Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
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Which one is greater $600!$ or $300^{600}$

Which one is greater $600!$ or $300^{600}$ $\bf{My\; Try::}$ I have used Stirling Approximation. For large $n>2\;,$ We can write $\displaystyle n! \approx \left(\frac{n}{e}\right)^n\sqrt{2\pi n}$ So $$600!\approx…
juantheron
  • 53,015
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Proof of Pascal's rule by induction

I'm trying to prove pascal's rule by induction.Who could tell me how can I prove the following equation. i.e $$\dbinom{n}{k}=\dbinom{n-1}{k-1}+\dbinom{n-1}{k}$$ Many Thanks!!!
Yi Wang
  • 41
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Coefficients and Expansions

So I was just hoping for a look over my work to check if what I am doing is right because I'm not so sure: Find the coefficient of: f$$ x^6$$ with the equation $$(3x-\frac{(1)}{x^2})^{12}$$ I have: $\sum_{i=0}^{24} …
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The value of $\mathop{\sum\sum}_{0\leq i< j\leq n}(-1)^{i-j+1}\binom{n}{i}\binom{n}{j}$

The value of $$\displaystyle\mathop{\sum\sum}_{0\leq i< j\leq n}(-1)^{i-j+1}\binom{n}{i}\binom{n}{j} = $$ $\bf{My\; Try::}$ Let $$S=\mathop{\sum\sum}_{0\leq i
juantheron
  • 53,015
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Calculation of the limit of the difference of binomial coefficients

This question pertains to harmonic analysis on spheres. Let $H_d$ = {homogeneous, total degree $d$ harmonic polynomials in $\mathbb{C}[x_1,\dots,x_n]$} Given that the Dimension of $H_d = \binom {n+d-1}{ n-1} - \binom {n+d-3}{ n-1}$ How do I…
user12802
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Evaluate the sum $\sum_{i=0}^n \binom{n}{i}^2 i^k$

Given a positive integer $k$, is it possible to evaluate the following sum? $$ \sum_{i=0}^n \binom{n}{i}^2 i^k\,\,\,? $$ [I know just for $k=0$ the sum is $\binom{2n}{n} \approx 4^n/\sqrt{n}$..]
user207096
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Binomial identity $\sum_{i=0}^{n-1-j}\binom{n}{i+j}\binom{i+j}{j}(-1)^i=\binom{n}{j}(-1)^{n+j+1}$

Let $n$ be a positive integer and fix a non-negative integer $j\le n-1$. Is it true that $$ \sum_{i=j}^{n-1}\binom{n}{i}\binom{i}{j}(-1)^i=\binom{n}{j}(-1)^{n-1} $$ or,…
user207096
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how many terms will there be once you collect terms with equal monomials? What is the sum of all the coefficients?

If you expand $(x_1+x_2+\cdots+x_k)^n$, how many terms will there be once you collect terms with equal monomials? What is the sum of all the coefficients? I'm kind of lost here. This came up with other questions on the topic of binomial…
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Number of terms in the expansion of $\left(1+\frac{1}{x}+\frac{1}{x^2}\right)^n$

Number of terms in the expansion of $$\left(1+\frac{1}{x}+\frac{1}{x^2}\right)^n$$ $\bf{My\; Try::}$ We can write $$\left(1+\frac{1}{x}+\frac{1}{x^2}\right)^n=\frac{1}{x^{2n}}\left(1+x+x^2\right)^n$$ Now we have to calculate number of terms in…
juantheron
  • 53,015
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Prove that $\frac{(2n)!}{(n!)^2}-1$ is divisible by $(2n+1)$

Prove that $$\frac{(2n)!}{(n!)^2}-1$$ is divisible by $(2n+1)\;,$ Where $n\in \mathbb{N}$ and $n>1$ $\bf{My\; Try::}$ Let $$S = \frac{(2n)!}{n!^2}-1 = \frac{2^n(2n-1)(2n-3)\cdot \cdot ........\cdot 3 \cdot 2 \cdot 1}{n!}-1$$ Now How can we prove…
juantheron
  • 53,015
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Sum of Series of Binomial Coefficients.

Find the sum of $\binom{200k}{0}+\binom{200k}{100}+\binom{200k}{200}+...+\binom{200k}{200k}$ and $\binom{200k}{1}+\binom{200k}{101}+\binom{200k}{201}+...+\binom{200k}{200k-99}$ in terms of $k$. I've tried to do generating functions but I don't get…
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Sum of binomial coefficients $\sum_{n=0}^6 \binom{6}{n} = 2^6$

I assume this is a rather simple result, but I am not sure how to arrive at it. Apparently: $$\sum_{n=0}^6 \binom{6}{n} = 2^6$$ I can sum over all the binomial coefficients and verify this of course, but how would i arrive at the above without…
Naz
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Subsets and binomial coefficients

Assume that $R$ is a set with $n$ elements. We know that the number of subsets of $R = 2^n$. What does this statement have to do with the binomial coefficient?
Lama
  • 43
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5 answers

Sum of the rows of Pascal's Triangle.

I've discovered that the sum of each row in Pascal's triangle is $2^n$, where $n$ number of rows. I'm interested why this is so. Rewriting the triangle in terms of C would give us $0C0$ in first row. $1C0$ and $1C1$ in the second, and…
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Prove the following result on binomial coefficients

If $(1+x)^n=^n\!\!C_0+^n\!\!C_1x+^n\!\!C_2x^2+\cdots+^n\!\!C_nx^n$, then show that $$(^n\!\!C_0-^n\!\!C_2+^n\!\!C_4-^n\!\!C_6+\cdots)^2+(^n\!C_1-^n\!\!C_3+^n\!\!C_5-\cdots)^2\\ =^n\!\!C_0+^n\!\!C_1+^n\!\!C_2+\cdots+^n\!\!C_n$$ We have by putting,…