Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Why $f^2$ cannot divide $x^n - 1$ check

So I am trying to show that $f^2,$ a non constant polynomial, cannot divide $x^n - 1.$ Suppose it did. Then $x^n - 1 = f^2g.$ The derivative of $x^n - 1$ is $nx^{n - 1} = 2ff'g + f^2g'.$ Clearly, $f^2$ and $2ff'g + f^2g$ share a factor of $f.$…
green frog
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Asymptotes and Polynomials

Problem: Let $$f(x) = 3\frac{x^4+x^3+x^2+1}{x^2+x-2}.$$Give a polynomial $g(x)$ so that $f(x) + g(x)$ has a horizontal asymptote of $0$ as $x$ approaches positive infinity. How would I start this? I found the partial fractions expansion of this,…
JenkinsMa
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What allows synthetic division to work?

I just learned synthetic division of polynomials and was wondering what allows it to work? Why does it work?N An example of a problem would be $(4b^3+27b^2-15b-52)/(b+7)$ You write the -7 in the corner, line up the coefficients Drop down the first…
JonnyBoi
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Rational points on quadratic curves

I guess this question might be very difficult, so I would only like to know what is known about it. Given a quadratic polynomial $P$ in two variables with degree $2$ and integer coefficients. Assume $P = 0$ has real solutions. Does this imply that…
Till
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Find coefficients of $x^{2012}$ in $(x+1)(x^2+2)(x^4+4)\cdots (x^{1024}+1024)$

Find coefficients of $x^{2012}$ in $(x+1)(x^2+2)(x^4+4)\cdots (x^{1024}+1024)$ Attempt: i have break $2012$ in to sum of power of $2$ as $2012 = 2^{10}+2^{9}+2^{8}+2^7+2^6+2^4+2^3+2^2$ but wan,t be able to go further, could some help me , thanks
DXT
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$P(x)$ with coefficient $\pm1$

Find all polynomial $P(x)$ with coefficient $\pm1$ and have all real roots. My attempted work : Let $P(x) = a_nx^n + a_{n-1}x^{n-1} + ... + a_1x + a_0$ $-P(x) = -a_nx^n - a_{n-1}x^{n-1} - ... - a_1x - a_0$ $P(x)$ have all real roots…
user403160
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Number of Terms in Polynomial

The number of terms in a polynomial expansion can be found here But what about in number of terms for polynomial expansion in Galois Field (or characteristic of 2, where addition is addition mod 2 or Xor)
crypt
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irreducible polynomial of degree 2 or 3 without roots in an integral domain.

It is well-known that a degree 2 or 3 polynomial over a field is reducible if and only if it has a root. But what about integral domains? Can we have a reducible polynomial over an integral domain having no roots in the domain?
Reader
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Analytic solution for a quartic polynomial

I'm trying to use a generic solution with an analytic method for quartic polynomials. I am only interested in finding the real roots. Based on the solutions given by Wolfram|Alpha, and since the formula given in a previous question was apparently…
ValV
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If the polynomial $x^4-6x^3+16x^2-25x+10$ is divided by another polynomial $x^2-2x+k$, the

If the polynomial $x^4-6x^3+16x^2-25x+10$ is divided by another polynomial $x^2-2x+k$, theremainder is $x+a$, find $k$ and $a$. My Attempt, $f(x)=x^4-6x^3+16x^2-25x+10$ $g(x)=x^2-2x+k$ $R=x+a$ Here, the divisor is in the quadratic form. so how do I …
pi-π
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Polynomials $p(x)$ and $q(x)$ such that $p(x) \cdot (x + 2) + q(x) \cdot (2x + 1) = 1$

Is there a pair of polynomials $p(x)$ and $q(x)$, each with integer coefficients, such that $p(x) \cdot (x + 2) + q(x) \cdot (2x + 1) = 1$ for every real number $x$?
Thomas
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Is there a polynomial with integral coefficients satisfying 2 conditions?

Is there a polynomial $P(x)$ with integral coefficients s.t. $P(1+\sqrt[3]{2})=1+\sqrt[3]{2}$ and $P(1+\sqrt{5})=2+3\sqrt{5}$. I'm not good at this kind of problem, all I did up to now is just assuming $deg P=3,4,5$ and if I'm not wrong, $degP…
user391671
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Prove $\cos{\frac{\pi}{n}}\notin\mathbb Q$ for any postive integer $n\ge 4$

Let $n\ge 4$ postive integer,show that $$\cos{\dfrac{\pi}{n}}\notin\mathbb Q$$ Now I have solve for a case: Assmue that $$\cos{\dfrac{\pi}{n}}=\dfrac{q}{p},(p,q)=1,p,q\in N^{+}$$ use Chebyshev polynomials? $$T_{n}(\cos{x})=\cos{(nx)}$$ so we…
math110
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if $xP(x)=x^t+P(x-1)$ find the $t\equiv ?\pmod 3$

Let polynomials $P(x)\in Z[x]$,and such $\deg{(P(x))}=t-1$,and such for any real $x$ have $$xP(x)=x^t+P(x-1)$$ Find the $t\equiv ?\pmod 3$? I try Let $P(x)=x^{t-1}+a_{t-2}x^{t-2}+\cdots+a_{1}x+a_{0}$ where $a_{i}\in Z$ so we…
math110
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Show that $ f(x)=x^{1000}-x^{500}+x^{100}+x+1=0 $ has no rational roots.

Show that $ f(x)=x^{1000}-x^{500}+x^{100}+x+1=0 $ has no rational roots.