Questions tagged [polynomials]

For both basic and advanced questions on polynomials in any number of variables, including, but not limited to solving for roots, factoring, and checking for irreducibility.

Usually, polynomials are introduced as expressions of the form $\sum_{i=0}^dc_ix^i$ such as $15x^3 - 14x^2 + 8$. Here, the numbers are called coefficients, the $x$'s are the variables or indeterminates of the polynomial, and $d$ is known as the degree of the polynomial. In general the coefficients may be taken from any ring $R$ and any finite number of variables is allowed. The set of all polynomials in $n$ variables $X_1,\ldots,X_n$ over a ring $R$ is denoted by $R[X_1,\ldots,X_n]$. Strictly speaking this is a formal sum, because the variables do not represent any value. Nevertheless, the variables of a polynomial obey the usual arithmetic laws in a ring (like commutativity and distributivity). This makes $R[X_1,\ldots,X_n]$ a ring itself. One should note that $R[X_1][X_2]=R[X_1,X_2]$. This idea can be extended to $R[X_1,\ldots,X_n]$ in a very natural way.

An expression of the form $rX_1^{i_1}X_2^{i_2}\cdots X_n^{i_n}$ ($r\in R$) is called a term (of the polynomial). Polynomials are defined to have only finitely many terms. An expression with infinitely many different terms is generally not considered to be a polynomial, but a (formal) power series in one or more variables.

When $P\in R[X]$, $P(x)$ is the evaluation of $P$ at $x$ (pronounced $P$ of $x$, or simply $Px$). Here $x$ does not necessarily have to be an element of $R$. For $P(x)$ to be properly defined for an $x$ in some ring $S$ we need:

  • a homomorphism $\phi:R\to S$
  • the image of all coefficients of $P$ under $\phi$ should commute with $x$.

Evaluation is now simply performed by replacing all coefficients $r_i$ of $P$ by $\phi(r_i)$ and all appearances of $X$ by $x$. This quite naturally gives an expression that is well defined as an element of $S$. The concept of evaluation is naturally extended to $R[X_1,\ldots,X_n]$.

26755 questions
1
vote
2 answers

An easier way of solving a problem about the number of roots of a square equation on an interval

I am trying to solve the following problem: I need to find out the number of roots on the interval $[-1; 3)$ of the equation $(4-a)x^2-6ax+3=0$ depending from $a$. I know a solution, but it is too difficult to calculate. I thought I could solve that…
student28
  • 385
1
vote
1 answer

Proof F[x] is integral domain

Given $F$ is integral domain, prove $F[X]$ is integral domain Need to prove:(I did not use the condition: $F$ is integral domain) Proof: $f(x)g(x) = 0 \Leftrightarrow f(x) = 0 \text{ or } g(x) = 0 $ Here is my proof, can anyone check whether it…
Aron Lee
  • 123
1
vote
1 answer

do you recognize this polynomial with double factorials?

I've got a polynomial (which comes from solutions of the heat conduction PDE) which seems so simple I'm wondering if anyone recognizes it $$f_{m}=x^{m-1} +(m-1)x^{m-3}+(m-1)(m-3)x^{m-5} +(m-1)(m-3)(m-5)x^{m-7} +\cdots$$ where the sum terminates when…
j.jonah
  • 19
1
vote
2 answers

Tricky question on polynomials

For any real numbers $x$ and $y$ satisfying $x^2y + 6y = xy^3 +5x^2 +2x$, it is known that $$(x^2 + 2xy + 3y^2) \, f(x,y) = (4x^2 + 5xy + 6y^2) \, g(x,y)$$ Given that $g(0,0) = 6$, find the value of $f(0,0)$. I have tried expressing $f(x,y)$ in…
1
vote
2 answers

How do I solve the polynomial exercise?

