Questions tagged [power-series]

Questions about the properties of functions of the form $\sum_{n=0}^{\infty}a_n (x-c)^n$, where the $a_n$ are real or complex numbers, and $x$ is real or complex.

A series of the form $$\sum_{n=0}^{\infty} a_n (x-c)^n$$ is called a power series, and can be used to expand functions. The center $c$ is often $0$ and the radius of convergence $R$ is given by $R = \left(\limsup\limits_{n\to\infty}\sqrt[n]{|a_n|}\right)^{-1}$.

Power series for some common functions are: \begin{align} \frac{1}{1-x}&=\sum_{n=0}^\infty x^n\quad(|x|\lt1)\\\ \ln(1+x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{n+1}}{n+1}\quad(|x|\leq 1, x\neq -1)\\\ \arctan(x)&=\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{2n+1}\quad(|x|\leq 1,x\neq \pm i)\\\ \tan(x)&=\sum_{n=1}^{\infty}\frac{|B_{2n}|(4^n-1)4^n }{(2n)!}x^{2n-1}\quad(|x|< \pi/2)\\\ \sin(x)&=\sum_{n=0}^\infty\frac{(-1)^n x^{2n+1}}{(2n+1)!}\\\ \cos(x)&=\sum_{n=0}^\infty \frac{(-1)^n x^{2n}}{(2n)!}\\\ e^x &= \sum_{n=0}^\infty\frac{x^n}{n!}\\\ \end{align}

If convergence is not an issue or if you are working over a different domain than $\mathbb{R}$ or $\mathbb{C}$, consider using the tag instead.

8489 questions
3
votes
2 answers

How to represent $\ln(5-x)$ as a power series?

I know that $$ \ln(1+x)=\sum _{n=1}^{\infty }\:\left(-1\right)^{n-1}\frac{x^{n}}{n} $$
DDDD
  • 563
  • 2
  • 6
  • 18
3
votes
3 answers

Finding power series of function

could anyone help me answer question? $$F(x)=\ln\left(\dfrac{7+x}{7-x}\right)$$ Find a power series representation for the function.
yswong
  • 41
3
votes
3 answers

Inverse in noncommutative power series ring

Let $k$ be a field and let $X_1, X_2, \ldots , X_n$ be formal noncommuting variables and let $K\langle \langle X_1, X_2, \ldots , X_n\rangle \rangle $ be the formal noncommutative power series ring in these variables. Suppose $F$ is a power series…
Valeriya
  • 265
3
votes
5 answers

Power series $\sum n^3a_nz^n$

If $f(z)=\sum a_nz^n$, what is $\sum n^3a_nz^n$? The desired sum is $a_1z+8a_2z^2+27a_3z^3+\cdots$. I can't see how to write the desired sum in terms of $f$. For example, I could substitute $kz$ for $z$ to get $f(kz)=\sum k^na_nz^n$, but that…
PJ Miller
  • 8,193
3
votes
2 answers

Is there an explicit formula for power series of $\left(\frac{1+x}{1-x}\right)^n$?

I am trying to answer this question. Per suggestion in one the comments for that question, one might be able use the power series of the terms to arrive at the answer. However, one of the terms is: $$\left(\frac{1+x}{1-x}\right)^n$$ I am wondering…
M.B.M.
  • 5,406
3
votes
0 answers

Changing the power series of sin(x), and its waves are getting bigger. How big do they get?

Motivation: I've been thinking about the transformation of power series, which takes the (power series of) $\exp(x)$ to $\sin(x)$. At first i was trying the series $\sum_{n=0}^{\infty} \frac{x^n}{n^n}$. Since for positive $x$ this function is…
3
votes
2 answers

Power series of $\frac{x^{3}-2}{x^{2}+1}$

I have to find the power series of the function $$f(x)=\frac{x^3-2}{x^{2}+1}$$ centered at $a=1$. I tried to write $f$ as $$f(x)=(x^3-2)\cdot\frac{1}{x^{2}+1}$$ and then, find the power series of $\displaystyle\frac{1}{x^{2}+1}$ centered at $a=1$. I…
mvfs314
  • 2,017
  • 15
  • 19
3
votes
2 answers

Is $\sum_{n=0}^\infty \frac{(x^2-5)^n}{2^n}$ a power series?

The series $\sum_{n=0}^\infty \frac{(x^2-5)^n}{2^n}$ can be expressed as the following geometric series: $$\sum_{n=0}^\infty \left(\frac{x^2-5}{2}\right)^n.$$ This series should converge if $$\left|\frac{x^2-5}{2}\right|<1.$$ This gives the…
3
votes
2 answers

Which expression about power series is correct?

I found something weird about power series. In my textbook, $$ \frac{1}{1-x} = 1+x+x^2+x^3+\cdots=\sum_{n=0}^\infty x^n \quad |x|<1 $$ and $ \frac{1}{2+x} $ could be expressed using above equation. $$ \frac{1}{2+x} = \frac{1}{2 \left(1 +…
JehunYoo
  • 131
3
votes
1 answer

Can radius of convergence of conditionally convergent series be less than absolute convergence radius?

Is the radius of convergence of a conditionally convergent series always equal to the radius where it converges absolutely? For example, the power series: $$ \sum_1^{\infty} (-1)^{n+1}\frac{2^n x^n}{n 3^n} $$ is absolutely convergent when…
Dominic
  • 440
3
votes
1 answer

$f(x) = \frac{1}{\cos(x)}$ can be expanded as a power series. What is the radius of convergence?

This question is off an exam I took. Naturally I set out to first to create a Maclaurin power series. $f(x) = \frac{1}{\cos(x)}$ $\qquad \quad \quad \quad \quad f(0)= 1$ $f'(x)= \frac{\sin(x)}{\cos^2(x)}$ $\quad \quad \quad \quad \quad f'(0)=…
stack ex
  • 350
3
votes
2 answers

Difficulty in finding interval of convergence with power series

I have the following power series: $$\sum_{n=1}^\infty \frac{(4x+1)^{n}}{n} $$ When finding the interval of convergence, I am left with the following inequality: $$ |4x+1|\lt1 $$ How do I go about finding the values of $x$ for which this series…
melm
  • 315
3
votes
3 answers

Is this sine series bounded?

Let $$f(x)=\sum_{k=1}^{\infty}\sin\left(\frac{x}{2^k}\right)$$ Is $f(x)$ bounded? EDIT: I'm asking if there is $M \in R$ (M constant), s.t. $\forall x $ $|f(x)|
zxc
  • 405
  • 2
  • 9
3
votes
4 answers

Power series with alternating signs and its zeros.

This may be a strange question, but I've not found anything about this. Well, anyone can observe that both $$ \cos(z)=\sum_{n=0}^{\infty}\frac{(-1)^{n}}{(2n)!}z^{2n} $$ and $$ \sin(z)=\sum_{n=0}^{\infty}\frac{(-1)^{n}}{(2n+1)!}z^{2n+1} $$ are…
Neves
  • 5,617
3
votes
1 answer

Power series representation of $f(x) :=$ $1 \over {1 + 4x^2}$

Let $f:$ ($-1 \over 2$, $1 \over 2$) $\rightarrow \Bbb R$, $f(x) :=$ $1 \over {1 + 4x^2}$ be a function. I am searching for a power series representation of this function. I solved this the following way: We know that $1 \over {1 - x}$ $=…