Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

7820 questions
1
vote
1 answer

Improper integral and finding values for when they exist

please don't mark this as a replicated post, nobody is answering me on the old one. Can anyone explain what to look for next: Find the values of $p>0$ for which the following integral exists:$$I =\int^{\infty}_{1} x^{-p}\sin{(x)} dx$$ which has an…
user2850514
  • 3,689
1
vote
1 answer

Finding whether improper integrals exist

For which $p>0$ does the following improper integral exist? $$\int^{\infty}_{1} x^{-p}\sin{x} \ dx$$ how do I find the value of p?
user2850514
  • 3,689
1
vote
2 answers

Evaluating an improper integral yields an indeterminate answer?

$$\displaystyle \int_{0.5}^1 \frac{\ln(1-t^2)}{t^2} \mathrm{d}t = \lim_{h\to 1^-} \int_{0.5}^h \frac{\ln(1-t^2)}{t^2} \mathrm{d}t =$$ $$ \lim_{h\to 1^-} \left[\ln(1-t)-\ln(1+t)-\frac{\ln(1-t^2)}{t} \right]_{0.5}^{h} = -\infty - \ln 2 +\infty…
TylerC
  • 67
1
vote
1 answer

Prove that two integrals are convergent or disvergent simultaneously

I'm dealing with a problem for improper integrals reads the following: Let $f(x)$ be a function defined on $[a,+\infty)$, monotonic down to $0$ as $x \to +\infty$. Prove that the following integrals $\int_{a}^{+\infty} f(x)dx$ and…
1
vote
2 answers

Does $\int_{1}^{\infty}|\sin(x)/x|dx$ converge?

$$\int_{1}^{\infty} \left| \frac{\sin(x)}{x}\right|dx$$ I'd like to know if this integral converges or not. I tried Wolframalpha but it didn't give me answer.
YD55
  • 169
1
vote
1 answer

Improper Integral of $\int_{-1}^0 \frac{e^\frac{1}{x}}{x^3}dx$

I have a question for The Improper Integral of $\int_{-1}^0 \frac{e^\frac{1}{x}}{x^3}dx$ That's what i have done $u=\frac1x$ $du=\frac{-1}{x^2}$ After integrated by parts I had $e^{\frac1x}(1-\frac1x)$ So the $\lim_{t\rightarrow 0^-}…
user32104
  • 527
1
vote
1 answer

Improper Integral from minus infinity to $0$ of $xe^{2x}$

Improper Integral $$ \int_{-\infty}^0 xe^{2x}dx $$ I have got $$ \lim_{t\to -\infty} [-1/4 - te^{2t} + e^{2t}/4] $$ The answer in My book is $-1/4$ why?
user32104
  • 527
1
vote
4 answers

The improper integral of $1/(x^2+x)$ from $0$ to $\infty$.

I know the integral of $\dfrac{1}{x^2+x}$ from $0$ to infinity is equal to $$\lim_{t \to \infty}(\ln|t|-\ln|t+1|-\ln|1|+\ln|2|)ln|t|=\infty $$ but in my book the answer is $\ln2$. Why??
user32104
  • 527
1
vote
2 answers

Does this integral converge $\int_{-\infty}^{\infty} \frac{e^{-x}}{1+x^2}\,dx$

I need to check whether this integral converges or not $\int^{\infty}_{-\infty} \frac{e^{-x}}{1+x^2}\,dx$ I substituted $y=-x$ then this integral transformed to $\int^{\infty}_{-\infty} \frac{e^{y}}{1+y^2}\,dy$ , then I thought of dividing it…
Mathronaut
  • 5,120
1
vote
1 answer

Checking the convergence of this improper integral $\int_{-\infty}^{\infty} x^ne^{-|x|}dx$

need to decide rather the this integral converges or not: $$\int_{-\infty}^{\infty} x^ne^{-|x|}dx$$ is it possible to say that it converges beacuse it's "tail"->0 and the function itself is continous and blocked?
nimas li
  • 11
  • 1
1
vote
2 answers

Calculate $\int_{0}^{\infty}\frac{\arctan(x)}{(1+x^2)^{3/2}}dx$ or show that it diverges

Calculate the following improper integral or show that it diverges. $$\int_{0}^{\infty}\frac{\arctan(x)}{(1+x^2)^{3/2}}dx$$ I'm really lost. Your help would be very appreciated.
William
  • 45
1
vote
1 answer

Does there exist a sequence of compact rectifiable sets $C_{N}$ such that $\lim_{N\rightarrow \infty}\int_{C_{N}} x=\lambda$ for any $\lambda$?

Let $f:\mathbb{R}\rightarrow \mathbb{R}$ be the function $f(x)=x$. Show that, given $\lambda \in \mathbb{R}$, there exists a sequence $C_{N}$ of compact rectifiable subsets of $\mathbb{R}$ whose union is $\mathbb{R}$, such that $C_{N}\subset…
user39723
1
vote
1 answer

Improper Integrals: if one term diverges then...

I would like to know if it is true that if one term (summand) diverges then the whole improper integral diverges. I would have thought that it would be like splitting a fraction, that divergance of the numerator can/may be compensated by the…
ben
  • 35
1
vote
3 answers

Approach to an improper integral involving sinh

How do I calculate an integral $\int_{-\infty}^{\infty} \frac{z-a}{\sinh(z-a)}\frac{z+a}{\sinh(z+a)} dz$ for $a>0$? Expanding the integrand and integrating term-by-term (a-la polylog) gives rise to an ugly looking double series. Edit: it surely can…
1
vote
1 answer

$ \int_0^1(\ln\left(\frac{1}{x}\right))^n $ dx

find values of n for which the integral converges $ \int_0^1 (\ln\left(\frac{1}{x}\right))^n $ dx i am able to understand that Integral needs to be broken in two parts so that convergence can be checked at x=1 and x=0 separately. for the first part…