Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

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Comparing coefficients to find the other roots of a polynomial?

Suppose I am given that $(x - \alpha)$ is a factor of $p(x) = a_0x^n + a_1x^{n-1} + .... a_n$ That obviously means $(x - \alpha)$ is a factor of $p(x)$ i.e $p(x) = (x - \alpha)q(x)$. My question is, if I want to find $q(x)$, and therefore the other…
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When I was said to factorize a polynomial in school what did I actually told to perform?

In school we spend several hours factorizing polynomials. But now as I've started gainnning some knowledge on polynomial rings, it suddenly occurred to me that none of the books I practiced then, suggested the factorized form of the polynomial…
Sriti Mallick
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Is $ \frac{x^2 -4}{x-2} $ a polynomial?

The expression $ \frac{x^2 -4}{x-2}$ doesn’t looks like a polynomial because of $ x $ in the denominator. But it can be factorized. After factorizing and canceling the common factor $$\frac{x^2 -4}{x-2} = \frac{(x+2)(x-2)}{x-2} = x+2, $$ and $ x+2 $…
a_uti
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Generalization of real roots for a polynomial of $n$ degree.

Is there any specific condition on the coefficients of a polynomial of $n$ degree, so that all roots are real ? I know that there is a condition on quadratic polynomials : $p(x) = ax^2+bx+c$, for both the roots to be real, $b^2-4ac\ge0$.
arnav_de
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proof about an polynomial proposition.

Welcome to edit my post to revise any mistakes, especially English, thanks. Proposition Assuming $f(x),g(x)$ are integer polynomials, and $g(x)$ is primitive. If $f(x)=g(x)h(x)$, where $h(x)$ is rational polynomial, then $h(x)$ must be polynomial…
HyperGroups
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Proof reading of one college-Algebra-polynomial-thereom.

Welcome to edit my post to revise any mistakes, especially English, thanks. Theorem 11: If an nozero integer polynomial $f(x)$ can be factored as a product of two rational polynomials and less degree, then it can be factored as a product of two…
HyperGroups
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what are the steps to get this answer?

If $\frac ab+\frac ba=1$, and if "a" and "b" are not equal to zero then what would be the value of $a^3-b^3$? It would be helpful if the answer is given in the form of steps leading to the value.
user426
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Let $p(x)$ be a monic $2003$ degree integer polynomial. Let $q(x) = (p(x))^2 - 25$. Prove at most $2003$ distinct integers $m$, ST $q(m) = 0$

Let $p(x)$ be a monic $2003$ degree integer polynomial. Let $q(x) = (p(x))^2 - 25$. Prove that there are not more than $2003$ distinct integers $m$, Such That $q(m) = 0$ To prove this, I assumed the contrary, and then factorised $q(x) =…
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Show that if $\forall x \in [0,1], P(x) \ge 0$ therefore $\exists A,B,C,D \in \Bbb R[X], P=A^2+XB^2+(1-X)C^2+X(1-X)D^2$.

Let $P \in \Bbb R[X]$. Show that if $\forall x \in [0,1], P(x) \ge 0$ therefore $\exists A,B,C,D \in \Bbb R[X], P=A^2+XB^2+(1-X)C^2+X(1-X)D^2$. I showed that this is true for $\deg P=2$ but I don't see how to generalize my proof. I tried to…
Michelle
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Elemental proof of Newton Girard identities

I've been trying to prove the Newton identity: $N_k(X) -s_1(X)N_k(X)+ s_2(X)N_{k-2}(X) + \dots + (-1)^{k}ks_k(X) = 0$. Where $N_k$ are the newton sums in $n$ variables and $s_k$ the elemental symetric polynomial. I've found diferent proofs using…
Johanna
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$\prod_{i=1}^n[(N-x_i)!]=\prod_{i=1}^n[(N-y_i)!]$ for all $N\in\mathbb{Z}^+$ implies $x_{(i)}=y_{(i)}$, for all $i\in\{1,\cdots,n\}$

Suppose $$\prod_{i=1}^n[(N-x_i)!]=\prod_{i=1}^n[(N-y_i)!]$$ for all $N\in\mathbb{Z}^+$. Why does it imply $x_{(i)}=y_{(i)}$, for all $i\in\{1,\cdots,n\}$? Here $X_{(i)}$ is the order statistic. I am trying to find a minimal sufficient statistic for…
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Dividing $x^{81}+x^{48}+2x^{27}+x^{6}+3$ by $x^{3}+1$

Letting $f(x)=x^{81}+x^{48}+2x^{27}+x^{6}+3$, and we seek to divide $f(x)$ by $x^{3}+1$, or just any $x^3-a$. Is subbing $y=x^3$ allowed in this kind of division? I've experimented doing so and so far it seems correct.
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$f(x) = x^{2015}+2x^{2014}+3x^{2013}+...+2015x+2016$

(From OMITS Indonesian $2015$) Known that $f(x) = x^{2015}+2x^{2014}+3x^{2013}+...+2015x+2016$, if $x_1, x_2, x_3,..., x_{2015}$ is the roots of $f(x)$, Find : $\sum_{n=0}^{2014}$ $\sum_{k=1}^{2015}$ $(x_k)^n$ $a. -2016$ $b. -2015$ $c. -2014$ $d.…
Newbie000
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Let $P(x) = x^3 - 5 x^2 + 7 x + k = 0$. If P(x) has a double root in the set of integers, find the value of k using Vieta's Formulas.

I managed to derive Vieta's Formulas intuitively to find the values for each coefficient of $n$ degree of $x$ but didn't have success in finding the value of $k$. I figured out it was simultaneous equations however still couldn't find the value of…
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Solve the roots of a cubic polynomial?

I have had trouble with this question - mainly due to the fact that I do not fully understand what a 'geometric progression' is: "Solve the equation $x^3 - 14x^2 + 56x - 64 = 0$" if the roots are in geometric progression. Any help would be…
missiledragon
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