Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

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Determine the graph of an absolute value function

How do I know what |x-1| = 1 look like on a graph without a graph calculator. Is this the proper way of writing it: $$ \begin{gathered}\begin{gathered}|x-1|=|y|\\ |y|=\begin{cases}y,&y\geqslant 0\\ -y&y<0\\ &\end{cases} \end{gathered} \\…
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Absolute value and roots

I've been trying to solve this problem and I always get 1, but the answer is $1 - 2x$. If $x<\frac12$ then what is $\left|x-\sqrt{(x-1)^2}\right|$ ?
Jose
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Find alternate solutions to absolute value functions

For, the problem $|x + 1| = |2x - 1|$, I found one solution analytically: $x + 1 = 2x - 1$ $\to x = 2$ Since, these are absolute functions, they should intersect once more at $x = 0$. This solution I got by guessing integers. Is it possible to find…
Dstarred
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Question involving absolute function

I saw this interesting problem in a math puzzle forum:- Find all integral values of $t$ such that the equation $|s-1| - 3|s+1| + |s+2| = t $ has no solutions. How does one approach these kind of problems?
Train Heartnet
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Minimum Value of Sum Absolute Functions

I have this problem So the minimum value of the |5x-1| is the 0 because |-a|=a and then every negative value of the 5x-1 is positive and greater than 0?
liontass
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Absolute value proof, $|a|\leq\max\{|x|,|y|\}$

I would like to confirm a proof I made: For every $a,x,y \in\mathbb{R}$ such that $x≤a≤y$, we have $|a|≤\max\{|x|,|y|\}$. I assumed that $|x|≤|y|$, so: $-|y|≤a≤|y|$, and that means: $a≤|y|$. Then, I assumed: $|y|≤|x|$, so $-|x|≤a≤|x|$, and that…
user853637
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Equivalent form of $\frac{\text{sgn}(x)}{|x|}$

Wikipedia says that any real number $x$ can be written as $|x| = \text{sgn}(x)x$ where $\text{sgn}(x)$ is the sign function. Rearranging, this means that $\frac{\text{sgn}(x)}{|x|} = \frac{1}{x}$ for $x\neq 0$. On the other hand, WolframAlpha says…
jonem
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Understanding of Absolute Values

Let $f(x)$ and $g(x)$ be two functions. Does the following property hold true? $$|f(x) - g(x)| = |g(x) - f(x)|$$ On the surface, it would seem like it, but then some other properties of absolute values don't seem to hold. $$|f(x) - g(x)| \le…
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Can you take an arbitrary constant out of an absolute value sign?

Is |f(x) + C1| the same thing as |f(x)| + C2, where the C's are just arbitrary constants? In other words, can one take out the constant from an absolute value sign? The context of this is that I'm trying to take the absolute value of an integral…
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Is the examiner's given answer wrong? (Absolute value and points of intersection question)

Part b) of this question to find the points of intersection of $y = |2x+3| - 4$ and $ y=-\frac{1}{4}x + 2$ However, in the given answer set, they seemed to have ignored the $-4$ constant in the first equation: I have no idea why they would do…
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Product of Absolute Differences: Tao 4.3.7 (h) Too restricting?

In Analysis I Tao states this lemma: Let ε, δ > 0. If x and y are ε-close, and z and w are δ-close, then xz and yw are (ε|z| + δ|x| + εδ)-close. Here x and y being ε-close is defined by |x - y| ≤ ε. He proofs it like this: Let ε, δ > 0, and suppose…
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x(t)=asin(ωt):y(t)=acos(ωt);z(t)=bt i have to find the velocity, the acceleration and then their absolute values

x(t)=asin(ωt):y(t)=acos(ωt);z(t)=bt i have to find the velocity, the acceleration and then their absolute values. I did not understand how I can calculate the absolute value.
Mary
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How to solve equations with absolute value on both sides?

Assume we are given an equation $|f(x)|$=g(x). From the definition of the absolute value we know that:$$ |f(x)|= \begin{cases} +f(x), & \mbox{if } f(x) \geq 0 \\ -f(x), & \mbox{if } f(x)<0 \end{cases} $$ This implies that in order to solve it we…
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$|(1 + j2\pi fT)^2| = 1 + (2\pi fT)^2$

I'm currently trying to understand why $|(1 + j2\pi fT)^2| = 1 + (2\pi fT)^2$ holds. So far I have: $|(1 + j2\pi fT)^2| = |-4\pi^2 f^2T^2 + j4\pi fT + 1|$. But why does $4\pi fT$ disappear? I know that $|j| = 1$.
user577529