Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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Does $\int_{-\infty}^\infty \text da \ \int_{-\infty}^\infty \text db \ e^{i u (a^2-b^2) - v(a^2-b^2)^2}a^p b^q$ converge?

I'm trying to solve \begin{equation} S_{p,q}:= \int_{-\infty}^\infty \text da \ \int_{-\infty}^\infty \text db \ \exp \Big[i u (a^2-b^2) - v(a^2-b^2)^2\Big] a^p b^q \end{equation} with positive real valued constants $u$ and $v$ for all cases…
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Convergence of improper integral with parameter

I'm studying improper integrals for an exam and solving some exercises from previous exams and I came across this. It says: "Give two definitions of the following integral and analyse the convergence for each case. Explain the result." $$\int_0^3…
John Katsantas
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How can i study the convergence of the following improper integral?

I have tried to narrow $\sin(x)$ by substituting to $\int_{0}^{1/2}\frac{dx}{x^{3/2}\log(x)}$, but anyway, I have not obtained anything so far. $$\int_{0}^{1/2}\frac{\sin(x)}{x^{3/2}\log(x)}\,dx.$$
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Integral of $\sin(x^2)$ From 0 to Infinity

In my complex analysis final yesterday we computed $$\int_{-\infty}^\infty{\sin(x^2)dx}=\int_{-\infty}^\infty{\cos(x^2)dx}=\sqrt{\pi/2}$$ using contour integration. It seems similar to the Gaussian $$\int_{-\infty}^\infty{e^{-x^2}dx}$$ which can be…
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How does $1/e^{(1/\infty)}$ equal $1$?

My professor had us solve an improper integral, the problem or work I did correctly, however, when I got to the final part of the answer, I got $1/e^{1/\infty} - 1/e$. My professor got this as well, but when she put the actual value, she put $1 -…
Phia
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Convergence of an improper integral

When is $\displaystyle \int_{0}^{\frac{1}{2}}\left(x\log^{2}x\right)^{-r}dx$ convergent? And how to prove it?
CrisSer
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Improper integral of Euler constant

What about whether or not this integral converges: $$\int_0^\infty x^\alpha(\text{log}_e(x))^ne^{-x}\text{d}x\:\:\:\:\:\:\:(\star)$$ $\alpha,n,x:=\begin{cases}\alpha\in\mathbb{R^+}\cup\text{(-1,…
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How can I compute $\int_0^\infty {\sin x \over x} dx$ from computing $\int_0^\infty e^{-xt} {{\sin x} \over x} dx$

This is what I tried. I let $\int_0^\infty e^{-xt} {\sin x \over x} dx= F(t)$ and computed $f(t) = \int_0^\infty (-x) * e^{-xt} * (sinx/x) dx$ but I couldn't get anything more. Please help me.
최선웅
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When does $\int_0^{\infty}\frac{7x}{x^2+1}-\frac{7C}{3x+1}dx$ converge?

I am required to find the values of $C$ for which the integral $$\int_0^{\infty}\frac{7x}{x^2+1}-\frac{7C}{3x+1}dx$$ converges. I know by experimentation that it converges when $C=3$. I am, however, unable to show this in a rigorous way. I get stuck…
niobe
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Measure of Smoothness of a Function

I would like to proove somehow that if $$f(x) = \int_{-\infty}^{+\infty} g(x+\varepsilon) \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{\varepsilon^2}{2\sigma^2}} \mathrm{d}\varepsilon$$ with $g$ continuos and limited, than $f$ will be its smoothed…
Sam
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itegrable, converge, improper integral

$f(x)$ is a itegrable function on $(0,+\infty)$ and $\int_{0}^{+\infty}f(x)dx$ coverge. Prove that $$\lim_{t\to 0^+}{\int_{0}^{+\infty }e^{-tx}f(x)dx}=\int_{0}^{+\infty }f(x)dx$$ I got that problem when I learned about improper-integals with a…
Noun
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Improper integral of $\exp(-x)|\sin(x)|$

I encountered the following improper integral: $I=\int\limits_0^\infty {{e^{ - x}}\left| {\sin x} \right|dx}$. I solved the problem as follows: $I=\int\limits_0^\pi {{e^{ - x}}\sin xdx} - \int\limits_\pi ^{2\pi } {{e^{ - x}}\sin xdx} +…
Viet
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Convergence/Divergence $\int_2^\infty \frac{4x^3+3x^2-x}{5x^5-2x^4+x^2-2}\ln x \, dx$

$$\int_2^\infty \frac{4x^3+3x^2-x}{5x^5-2x^4+x^2-2}\ln x\, dx$$ How should I approach this? can I look at $$\int_2^\infty \frac{\ln x}{x^2}\,dx \text{?}$$
newhere
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How we can solve: $\int_0^\infty \frac{\exp(ib x) }{x+b}d x$

The above integral has a pole at $x=-b$. $b$ is real and $b\ge 0$. To my knowledge such integral are solved using residue theorem. But, I am not able to find suitable contour to solve this integral.
Bandhu
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How do I solve this indefinite integral?

Given the improper integral: $$\int_1^\infty 45\frac{x+1}{x^2+2x} \, dx$$ I was able to set up the limits as shown below, but I am not sure how to continue integrating. $$\lim_{t\to\infty}\int_1^t 45\frac{x+1}{x^2+2x} \, dx = \lim_{t\to\infty} 45…
Derek
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