0

Find all monic complex polynomials $P(x)$ such that $P(x)|P(x^2)$.

My progress so far is that I have find that for degree 1, $P(x)=x, x^2$ are the only ones.

For degree 2, they are $P(x)=x^2+x+1, x^2, x^2-1, x^2-x, x^2-2x+1$.

I also prove that these are only solutions for degree 1 and 2. However I do not see how this generalizes. Any help please?

Blue
  • 75,673
  • 1
    Oh yes, thank you pointing that out. It is because any working polynomial can be scaled to monic. I has edited it in. –  Mar 05 '21 at 23:28

1 Answers1

5

Hint: If $P(c)=0$ then $0=P(c^{2})=P(c^{4})=P(c^{8})=...$ and a polynomial can only have finite number of roots. Can you take over from here?