Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Barbeau's Polynomials, Exploration 2

I'm reading Barbeau's Polynomials. Let $m$ be a positive integer. It is a remarkable fact that the numbers from $1$ to $2^{m+1}$ inclusive can be subdivided into two subsets $A$ and $B$ such that, for any polynomial $p(t)$ of degree not exceeding…
Red Banana
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Monic polynomials with integer coefficients

We have $\Pi_{j=1}^n (z-z_j)$ a polynomial with integer coefficients. Is also $\Pi_{j=1}^n (z-z_j^k)$ for k=1,2,3,... a polynomial with integer coefficients?
Marko
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Using Legendre polynomial to approximate any polynomial

How can I show that any polynomial can be approximated by using linear combination of Legendre polynomial?
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proof that at least one solution exist

let us consider following problem: i can take $n=1,2,...$ and try to understand basic relationship between this linear relation and relevant polynomial,for example 1.$n=1--> we have $a_0=0$ 2.$n=2$ we will…
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Find all polynomials P such that $P(x) | P(x^2)$

If $x$ is the root of $P$, then $x^2$ is also the root. Now spamming this we get that $x^{2^k}$ is eventually $1$ for fixed root $x$ (and some positive integer k, of course assuming that $x \ne 0$). But thats where i got stuck.
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Prove that the polynomial $f(x)=P\left(x\right)+P'\left(x\right)+...+P^{(n+1)}\left(x\right)$ has no real roots

Let $P(x)$ be a polynomial of degree $n$ and $P(x) \geq 0$ then prove that the polynomial $f(x)=P\left(x\right)+P'\left(x\right)+...+P^{(n+1)}\left(x\right)$ has no real roots. [$P^{(k)}(x)$ means the $k^{\text{th}}$ derivative of $P(x)$] $P(x)$…
zaemon_23
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Polynomial division over not a field

I am trying to understand the following example that shows that the polynomial division theorem doesn't hold when the coefficients aren't from a field $F$. So the statement is that it $F$ isn't a field (let's say it's a ring as it is in the…
SAQ
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Prove that $a\leq 4$ if $0\leq ax^4 + bx^2+c\leq 1$ in the interval $[0,1]$

Consider a real polynomial of the form $p(x) = ax^4 + bx^2+c$. We are given that $0\leq p(x)\leq 1$ in the interval $[0,1]$. Show that $a\leq 4$ Take $x^2=y$. So $p(x)=q(y)$We assumes $a>0$. Now we consider two cases: $x$ such that $q'(x)=0$…
Yoda_2008
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Find the remainder when $x^n - a^n$ is divided by $x^2-a^2$, when a) $n$ is odd

Question: Find the remainder when $x^n - a^n$ is divided by $x^2-a^2$, where $n$ is odd. I am not sure if my process is correct: As the divisor is a quadratic, the remainder should be linear or constant. $P(-a) = -a^n-a^n = -Aa+B = -2a^n$ $P(a) =…
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Dividing polynomials with coefficients

Let $\;f(t)=\left(t^{pq}-1\right)\left(t-1\right)\;$ and $\;g(t)=\left(t^p-1\right)\left(t^q-1\right)\;$ where $p$ and $q$ are relatively prime positive integers. Prove that $\dfrac{f(t)}{g(t)}$ can be written as a polynomial where it has just $1$…
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Real Roots to a System of Equations

Prove the cubic $$ x^3 - \frac{a+a^2+a^4+b+b^2+b^4}2 x^2 + \frac{a^3+a^5+a^6+b^3+b^5+b^6}2 x - \frac{a^7+b^7}2 $$ has all real roots given that $0 < \sqrt a \leq b \leq a^2$. I don't see how you would do this cleanly, my only thoughts were using…
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Proving that product of roots does not exceed $\frac{1}{2^n}$ if $|f(0)| = f(1)$ and the roots lie between 0 to 1.

Problem: Let $a_0, a_1, \ldots, a_{n-1}$ be real numbers where $n \geq 1$ and let $f(x) = x^n + a_{n-1} x^{n-1} + a_{n-2} x^{n-2} + \ldots + a_0$ be such that $|f(0)| = f(1)$ and each root of $f(x) = 0$ is real and lies between $0$ to $1$. Prove…
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Can I express $x(x-1)\ldots(x-34)$ as $p(q(x))$ where $p$, $q$ are polynomials of degree 5 and 7?

To give an easier example, $x(x-1)(x-2)(x-3)$ can be written as $x(x-3) \cdot (x(x-3) + 2)) = q(x)(q(x)+2)$ where $q(x) = x(x-3)$. In other words, we can write this degree-4 polynomial as $p(q(x))$ where $p$, $q$ are degree-2 polynomials. Note that…
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$P(x^2+1)=P(x)Q(x)$ implies $P(x)$ is of even degree

The question is to prove that the polynomial $P(x)$ is of even degree if there exists a polynomial $Q(x)$ such that $P(x^2+1) = P(x)Q(x) $. This was an interview question. It is easy to show that $P(x)$ can't be linear and that the degree of $P(x)$…
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An interesting algebra problem from South Korea Olympiad 1994 problem 6

Let $a$, $b$ be integers and $p$ be a prime number such that: $p$ is greatest common divisor of $a$, b $p^2$ divides a. Prove that the polynomial $x^{n+2}+ax^{n+1}+bx^n+a+b$ cannot be decomposed into the product of two polynomials with integer…
Snell
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