Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

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Find real $a$ for which $x^2 +|x-a|-3\lt 0$ is satisfied for negative $x$.

*Have problem solution given at: https://math.stackexchange.com/a/460988/424260, which am unable to understand. * This problem's graphical soln. takes $|x-a|\lt 3-x^2$, & has right arm of the graph for $|x-a|$ first touching the curve for negative…
jiten
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Solving modulus equality for $x$.

The given equation is: $$|x - |4-x|| -2x = 4.$$ (Here $|x|$ means the absolute value of $x [\text{abs}(x)])$ Please help me to solve the equation for $x$.
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Finding the values that $x$ can take $\left|\frac{-10}{x-3}\right|>\:5$

$$\left|\frac{-10}{x-3}\right|>\:5$$ Find the values that $x$ can take. I know that $$\left|\frac{-10}{x-3}\right|>\:5$$ and $$\left|\frac{-10}{x-3}\right|<\:-5$$
user514117
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Why arent there 4 cases to |$a+b$|=|$x+y$|

With absolute value equations, such as $|x-4| = 3$ , to turn it into a normal equation we take the 2 cases of +- from the absolute value, which I understand. What I dont however, is why for say $|x-3| = |2x+5|$, we only do $x+3 = \pm(2x+5)$.…
John Hon
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Is the $\left|\frac{f(x)}{g(x)}\right|$ always equivalent to $\frac{\left|f(x)\right|}{\left|g(x)\right|}$

Can I split the modulus of a rational function into two parts like this $$ \left|\frac{f(x)}{g(x)}\right|=\frac{\left|f(x)\right|}{\left|g(x)\right|} \ $$ Is this statement always true for any function (or at least for polynomials) Thanks
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Trying to understand idea behind absolute value?

I came up with this question when trying to understand how to process the equation $|x| + |y| = 4$, and how its graph should look. It only started to make sense when I broke $|x|$ down into two separate statements for $x \geq 0$ and $x <0$. Then I…
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Is this correct? An absolute value question with a picture.

I found this answer to this online firstly is it true and secondly please can you explain to me how so? The question is what could the range be in this expression if x is any real number.
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Absolute Value. Real Analysis

I just came across the following. The working goes from this step: $|f(x)-f(c)|<1$. To the next step: $|f(x)|<1+|f(c)|$ Could someone please explain the transition from one step to the next using absolute value properties. Thanks!
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Solving equations with two terms having absolute values

How would one go about solving (for $x$) an equation which looks like $$ \left| \frac{x - k}k \right| + \left| \frac{x - c}k \right| = m$$ for constants $k$, $c$, $m$?
Jaood
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What is the area of the polygon fromed by the points (x,y) which satisfy the inequality: $ |x| + \frac{|y|}{2} \leq 1$

I have an SAT II question that asks: What is the area of the polygon formed by the points (x,y) which satisfy the inequality: $ |x| + \frac{|y|}{2} \leq 1$ a) 2 b) 3 c) 4 d) 8 e) 10 How would you go about solving this?
Haim
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Absolute value inequality example

Can anyone please help me with this example from Spivak? I am math autodidact. I have to express this without absolute value: $$a-|a-|a||$$ The answer is $$\begin{cases}a&a\ge0\\ 3a&a<0\end{cases}$$ All examples went OK, but I dont know this one. I…
econ
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Simplifying expression with absolute value and unknown

This is probably a really easy task for the people of this site judging by what is normally discussed here. (I'm amazed by the knowledge here!) I have this expression that I need to simplify: $$\frac{(x-2)^2}{\sqrt{(2-x)^2}}$$ From what I've…
matfor
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Absolute Difference of Two Integers

New to math. I'm looking for an explanation (proof, rule, relationship or property) that explains that the absolute value of the difference between two integers $x$ and $y$ are equal regardless of: the sign of $x$ or $y$ the order of subtraction.…
LogBar
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Rejecting a Solution to a Modulus Question

Why is the solution of $|1+3x|<6x$ only $x>1/3$? After applying the properties of modulus, I get $-6x<1+3x<6x$. And after solving each inequality, I get $x>-1/9$ and $x>1/3$, but why is $x>-1/9$ rejected?
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Prove that $||a|-|b||$ is smaller or equal to $|a-b|$

I am stuck with this question: Show that $\vert \vert a\vert - \vert b\vert\vert \le \vert a-b\vert$ I had tried proving this using the following method below: $\vert a\vert+\vert b\vert \ge \vert a-b\vert$ $-\vert a\vert-\vert b\vert \le -\vert…
Derp
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