This approach is championed in Arnold's book on classical mechanics. The exterior derivative of a $k$-form $\omega$ is supposed to be a $(k+1)$-form, defined as follows: given tangent vectors $v_1,\dots,v_{k+1}$ at some point $x$ of the manifold, pick a coordinate chart, and let $\Lambda_\varepsilon$ be a parallelogram spanned by $\varepsilon v_1,\dots,\varepsilon v_{k+1}$ in that chart. Then, define
$$
d\omega(v_1,\dots,v_{k+1}):=\lim_{t\to0}\varepsilon^{-k-1}\int_{\partial \Lambda_\varepsilon}\omega.
$$
The area of each face of $\partial \Lambda_\varepsilon$ is of order $\varepsilon^k$. If we expand the coefficients of $\omega$ in a Taylor series in our coordinate chart, then the only contribution to the limit will come from the linear terms: the constant terms give zero contribution to the integral because of cancellation between the opposite faces, and terms of order $O(\varepsilon^2)$ will give contribution of order $\varepsilon^{k+2}$. And the contribution from the linear terms is straighforward to compute, recovering the usual algebraic definition of the exterior derivative.
Now, assume that we replace the parallelograms $\Lambda_\varepsilon$ by their images $\tilde{\Lambda}_\varepsilon$ under a diffeomorphism whose differential at $x$ is the identity map. The constant terms still gives zero contribution, since a constant form is exact (this is a crucial point; if we tried to differentiate, e. g., vector fields or metric tensors on a smooth manifold without additional structure, we would fail here.) The contribution of linear terms will be the same for $\Lambda_\varepsilon$ and $\tilde{\Lambda}_\varepsilon$, up to a negligible correction. This shows, in effect, that the whole construction was independent of the coordinate chart.