Questions tagged [pythagorean-triples]

Questions about Pythagorean triples, positive integer solutions to $a^2 + b^2 = c^2$.

Pythagoras' Theorem states that in any right angle triangle, the length of the hypotenuse squared is equal to the sum of the squares of the lengths of the two shorter sides. If we denote the side lengths of a right angle triangle by $a$, $b$, and $c$, where $c$ is the length of the hypotenuse, then we can restate Pythagoras' Theorem as $a^2 + b^2 = c^2$.

A Pythagorean triple is a triple of positive integers $(a, b, c)$ such that $a^2 + b^2 = c^2$. For any such triple, there is a right angle triangle with side lengths $a$, $b$, and $c$. A Pythagorean triple is called primitive if $\gcd(a,b,c)=1$. There are infinitely many primitive Pythagorean triples: $(3,4,5)$, $(5,12,13)$, $(8,15,17)$, and so on.

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How can you find a Pythagorean triple with $a^2+b^2=c^2$ and $a/b$ close to $5/7$?

How can you find a Pythagorean triple with $a^2+b^2=c^2$ and $a/b$ close to $5/7$? I've been reading the Plimpton 322 news, and this fits in the gap in the Babylonian table between 0.6996 ($a=1679,b=2400$) and 0.75 ($a=3,b=4$). The Babylonians…
user210229
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Is there an existing theory of Pythagorean triples for numbers of the form $p+q\sqrt r$ rather than integers?

Before Christmas I was teaching a class about surds. They were able to simplify, add, multiply etc. To give them one application of this, I wanted to give them some triangles that they would have to identify as right-angled or not. I wanted to avoid…
tomi
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Given two pythagorean triples, generate another

I don't know if this has been asked before, but I could not find any existing answer. I noticed that for any pair of primitive pythagorean triples (not necessarily distinct), let's say: a² + b² = c² d² + e² = f² Then there is at least another…
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What is my mistake in finding this pythagorean triplet?

Since Project Euler copyright license requires that you attribute the problem to them, I'd like to add that this is about question 9 there. I am trying to solve this problem on only two brain cells and can't figure out what am I doing wrong. Here is…
scribe
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pythagorean triples Pair (Adjacent)

Is there exists two pythagorean triples $(a,b,c)$ and $(b,c,d)$ such that $a < d$ ? Any idea to prove or disprove ?
Kevin
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Is this theorem Correct.

If it is, is it trivial? **Theorem** There does not exist a pythagorean triple $a^2 + b^2 = c^2$ $\{a,b,c \in \Bbb N\}$ where $b \ge a$ and $a|b$ …
Tobi Alafin
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Prove that if a rectangle's sides are all odd, then it's diagonal is irrational?

In trying to write an alternate and simple proof that at least one leg of a right triangle is a multiple of 4 using Dickson's method of generating triples, I came across quite an interesting observation that ifall the sides of a rectangle is odd,…
Sandeep
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Solving Pythagoras Problem

An aircraft hangar is semi-cylindrical, with diameter 40m and length 50 m. A helicopter places an inelastic rope across the top of the hangar and one end is pinned to a corner, a A. The rope is then pulled tight and pinned at the opposite corner, B.…
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Are there infinitely many Pythagorean triples with two primes?

Using the classic parametrization of Pythagorean triples, for a primitive triple to contain two primes, we need $$ a = |m^2 - n^2|, c = m^2 + n^2 $$ to be prime. Taking $m
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What’s the most natural/useful way of ranking Pythagorean triples “by size”?

I want to “rank” [primitive] Pythagorean triples by some metric that could reasonably be referred to as “size”. Naturally, there are a huge number of options: size of hypotenuse, size of smallest leg, perimeter, area, radius of incircle, etc. etc.…
Kieren MacMillan
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Consecutive Integers Pythagorean Triplets

I have a question for which I was not able to find an answer online. I was wondering how many Pythagorean Triplets we have found till now which consists of three consecutive integers like $(3,4,5)$.
Ganit
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Generating primitive Pythagorean triples

Given this equation $a^2 + b^2 = c^2$ , in order to generate all primitive Pythagorean triples all we nedd to do is : write (a,b,c) as : $a = 2mn $ $b = m^2-n^2$ $c= m^2+n^2$ with conditions : $\gcd(m,n)=1$ and $(m+n)$%$2= 1 $ But what about if we…
meh98
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Method for Finding all Pythagorean Triplets including a number

I am aware of following technique to generate pythagorean triplets - $$ m^2 + n^2 , m^2 - n^2 , 2mn$$ However i have discovered a new technique which seems to be working as well - Lets say i want to find triplets including n = 9. First of all i…
rnjai
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How to compute the Pythagorean triple by one of the numbers that belonged to it?

I have a positive number $n>2$. How to compute the Pythagorean triple containing $n$? $n$ may be the hypotenuse and leg.
theuses
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Ternary Tree of Pythagorean triples

When following the approach to generate the ternary tree of Pythagorean triples with Fibonacci boxes, one has the root box \begin{bmatrix}1&1\\2&3\end{bmatrix} which corresponds to the Pythagorean Triple \begin{bmatrix}3&4&5\end{bmatrix} the box…
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