6

Can I find a topological space $X$ such that every convergent sequence in $X$ has a unique limit in $X$, but $X$ is not Hausdorff?

Silent
  • 6,520
  • 3
    Yes, if you look hard enough. Note that it's essential that you're considering only convergent sequences, not convergent filters or nets. – Daniel Fischer May 12 '16 at 18:27

1 Answers1

13

The co-countable topology on an uncountable set $X$ (like the reals) (the only closed sets are $X$ and all sets that are at most countable) is such a space.

The only convergent sequences are eventually constant and so the limits of convergent sequences are unique. But all non-empty open sets intersect, so $X$ is in fact anti-Hausdorff.

Henno Brandsma
  • 242,131