Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

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Is my hypothesis correct?

$$\left| \left|(a^2) - 25\right|-b\right| + b = 0$$ You have to prove that $b<0$ and $b=0$ at the same time I have no problem to prove that $b$ can be $0$ the thing that I need help with is $b<0$. My thought there is a bit complicated and some…
George
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absolute value (positive and negative part)

I found a notation that $$|y_i| = y_i^{+}+y_i^{-} $$ where y is y n dimensional vector. what does +/- imply? I understand that we can have both negative and positive value into absolute function, but eventually we will always have the positive…
pippp
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Solve for the values of $x$ in $|x+k|=|x|+k$ where $k$ is a positive real number

The question asks me for which values of the real number $x$ is $|x+k|=|x|+k$ where $k$ is a positive real number. How do I go about this? Can I square both sides to get rid of the absolute value signs? When I do it this way, I get a single $x$…
Spica
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Does |x| = |y| requires checking conditions while solving?

I am trying to solve this equation $\lvert 2x \rvert = \lvert x - 2 + y \rvert$ (specifically, find set of all points $(x, y)$ satisfying equation). $\lvert 2x \rvert = \lvert x - 2 + y \rvert$ is equivalent to $2x = x - 2 + y \lor 2x = -(x - 2 +…
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Some equations involving multiple absolute values

Consider the following equation: $$|x+y^2|+|x-y^2|+|y+x^2|+|y-x^2|=a$$ I'm looking for the method for solving some problems regarding this equation, namely: 1) prove that if $a=2015$, then the equations has no solutions such that…
user263286
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Is this a misprint or am I missing something?

What I'm given is this: Evaluate: x = 5, |x| -2 I'm thinking they probably mean |x|=-2, in which case the evaluation would be false. But then again I second guess myself and wonder if they're going for something else. Any thoughts?
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Absolute Value $|1-(1/x)| = |(1/x)-1|$

Can someone please explain to me how: $$|1-(1/x)| = |(1/x)-1|$$ Im working on a limit problem in my calculus book and I cant seem to understand how they reversed this and it equals the same thing. Thanks!
Kamical
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Equation with absolute value and parameter

How to solve this equation over real numbers with parameter $p \in \Bbb R$? $$(1 - p)(\left\lvert x + 2 \right\rvert + \left\lvert x \right\rvert) = 4 - 3p$$ I know how to solve absolute value equations without parameter.
user4201961
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Has this question on Absolute Value's been asked wrong?

I was going over some basics on Khan's Academy in preparation for a test. To my surprise I got this wrong: Has this been worded wrong? Surely the person farthest from sea level is Howard? This question was asked in the the context of Absolute…
Torra
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Solving Equations And Inequations Based On The Absolute Function

Today I came across some equations and inequations based on the absolute function. These were $|x^2+4x+3|+2x+6=0$ $|x^2+6x+7|=|x^2+4x+4|+|2x+3|$ $1\le |x-1|\le 3$ $\frac{2}{|x-4|}\gt 1$ $||x|-1|\le 1$ $|x+1|\gt |2x-1|$ I am really new to these…
user227000
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Simplifying a function with absolute value and two variables

I am trying to simplify the following $ f(\alpha, \beta)= \big|1-(\frac{\alpha+\beta}{2}+\frac{|\beta-\alpha|}{2})\big|-2 \big|1-\alpha-(\frac{\alpha+\beta}{2}+\frac{|\beta-\alpha|}{2})\big|+ |\alpha-1|…
Tyrone
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is the following true: $|a-b| = ||a|-|b||$?

is $|a-b| = \bigg||a|-|b|\bigg|$ ? I have tried a few examples and they seems to come out true, but I can't find any rule stating it. Is it true for all $a$ and $b$? Or am I missing something? Please notice I'm not talking about $|a-b| = |a| - |b|$,…
Tom Klino
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Absolute value:$ |x-a| \leq \frac{|a|}{2} \Rightarrow |x| \geq \frac{|a|}{2}$

Prove that $$|x-a| \leq \frac{|a|}{2} \Rightarrow |x| \geq \frac{|a|}{2}$$ I've tried by direct proof and contradicion but nothing worked. I would like a hint or a tip of what should I do. Thanks in advance!
Giiovanna
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How to simplify an expression with absolute and log functions?

I'm confused with regard to simplifying this expression: $$ |x| - |x-A| > \ln(\Gamma) $$ I was thinking of taking square on both ends, and that's basically where I got confused. Should I square the whole left side of the expression, i.e. $(|x| -…
Ali
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Absolute Value Theorem

When trying to prove the inequality $$ |a +b| \leq |a| + |b| \text{, for any real numbers a and b} $$ I manage to use the absolute value definition to get to following inequality: $$ -\big(|a|+|b|\big) \leq a + b \leq |a| + |b| $$ However, the…
MBdr
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