Questions tagged [schwartz-space]

For question about the Schwartz space, a vector space of smooth functions stable under the Fourier transform.

The Schwartz space on $\mathbb R^n$, usually denoted $\mathcal S(\mathbb R^n)$ or just $\mathcal S$ for short is the vector space of all smooth functions $f:\mathbb R^n\to\mathbb R$ such that for all multi-indices $\alpha,\beta\in(\mathbb N\cup\{0\})^n$, the following semi-norms are finite:

$$ |f|_ {\alpha,\beta} := \sup _{x\in\mathbb R^n} |x^\alpha \partial^\beta f(x)| <\infty.$$

Here, $x^\alpha := x_1^{\alpha_1} \dots x_n ^{\alpha_n}$ and $\partial^\beta := \frac{\partial^{|\beta|}}{\partial x_1^{\beta_1}\dots \partial x_n^{\beta_n}}$. Intuitively, $f$ and all its derivatives decay faster than any polynomial.

Questions about Schwartz functions naturally arise when discussing , , , or , which are topics in .

Every compactly supported smooth function is Schwartz (i.e., $\mathcal D \subset \mathcal S$), and $e^{-|x|^2}\in\mathcal S$ is not compactly supported. The semi-norms generate a topology that is metrizable but not normable.

One reason why $\mathcal S$ is important is that the Fourier Transform of a function in $\mathcal S$ is easily seen to also be in $\mathcal S$. The boundedness of the seminorms mean that many formal manipulations like differentiating under the integral sign are very easy to justify when using Schwartz functions. For example, one defines a Fourier inversion first on $\mathcal S$, which extends to $L^2$. More generally, Fourier multipliers are defined by multiplication 'on the Fourier side', at least when the functions are in $\mathcal S$.

The dual of $\mathcal S$ is called the space of tempered distributions. As mentioned $\mathcal D \subset \mathcal S$, and therefore $\mathcal D' \supset \mathcal S'$. The distributions $T$ that are also tempered have a Fourier transform defined by duality, $$ \langle \mathcal FT, \phi\rangle := \langle T, \mathcal F\phi\rangle.$$ For example, $\mathcal F\delta_0 = 1$ in the sense of tempered distributions.

The Schwartz space can be similarly defined for other sets; for example the Schwartz space on the circle $\mathbb R/\mathbb Z$ is coincident with the space of smooth functions.

Wikipedia link here.

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If $T\frac{d}{dx} = \frac{d}{dx}T$ is it true that $T\tau_h = \tau_hT$? And viceversa?

Let $\mathcal{S}(\mathbb{R})$ be the Schwartz-space, I define on it the two operators $$\tau_h(f)(x) := f(x-h)$$ $$Df(x) := f'(x)$$ Now let $T : \mathcal{S}(\mathbb{R}) \to \mathcal{S}(\mathbb{R})$ be an operator that commutes with $D$, is it true…
Paul
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Product of a Schwartz function and a function with polynomial bonuded derivatives is schwartz?

Is true the following?: If $f\in\mathcal{S}(\mathbb{R}^n)$ and $g\in\mathcal{C}^{\infty}(\mathbb{R})$ with $|g^{k}(|x|)|\leq p_k(x)$ all $k$ where $p_k(x)$ is a polynomial then $f(x)g(|x|)$ is in $\mathcal{S}(\mathbb{R}^n)?$
eraldcoil
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function $T^n(e^{-\pi x^2})\neq 0$ for all $n\in\mathbb N$

Let $\mathcal S(\mathbb R)$ be the Schwartz-space. Look at the linear operator $T:\mathcal S(\mathbb R)\rightarrow \mathcal S(\mathbb R)$ $(Tf)(x)=\sqrt{2\pi}xf(x)-\frac{1}{\sqrt{2\pi}}f'(x)$ and define $\phi_0(x)=e^{-\pi x^2}$,…
Leon
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Is translation continouos in Schwartz space?

It is true that translation is continuous in Schwartz Space {S}($\mathbb{R}$) with its topology?, in other words, I'm trying to prove that if $\phi \in {S}\left(\mathbb{R}\right)$ then the function $\phi(\cdot-y)$ converges to $\phi$ in…
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Product of a convolution by a monomial in Schwartz space.

