Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

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How can we rewrite a modulus function?

We can rewrite |x-3|<10 in the following way. -10
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In case of absolute values, isn't zero considered a positive value?

In the below image, it has been said that if x≤-4, then both |3x-3| and |2x+8| will be negative. If x=-4, how can |2x+8| be negative? If x=-4, |2x+8| becomes zero which is a positive vale. So how can they say that if x≤-4, then both |3x-3| and…
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If modulus sign is used, can a value be negative?

|x-3| If x is less than 3, will |x-3| be negative? I don't think so. For example, if x=2, |x-3|= |2-3|=1. x-3 can never be negative, I think. In this link, it has been said that when x<3, x-3 is negative, thus |x-3|=-(x-3). I think this statement…
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How do we solve the inequation $|x-1| - |x-3| \geq 5$?

The question is: how do we solve the following inequation: $$|x-1| - |x-3| \geq 5$$ For this question, I have tried to solve it like a normal absolute value problem but the answers I've were wrong so I'm quite stuck on this question. I thank you in…
allan
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When to use AND and when to use OR when we are solving a problem assosiated with absolute value?

What are the values of $n$ that satisfy the condition $1/|n| > n$? (a) $0
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Absolute value, the way of solving

$$0>1,4 -\mid2,6-x\mid$$ Have i done it in good way ?? $$-\mid2,6-x\mid<-1,4$$ $$(-\mid2,6-x\mid<-1,4)*(-1)$$ $$\mid2,6-x\mid>1,4$$ Now we've got 2 possibilities $$2,6-x>1,4$$ and $$2,6-x>-1,4$$ THE RESULTS: $$x < 1,2$$ $$x < 4$$
Wigya
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Finding the increment with the absolute function?

Let $K_1 = \left\| I_1 \right\|$ and $K_2 = \left\| I_2 \right\|$. Suppose $I_2 = I_1 + \Delta I$. Therefore: $$\Delta K = K_2 - K_1 = \left\| I_1 + \Delta I\right\| - \left\| I_1 \right\|$$ Is there a way I can calculate $\Delta K$ without having…
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Adding "C" to an absolute value equation

Does anybody know how the following equation: $$|a|+|b| \ge |a+b|$$ changes when a $c$ is added? This way: $$|a| + |b| + |c| \ge |a+b| + |c| \ge |a+b+c|$$ How should I expand this? What happens when a $c$ is added to the equation? I'd be grateful…
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Solving $\ln(\lvert y \rvert)=\ln(\lvert 1+x \rvert)+ \ln(\lvert c \rvert)$ for $y$ where $c$ denotes an arbitrary constant

According to my book: $$\ln(\lvert y \rvert)=\ln(\lvert 1+x \rvert)+ \ln(\lvert c \rvert)$$ $$\Rightarrow \ln(\lvert y \rvert)=\ln(\lvert c(1+x) \rvert)$$ $$\Rightarrow y=c(1+x)$$ I know that this is correct. However, I want to be able to understand…
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How to simplify absolute value expressions such as: $|x+1|+|x-1|$ algebraically?

After plotting this function on desmos, I understood that this absolute expression is actually a piecewise function. Hence this: $$f(x)=|x+1|+|x-1|$$is the same as $$f(x)=\left\{\begin{align}2x\quad&\text{if }x>1\\-2x\quad &\text{if }x<-1\\2\quad…
ray_lv
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Plotting $||x|-|y||=1$: How to verify the extra line segments aren't included in the plot?

I have to plot the graph of $||x|-|y||=1$, I did the following: As $|x|=\max(x,-x)$ I've obtained the following equations: $$|x|-|y|=1 \hspace{2cm} |y|-|x|=1$$ From there, I've obtained the following equations: $$x-y=1 \hspace{1cm}…
Red Banana
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Concept of Absolute value

I need to resolve this misconception quickly. The question is very simple, may I derive $|\sqrt y| = x-1$ from $y = (x-1)^2$, such that $x = |\sqrt y|+1$?
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When calculating the percent error where does the absolute value bar go?

I have been scratching my head at this for awhile, I see this all over the internet with mixed answers. When calculating the percent error does the absolute value bar go all the way through to the fraction or just the numerator? Example: $$\…
Geno C
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Is $\left|a-b\right| + \left|c-d\right|$ equal to $\left|(a+c)-(b+d)\right|$ for $a,b,c,d \geq0$?

I'm a little confused about this concept, as whatever example I'm taking holds true. I would like to know is the given problem is true considering the value of the variables is whole numbers. Is this true for n number of terms in the series?
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How to solve with steps (simple absolute value synthesis) |2x + 5| ≤ |x + 3|

|2x + 5| ≤ |x + 3| I have the answer listed in front of me but it's not helping me figure out how to get there.