Let $f\in\ \mathbb{R}[x]$ be a polynomial with the property that $f(x^2+3x+1)=f^2(x)+3f(x)+1$ and $f(0)=0$. Show that $f=x$. I tried for $x=-1 => f(-1)=-1$ and for $x=1=>f(1)=1$, but I do not have any idea how to prove for the general case. I think…
Ghost
  • 1,105
1
vote
0 answers

If a homogeneous multivariate polynomial is zero at all points, is it necessarily the zero polynomial?

A very stupid question: If a homogeneous polynomial $P(x_1,\cdots,x_k)=0$ for all $x \in \mathbb{R}^k$ then does that mean it is the zero polynomial? (I have proven this using induction but I suspect this is something rather trivial and perhaps…
Canine360
  • 1,481
1
vote
0 answers

Decomposition of polynomial into polynomials with non-negative coefficients

Let $f(x)$ be a polynomial with degree $> 1$. If $f(x^n)$ can be decomposed as $q_1(x)q_2(x)$, $q_1$ and $q_2$ non-constant polynomials with non-negative coefficients, then prove that there exists $p_1(x)$ e $p_2(x)$ non-constant polynomials with…
1
vote
1 answer

If $\frac 1{a+b+c}= \frac 1a+ \frac 1b+ \frac 1c$, then show for odd $n$, $ \frac 1{a^n+b^n+c^n}= \frac 1{a^n}+ \frac 1{b^n}+ \frac 1{c^n}$

The stated duplicate question does not address solution in terms of $p, q, r,$ i.e. not in terms of the Viete's formula. My approach is based on the viete's formula by finding the relation between the coefficients of a polynomial to sums and…
jiten
  • 4,524
1
vote
2 answers

Cyclotomic polynomials and products of cosines problem

I've run into an inconsistency I can't figure out while trying to find products of the cosine of various roots of unity. For example: $\cos(\frac{2\pi}{5})\cdot cos(\frac{4\pi}{5}) \cdot cos(\frac{6\pi}{5}) \cdot cos(\frac{10\pi}{5})$ Multiply…
benleis
  • 123
1
vote
2 answers

Understanding partial fraction decomposition

I don't understand why there are constant $A,B,C$ s.t. $$\frac{1}{(x-1)(x-2)^2}=\frac{A}{(x-1)}+\frac{B}{(x-2)}+\frac{C}{(x-2)^2}.$$ I now how to compute $A,B,C$, but I don't understand how someone though to do this. In what this is natural ?
user330587
  • 1,624
1
vote
1 answer

Square of a polynomial

Find a polynomial with more than one nonzero term such that its square has exactly same number of terms as the original polynomial. Attempts-I tried to use variables for the polynomial and equate some to $0$. I also found that it is not possible for…
Brilli
  • 51
1
vote
1 answer

How to find and characterise critical points of a polynomial?

Find and characterise the critical points of: $f(x)=(2x^3-12x^2+18x-1)^5$ I differentiated to get: $$\frac{df}{dx}=5(6x^2-24x+18)(2x^3-12x^2+18x-1)^4=30(x-3)(x-1)(2x^3-12x^2+18x-1)^4$$ But don't know how to factorise this further?
Fred
  • 11
1
vote
0 answers

Logical significance of Hudde's substitution in solution of general cubic equation

This is in continuance to my earlier post : Deriving expression for general cubic equation solution. Also, the links are repeated for the first four pages of the book by Dickson, titled "Introduction to Theory of Algebraic Equations" are given as :…
jiten
  • 4,524
1
vote
1 answer

Issue in the solution of general cubic equation.

This is in continuance to my earlier post : Deriving expression for general cubic equation solution. Also, the links are repeated for the first four pages of the book by Dickson, titled "Introduction to Theory of Algebraic Equations" are given as :…
jiten
  • 4,524
1
vote
1 answer

Solution to general cubic equation

This is in continuance to my earlier post : Deriving expression for general cubic equation solution. Also, the links are repeated for the first four pages of the book by Dickson, titled "Introduction to Theory of Algebraic Equations" are given as :…
jiten
  • 4,524