Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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For a continuous function, with a bounded antiderivative, prove improper Integral exists.

$f :[1, \infty)\rightarrow\mathbb{R}$ is a continuous function, with a bounded antiderivative $F$ It follows that, the improper integral $$\int_{1}^{\infty} \frac{f(x)}{x^{\alpha}} dx$$ exists for all $\alpha \in \mathbb{R^{+}}$ I don't want a full…
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Does $\int_0^{+\infty} e^{-t\sin t}\;dt$ converge?

Does $I=\displaystyle \int_0^{+\infty} e^{-t\sin t}\;dt$ converge? I haven't got the correction so, I would like to know if it's correct. $\forall t\in \big[(2k+1)\pi,\; (2k+2)\pi\big],\quad t\sin t\ \le 0\implies e^{-t\sin t}\ge 1$ Then…
Stu
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For which positive a this integral is convergent?

For which positive $a$ this integral is convergent? $$\int_0^\infty \frac{\sin x}{x^{a}+x^{2a}}\mathrm dx$$ I tried splitting it to two integrals (one from $0$ to $1$). I am not sure, but it seems to be convergent for all $a$.
Spideyyyy
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calculating $\int_0^{\infty}\frac{1}{(x^2+y)^n}dx$

I would like to know if I solved this improper integral right: $$\int_0^{\infty}\frac{1}{(x^2+y)^n}dx$$ for $y\gt 0$ My solution: $$\int_0^{\infty}\frac{1}{(x^2+y)^n} \, dx=\lim_{M\rightarrow \infty}\int_0^M1\cdot\frac{1}{(x^2+y)^n} \, dx$$ now I…
segevp
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Improper Integral I can't solve $ (1+\sin x)/x^2$

I've tried to figure out if this improper integral convergse or diverges: $$\int_1^\infty\frac{\sin(x) +1}{x^2}.$$ I want to use the "direct comparison" (sorry but I'm italian and in my book it's called "Confronto Diretto"). My integrand function…
D.T
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Improper integral $\int_{0}^{\pi}{\frac{x}{\sin{x}}}\,dx$

The problem is asking to check the convergence of the improper integral $$\int_{0}^{\pi}{\frac{x}{\sin{x}}}\,dx.$$ Besides some substitution and partial integration I've tried browsing through stackexchange and haven't found any useful tips…
Collapse
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How to solve these two integrals after substitution

I am trying to solve this integral: $$ \int_{0}^\infty \frac{\exp\left[-\frac{1}{\beta(x_s^2-1)}(u^2+y_p-y_s)\right]\exp\left[-\frac{1}{\beta}(u-\sqrt{y_s})^2\right]}{\sqrt{\frac{\pi}{\beta(x_s^2-1)}(u^2+y_p-y_s)}}\,u\,du, $$ where…
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How to evaluate $\int_0^{\infty} \frac{2(x-\tanh x)}{\sinh x \tanh^2x} \ \text dx$

$$ \int_0^{\infty}\frac{2\left[\,x - \tanh\left(\,x\,\right)\,\right]} {\sinh\left(\,x\,\right)\tanh^{2}\left(\,x\,\right)}\,\mathrm{d}x $$ I know that the answer is $\pi^{2}/4$. I tried to change $\sinh\left(\,x\,\right)$ and…
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For what value does $\int_0^{\infty} \frac{1-\cos x}{x^a} dx$ converge?

My question is for what realnumber $a$ does this converge? $$\int_0^{\infty} \frac{1-\cos x}{x^a} dx$$ I want a specific proof for this. Thanks in advance!
lacm
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Existence/Limit of Improper Integral

I got the improper integral: $$ \int_0^\infty \frac{x^2}{x^4+1} \, dx $$ On one hand one could of course just evaluate the integral and then apply limits. However, it's not always practical to find an antiderivative. I got a hint that one can trace…
johnka
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Does $\int_{-\infty}^{\infty} \sin(t) \,dt $ converge?

Does $\int_{-\infty}^\infty \sin(t) \,dt $ converge or diverge? How would I prove it? Should I use 'principle value' to do: $$\lim_{a \to \infty} \int_{-a}^a \sin(t)\,dt$$
21rw
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Does $\int_1^2\frac{\sin{x}}{\log{x}} \, dx$ converge?

I tried to use the absolute convergence test. $$\int_1^2\left|\frac{\sin{x}}{\log{x}}\right| \, dx<\int_1^2\left|\frac{1}{\log{x}}\right| \, dx$$ but I'm not sure whether $\frac{1}{\log{x}}$ converges or not. Thanks in advance!
user21312
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Improper integral over an open interval using the comparison test

I'm getting confused with improper integral over a closed interval it seems to me like the opposite of improper integrals when x tends to infinity. Example: $\int_0^1 \frac{sin^2x}{x^2}$ I can see that the integral is an improper integral when $x…
user21312
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Simplifying a ratio of integrals

I'm doing theoretical economics, and after a few computation I end up with a ratio of two integrals in one of my model. The function being integrated is the same, but the bounds are different. It goes as the…
Louis. B
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Improper integral $\int\limits_0^\infty x\exp (-x-x^2)\,\text dx$

Integrate $\int\limits_0^\infty x\exp (-x-x^2)\,\text dx$ Hint: Use $\int\limits_0^\infty \exp (-x-x^2)\,\text{d}x = 0.4965$ I don't know how to use this hint in solving the integration. Help!
L.mak
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