Find the area of the shaded region such that the measure of a side of the square is $x$ unit.
Here is my plan and incomplete solution:
Step 1: I need to subtract the area of the circle from the area square and divide it by $4$. I denote the resulting area as $A_1$
$A_1 = \dfrac{x^2(4-π)}{16}$ square units
Step 2: Next is I need to subtract the area of a quarter circle with radius $x$ unit from the square. I denoted this resulting area as $A_2$.
$A_2 = x^2\left(1-\dfrac{π}{4}\right)$ square units
Step 3: My next plan is to subtract $A_1$ from $A_2$. The result is denoted as $A_3$.
$A_3 = \dfrac{3x^2}{16}(4-π)$ square units
I was stock in step 3. I know that I still need to remove a certain portion to get the area of the shaded region.
