Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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When does polynomial equation have a double root?

I'm actually solving next task: We have an polynomial: $x^n-ax^{n-1}+bx-1$. And we need to find values of $a$ and $b$, such that we can divide polynomial by $(x-1)^2$ without remainder. I tried equating polinomial to $0$ and got $a=x$ and $b=1/x$.…
Roma
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Find the sum of the inverse roots of $x^3-7x^2+4x-1$

Calculate the sum of the inverse roots of the equation $x^3-7x^2+4x-1=0$. My development was: sum = $-7$ product = $1$ Thus, I believe that to find the inverse roots one only has to share the sum with the product, i.e. $-\frac{7}{1} = 7$, however,…
funfun
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Solving the trinomial

Consider the following trinomial equation \begin{equation} ax^n-x+1=0. \end{equation} If $a = \left(\frac{b^{n-1}-1}{b^n-1}\right)^{n-1}\left(1-\frac{b^{n-1}-1}{b^n-1}\right)$ for some $b\in\mathbb{R}$, then one can check that a solution to the…
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a set of pairwise commuting polynomials

The set $\{1,x,x^2,x^3,\dots\}$ has the following properties: any two of these polynomials commute for any $n\ge 0$ there is exactly one polynomial of degree $n$ inside Is this the only example? If not, is there a general form of such sets? I…
larry01
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Finding coefficients of a polynomial with minimal queries

Consider the following game, played between Alice and Bob: Alice chooses a polynomial $p(x) \in \mathbb{Z}[x]$, where the coefficients are all greater than or equal to $-1$. Bob's goal is to determine the polynomial; to this end he may ask Alice to…
Micapps
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How to show the polynomial $P= x^{10}+ax^9+bx^8+cx^7+x+1$ always has at least one non-real root?

I rephrase my question how can prove or disprove that the roots of polynomial $P= x^{10}+ax^9+bx^8+cx^7+x+1$ can't be all real any way we choose $a,b, c\in \mathbb{R}$.
user63181
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Real solution of $P(P(\cdots P(x))\cdots)=0$

Let $P(x)=x^2 +2013x+1$. Show that $P(P(\cdots P(x))\cdots)=0$ (i.e. $P$ is $n$-times nested) has at least one real root for any $n$ $P$. For $n = 1$ this is obvious. Next, for $n = 2$ we get a fourth order polynomial $$x^4 + 4,026 x^3 +…
Parzifal
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Is it true? $(1+ta_1)(1+ta_2)\cdots(1+ta_n)=1, \;\forall t\in{\Bbb R}$ ⟺ $a_1=a_2=...=a_n=0$

$(1+ta_1)(1+ta_2)...(1+ta_n)=1$ $\forall t\in R$ if and only if $a_1=a_2=...=a_n=0$ Is it true? If yes, how to prove it? I already gave a proof when $n=3$. $1=(1+ta_1)(1+ta_2)(1+ta_3)=1+(a_1+a_2+a_3)t+(a_1a_2+a_1a_3+a_2a_3)t^2+(a_1a_2a_3)t^3$ It is…
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If $f: \mathbb{R}^2 \to \mathbb{R}$ is polynomial in each argument, $f$ is polynomial

Given $f: \mathbb{R}^2 \to \mathbb{R}$ such that for all real $y$, $t \mapsto f(t,y)$ is a polynomial function and for all real $x$, $t \mapsto f(x,t)$ is a polynomial function, is it necessarily true that $(x,y) \mapsto f(x,y)$ is a polynomial…
math_lover
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Showing that $P(x)$, where $P(x) = P(x+2)-x^2-2$ for all $x$, is a third-degree polynomial

I want to show that $P(x)$ is a third degree polymomial: $P(x) = P(x+2) -x^2-2$ for every real $x$ It is not so difficult, but I am not seeing the proof straight away.
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A special kind of polynomial: $p(x)=x^{2}(4x^{2}-3)^2$

Coonsider the polynomial $p(x) = x^2(4x^2-3)^2$. This polynomial is special because: All of the local maxima $M_i$ are of the form $p(M_i)=1$ All of the local minima $m_i$ are of the form $p(m_i)=0$ and $p(-1)=p(1)=1$ The polynomial has no other…
Neves
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How to simplify polynomials

I can't figure out how to simplify this polynominal $$5x^2+3x^4-7x^3+5x+8+2x^2-4x+9-6x^2+7x$$ I tried combining like…
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Show that the polynomial $x^8 -x^7+x^2-x+15$ has no real root

I am not getting on how to approach this problem. Clearly, this polynomial can have atleast 2 real roots. And using Descartes's rule of signs, it can have a maximum of 4 positive real roots. But after that, how should I proceed ? Any help would be…
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How to prove $f(x^n)$ is divisible by $x^n-1$

The question states that if $f (x)$ is a polynomial such that $x-1|f(x^n)$ prove that $f(x^n)$ is divisible by $x^n-1$ This is how I proceeded since$x-1|f(x^n)$ $f(1)=0$ $\frac {f (x^n)-f(1)}{x^n-1}=g(x)$ since $f(1)=0$…
Pulsar
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Polynomial : $P(a)P(a^2)P(a^3)P(a^4)$

Let $P(x) = x^3 + 2x^2+3x+4$ and $a$ be the root of equation $x^4+x^3+x^2+x+1=0$. Find the value of $P(a)P(a^2)P(a^3)P(a^4)$ Is my answer correct ? Since root of equation $x^4+x^3+x^2+x+1=0$ is the $5^{th}$ primitive root of 1, so $a, a^2, a^3, a^4$…
user403160
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