How proves the next formula? Let $f,g\in S(R^n)$ Schwartz space. Then for all multi index $\alpha=(\alpha_1,\ldots, \alpha_n),\quad x^{\alpha}(f*g)(x)=\sum_{\gamma+\overline{\gamma}=\alpha}\frac{\alpha}{\gamma!\overline{\gamma}!}…
eraldcoil
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Convolution of a Schwartz function with $2\operatorname{sinc}(tx)$

This is problem 3.12 in Paul Garrett's 2019 example problems. For $f \in \mathscr{S} $ (the space of Schwartz functions), show that $$\lim_{t \rightarrow + \infty} f(x) * \frac{2 \sin tx}{tx} = f(x) $$ ($*$ is the convolution operator). I'm not…
thisre
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Example of a Schwartz function

If $\psi,\phi \in \mathcal{S}(\mathbb{R}^n)$ then I know that the product $\psi\phi \in \mathcal{S}(\mathbb{R}^n)$ is also in the Schwartzspace. Now I was wondering if $\psi\in \mathcal{S}(\mathbb{R}^n)$ but $\phi \notin \mathcal{S}(\mathbb{R}^n)$…
James
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Composite function in schwartz

Let $f(x,y)=(x-y, x+y) $ and $\varphi \in S (\mathbb R^2).$ Prove that $\varphi \circ f \in S(\mathbb R^2 ),$ where $S $ is the Schwartz space and $(x,y)\in \mathbb R^2.$ I tried to apply $ \forall \alpha, \beta \in \mathbb…
A. T
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When $\mathrm{e}^{-f(x)}$ is a Schwartz function?

The gaussian function $\mathrm{e}^{-|\xi|^2}$ is a schwartz function. In general, Are there some critery on the function $f(\xi)$ for which the function $\mathrm{e}^{-f(\xi)}$ is a Schwartz funtion? From what I see, $f(\xi)=|\xi|^{m}$ with $m$ any…
eraldcoil
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Schwartz space on cartesian

Does anyone knows if there is a relationship between $\mathcal{S}(\mathbb{R^n})$ and $\mathcal{S}(\mathbb{R})$? That is, if a function is in Schwartz space for each variable, can i prove that it is on Schwartz space of the cartesian?
TDg1
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Limit sequence of Schwartz functions

Let $\left\{f_n\right\}_{n\in\mathbb{N}}\subset \mathcal{S}(\mathbb{R}), f\in L^2(\mathbb{R})$ with $\lim f_n=f$ in $L^2$ and $p(x)$ an polynomial. Since $\mathcal{S}$ is closed under the product of polynomials, for each $n$,…
eraldcoil
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Translation of a Schwartz function is a Schwartz function?

If $f\in S(\mathbb{R}^n)$ and for all $y\in\mathbb{R}^n$ then $\tau_{y}f\in S(\mathbb{R^n})$? $\sup_{x} |x^{\alpha} \partial_{x}^{\beta} \tau_{y}f(x)|<\infty$?
eraldcoil
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Schwartz function exponential decay

Let $f$ be a Schwartz function in $\mathbb{R}^n$. I would like to know if there is some constant $\alpha > 0$ such that the function defined by $g(x) = f(x)e^{\frac{\lvert x \rvert^2}{\alpha}}$ is in the Schwartz space or even $L^2(\mathbb{R}^n)$.…
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Check if a function is $\mathscr S(\mathbb R)$

How can I check if a generic function is $ \mathscr S(\mathbb R) $ ? I mean the Schwartz space. The definition asserts that $ f\in \mathscr S(\mathbb R) $ if: $ f \in C^\infty (\mathbb R) $ $ \displaystyle\Vert f \Vert = \sup_{x\in\mathbb R} |…
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Proving expression involving Schwartz function tends to zero

Let $\xi \in \mathbb{R}$ and $f$ belong to the Schwartz space on $\mathbb{R}$. I know, that Schwartz functions are rapidly decreasing, but I am not very familiar with them. My question is, why is it true that $$\lim_{x \to \infty} f(x)(e^{-2\pi i x…
TheGeekGreek
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