$A$ is $$A= \begin{pmatrix} 2 & 0 & 1 \\ 0 & 2 & 0 \\ 1 & 0 & 2 \\ \end{pmatrix} $$ Find a matrix $B$ so that $A=BB^{T}$. Hint: $A=PDP^{T}$.
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Hint: since $D$ is diagonal, you can take its square root $\sqrt{D}$. Then define
$$B\equiv P\sqrt{D}$$
eranreches
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Did you pull that equation out of thin air?? – A_for_ Abacus Apr 12 '21 at 21:23