Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
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Sum of Triple Product of Binomial Coefficients with fixed variable sum

I have to calculate a product of two probabilities, namely hypergeometric distribution $$P_1(t)=\frac{\binom{\frac{D+m}{2}}{t}\binom{\frac{D-m}{2}}{z-t}}{\binom{D}{z}}$$ and binomial distribution $$P_2(s)=\frac{1}{2^{D-z}}\binom{D-z}{s}$$ where…
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How we can show this ;$\frac{x^2+y^2+z^2}{2}\times\frac{x^5+y^5+z^5}{5}=\frac{x^7+y^7+z^7}{7}$

Let be $\quad x+y+z=0$ show this: $$\frac{x^2+y^2+z^2}{2}\times\frac{x^5+y^5+z^5}{5}=\frac{x^7+y^7+z^7}{7}$$ I solved ,but Im interesting what are you thinking about this,how can we arrive to solution quickly?
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Evaluate $\binom{m}{i} - \binom{m}{1}\binom {m-1}{ i} + \binom{m}{2}\binom{m - 2}{i} - \ldots + (-1)^{m-i} \binom{m}{m-i}\binom{ i }{i} $

Evaluate the expression $$\binom{m}{i} - \binom{m}{1}\binom {m-1}{ i} + \binom{m}{2}\binom{m - 2}{i} - \ldots + (-1)^{m-i} \binom{m}{m-i}\binom{ i }{i} $$ I'm really stumped about trying to get anything meaningful out of this. For some context I…
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What is the coefficient of $x^4$ in the expansion of $\sqrt[3]{1+x}$

Here's what I tried: $$\sum_{n \ge0} {\frac{1}{3} \choose n} x^n= \sum_{n \ge0} = \frac{\frac{1}{3}!}{n!(n-\frac{1}{3})!}x^n=\sum_{n \ge0} \frac{(\frac{1}{3}-1)(\frac{1}{3}-2)\cdot ...\cdot(\frac{1}{3}-(n-1)) }{n!}x^n$$ What to do more, or is this…
Gjekaks
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Prove this binomial sum

Following problem is interesting Show that: $$\sum_{i=1}^{n-1}\binom{n-1}{i} i^{i-1}(n-i)^{n-i-1}=n^{n-1}-n^{n-2}$$
user253631
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Binomial coefficients sum convergens

Find when $\sum_{n=1}^{\infty }\binom{\alpha}{n}$ ($\alpha$ is a real number) diverges, converges, or converges absolutely. First I notice that it is basically ${(1+1)}^{\alpha}$ so the sum always converges to $2^{\alpha}$. But what if I want to…
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The coefficient of $x^3$ in $(1+x)^3 \cdot (2+x^2)^{10}$

Find the coefficient of $x^3$ in the expansion $(1+x)^3 \cdot (2+x^2)^{10}$. I did the first part, which is expanding the second equation at $x^3$ and I got: $\binom {10} 3 \cdot 2^7 \cdot (x^2)^3 = 15360 (x^2)^3$, but I can't figure out what to do…
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Why is ${n \choose k} ≥ 1$?

Why is $${n \choose k} ≥ 1$$ I've looked at the expansion of the binomial coefficient, but can't see why the nominator is larger or equal to the denominator.
mavavilj
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Very odd binomial coefficients

The number of odd binomial coefficients in each row of Pascal's triangle is always a power of two although their sum rarely is. One of these rare occasions occurs for numbers of the form $\,$$n = 2^m -2$$\,$$\,$when the sum is exactly half of the…
user2052
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Proportion with 3 variables - binomial coefficients

So, if we're given something like this: $$\binom{n}{k}:\binom{n+1}{k}:\binom{n+1}{k+1}=3:4:8$$ How do I rewrite this so I can manipulate it? Edit: Is there a general procedure for n variables?
A6SE
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Show that $\frac{n(n-1)(n-2)\times\cdots\times(n-r+1)}{r!}=\frac{n!}{r!(n-r)!}$ = The binomial coefficient formula

I have written in a textbook that $$\cfrac{n(n-1)(n-2)\times\cdots\times(n-r+1)}{r!}\tag{1}$$ $$=\cfrac{n(n-1)(n-2)\times\cdots \times 2 \times 1}{r!(n-r)(n-r-1)\cdots \times 2 \times 1}\tag{2}$$ $$=\cfrac{n!}{r!(n-r)!}\tag{3}$$ I understand…
BLAZE
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Find sum of binominal formula and prove it

I have hard time with finding sum of this: $$ \sum_{k=1}^{n}k{n\choose k} $$ Please help! Prferably with some good hints.
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Fun Proof! Show that there are ${m+n \choose n}$ allowable paths from $(0,0)$ to $(m,n)$ for all $m, n \in Z$

Define an ``allowable path" from a point $(x,y) \in R^2$ to a point $(x',y') \in R^2$ to be a path from $(x,y)$ to $(x',y')$ consisting of a finite sequence of positive, length $1$, horizontal and vertical steps. In particular, there are no…
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pascal's triangle sum of nth diagonal row

today i was reading about pascal's triangle. the website pointed out that the 3th diagonal row were the triangular numbers. which can be easily expressed by the following formula. $$\sum_{i=0}^n i = \frac{n(n+1)}{2}$$ i wondered if the following…
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Inequality with power function and binomial coefficients

Any suggestion on how to proceed to show: $$\frac{2(m+1)^m -1 }{(m+1)m} - \sum_{k=0}^{m} {{m}\choose{k}} \frac{m^k}{(k+1)^2} >0 $$ where $m\geq 2$ is of course an integer. Numerical results seem to confirm its validity.
Learner
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