
Mr. Y
  • 2,637
5
votes
6 answers

Let $k$ be a positive integer. Find all polynomials with real coefficients which satisfy the equation $P(P(x))=\left(P(x)\right)^k$.

Let $k$ be a positive integer. Find all polynomials with real coefficients which satisfy the equation $$P(P(x))=\left(P(x)\right)^k.$$ I simply don't even know how to think about this problem. I've tried simple stuff just to get my head on the…
Mr. Y
  • 2,637
5
votes
2 answers

Real polynomials with $P(x^3-2)=P(x)^3-2$

Find all real polynomials $P(x)$ such that $P(x^3-2)=P(x)^3-2$. Clearly $P(x)=x$ works. If $P(x)=ax+b$ is linear, then $P(x^3-2)=ax^3-2a+b$ and $P(x)^3-2=a^3x^3+3a^2bx^2+3ab^2x+b^3-2$, so $ab=0$ and $a^3=a$ and $-2a+b=b^3-2$. If $b=0$, then the…
Alexi
  • 1,882
5
votes
5 answers

How to solve $x^6-x^5+x^4-x^3+x^2-x+1=0$?

Can anyone tell me how to solve this? $x^6-x^5+x^4-x^3+x^2-x+1=0$ What I got to was $x^7+1=0$. Thanks in advance.
5
votes
1 answer

How is a degree-$d$ polynomial uniquely characterized by its values at $d+1$ distinct points?

A degree-$d$ polynomial is uniquely characterized by its values at any $d+1$ distinct points. Could someone explain why the statement above is necessarily true?
user26649
5
votes
5 answers

How can this expression be simplified?

How do I factorize $$a^{2}(b-c)+b^{2}(c-a)+c^{2}(a-b)?$$ I've tried it in different ways but failed. Wish some one could help solving it out.
Raisa
  • 63
5
votes
4 answers

Proof of Different Polynomial Decompositions into Linear Factors

From G. Polya "Mathematics and Plausible Reasoning" p. 18. How do you prove that provided the roots of a polynomial are different from zero, $$a_0 + a_1x+a_2x^2 + ... + a_nx^n$$ $$\,=…