Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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Improper integral asymptote shortcut

Suppose one has a function $ \ f(x) = (x-b)^ {-p} \ $ and ,of course, an asymptote at x = b and p is positive. Is it correct that the integral of f(x) from a to c (where a less than b less than c) will always converge of the following conditions…
Ryan
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How to show a improper integral is convergent by using Taylor expansion?

How do I show that the following improper integral $$\int^1_0\frac{e^x-1-x}{x^2\sqrt{x}}dx$$ is convergent by using Taylor expansion rigorously? So $e^x=1+x+x^2/2+x^3B(x)$ where $B(x)$ bounded close to zero. It doesn't make sense to just insert this…
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Is the Quotient test from shaums advanced calculus page 311-312 correct?

Is the Quotient test from shaums advanced calculus page 311-312 correct? (a) If $f(x)\geq 0$ and $g(x)\geq 0$ for $a\leq x\leq b$, and if $\lim_{x\rightarrow a} \frac{f(x)}{g(x)}=A\neq 0$ or $\infty$ then $\int_a^b f(x)dx$ and $\int_a^b g(x)dx$…
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Determining the convergence of improper integral

I would like to prove the convergence of the following improper integral: $$\int_1^2 {\frac{\sqrt{1+x^2}}{\sqrt[3]{16-x^4}}} dx\quad\quad $$ I tried to find antiderivative (with assistance of online calculators) and then check the limits, but was…
Avi Tal
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Computing $\int_{1}^{\infty}\left(\frac{1}{t}-\text{arcsin}\left(\frac{1}{t}\right)\right)\text{d}t$

I'm interested in the integral $$ I = \int_{1}^{\infty}\left(\frac{1}{t}-\text{arcsin}\left(\frac{1}{t}\right)\right)\text{d}t $$ I've shown that this integral exists and I know that $I = \frac{\pi}{2} - \left(1+\ln 2\right)$. I've tried multiple…
Atmos
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Convergence of Improper Integral: $\int_{e^2}^\infty {dx\over x\log\log x}$

Test the convergence of the following integral$$\int_{e^2}^\infty {dx\over x\log\log x}$$ I understand that the problem is only at $\infty$ how to proceed ?
Aman Mittal
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Find the maximum value $\alpha$ for which $\int_{0}^{\frac{1}{\pi}} \frac{1}{x^\alpha} \sin{\frac{1}{x}}dx$ converges.

Many calculus or analysis books write improper integrals $\int_{a}^{b} f(x)dx$, where $f(x)$ is a function such that $\lim_{x\to a} f(x)=+\infty$ or $\lim_{x\to a} f(x)=-\infty$ or $\lim_{x\to b} f(x)=+\infty$ or $\lim_{x\to b} f(x)=-\infty$. But…
tchappy ha
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What is the domain of the function $ f:x\mapsto \int_0^1\frac{t^x-1}{\ln(t)}dt$

I have been asked to find the domain of the function $$f:x\mapsto \int_0^1\frac{t^x-1}{\ln(t)}dt$$ where $ x $ is real. Obviously, $ f(0) $ exists, but for $ x\ne 0$ i couldn't find the criteria to use.
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Limit Comparison Test for Improper Inegrals

Given the integral : \begin{equation} \int_{1}^6 \frac{1}{x^p-x}\;dx \end{equation} I'm trying to find for which values of p the given integral converges. I know that there is a singularity point at $x=0$, and I'm trying to use the limit comparison…
AimMaan
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convergence of improper integral, sin in denominator

Let $f: (0,\infty) \times (0,1) \rightarrow \mathbb{R} $ where $f(x,t) = \frac{t^x}{\sin{\sqrt{t(1-t)}}}$ . I want to check if $g(x) = \int_0^1{f(x,t)dt}$ is convergent for $x\in(0,\infty)$. Have tried different ways, for example integration by…
flo
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How to solve this improper integral $\int_{0}^{+\infty} \frac{\sin^3 x}{x^2} \,dx$

I have a problem $$\int_{0}^{+\infty} \frac{\sin^3 x}{x^2} \,dx$$ How do I solve this? Attempt: $$I(\alpha)=\int_{0}^{+\infty} \frac{\sin^3 (\alpha x)}{x^2} \,dx$$ $$\implies I'(\alpha)=\int_{0}^{+\infty} \frac{3\cos (\alpha x)\sin^2 (\alpha…
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How do I determine whether the integral $\int^{\infty}_1\frac{\sin x}{(\ln(x+1)-\ln x)^a} \mathrm{dx}$

How do I determine whether the integral $$\int^{\infty}_1\frac{\sin x}{(\ln(x+1)-\ln x)^a} \mathrm{dx}$$ converges absolutely or not and for which $a$? I actually to be honest have no idea how to approach this problem and could use some hints on how…
user895986
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Parametric improper integrals

How can I find the values of $\mu$ such that: $\displaystyle\int_0^1\frac{1}{x\sqrt{1+x^\mu}}\,\mathrm{d}x$ is finite $\displaystyle\int_1^\infty\frac{\log(x)}{x^\mu}\,\mathrm{d}x$ is finite The second one looks like a Taylor series, but my…
sinbadh
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evaluating $\int_0^{\infty}\frac{e^{-t-\frac{x}{t}}}{t} dt$

I got to this integral, while proving some theorem in statistics: $$\int_0^\infty \frac{e^{-t-\frac{x}{t}}}{t} \mathop{dt}$$ I have trouble evaluating it. I tried partial integration, tried substitution with some polynomial and some trigonometric…
Untitled
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Improper Integral Question $ \int^{\infty}_0 \frac{\mathrm dx}{1+e^{2x}}$

I want to check if it's improper integral or not $$ \int^{\infty}_0 \frac{\mathrm dx}{1+e^{2x}}.$$ What I did so far is : set $t=e^{x} \rightarrow \mathrm dt=e^x\mathrm dx \rightarrow \frac{\mathrm dt}{t}=dx $ so the new integral is: $$…
Ofir Attia
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