Questions tagged [hausdorff-measure]

If $(X,\rho)$ is a metric space, then for any subset $S$, we have $$ H_\delta^d(S):=\inf\ \left{ \sum_{i=1}^\infty ({\rm diam}\ U_i)^d | S\subset \bigcup_{i=1}^\infty U_i,\ {\rm diam}\ U_i < \delta \right}, $$ where the infimum is over all countable covers of $S$. Then we have $H^d(S):=\lim_{\delta \rightarrow 0 } H^d_\delta (S)$, which is called the $d$-dimensional Hausdorff measure.

If $(X,\rho)$ is a metric space, then for any subset $S$, define $$ H_\delta^d(S):=\inf\ \left\{ \sum_{i=1}^\infty ({\rm diam}\ U_i)^d | S\subset \bigcup_{i=1}^\infty U_i,\ {\rm diam}\ U_i < \delta \right\}, $$ where the infimum is over all countable covers of $S$. Then we have $H^d(S):=\lim_{\delta \rightarrow 0 } H^d_\delta (S)$, which is called the $d$-dimensional Hausdorff measure.

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291 questions
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Frostman's Lemma

Say $h_\alpha$ is Hausdorff measure. Recall Frostman's Lemma. Suppose $K\subset\Bbb R^d$ is compact. Then $h_\alpha(K)>0$ if and only if there exists a (regular Borel) probability measure $\mu$ supported on $K$ with $\mu(B(x,r))\le cr^\alpha$ for…
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Why does Hausdorff measure go to zero as diameter power increases?

For example, why does the Hausdorff measure of a flat disc go to zero when the power that the diameter is raised to (in the definition of the Hausdorff measure) reaches 3?
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Scaling property proof of Hausdorff measure

I need to prove that $\mathcal H^s(\lambda F) = \lambda^s\mathcal H^s(F)$. Now my argument is as follows: Let $\{U_i\}$ be a $\delta$-cover of $F$, then $\{\lambda U_i\}$ is a $\lambda\delta$-cover of $\lambda F$. So: $$\begin{align} \mathcal…
Dylan Zammit
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Inequality for Hausdorff Measure

I am reading Falconer's book "Fractal Geometry" and he mentions that we can assume that "$0<\mathcal{H}^{s}(F)<\infty$" where $\mathcal{H}^{s}$ is the $s$-dimensional Hausdorff measure. I get the feeling the he means that we can only do this in…
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Show that for all $\varepsilon>0$ there is a compact $K\subset E$ s.t. $m_\alpha (E\backslash K)<\varepsilon$.

Let $E\subset \mathbb R^d$ a borelien s.t. $m_\alpha (E)<\infty $ where $m_\alpha $ is that $\alpha -$Hausdorff measure. Show that for all $\varepsilon>0$ there is a compact $K\subset E$ s.t. $m_\alpha (E\backslash K)<\varepsilon$. In fact, I don't…
idm
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Bounds on Hausdorff measure when extending a set

Let $(X, \rho)$ be a metric space that has Hausdorff dimension $d$, and let $S$ be an arbitrary Borel subset such that $H^d(S) = \alpha > 0$, where $H^d$ denotes the $d$-dimensional Hausdorff measure (assume this is nonzero). Is it possible to show…
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example; $H^t(K)=\infty$, and $H^s(K)=0$ for all $s > t$

Let $n\in \mathbb{N}$, and $H^s$ be the $s$-dimentional Hausdorff measure. Does there exist $0 t$?
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More detail please on exactly why the Hausdorff measure is monotone decreasing?

I've seen similar questions to my question, as has been suggested by some responses to the first version, but the answers (e.g. from Christopher L), don't help me understand exactly why the Hausdorff measure decreases as delta increases. In…