Questions tagged [improper-integrals]

Questions involving improper integrals, defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

An improper integral is defined as the limit of a definite integral as an endpoint of the interval of integration approaches either a specified real number or $\infty$ or $-\infty$, or as both endpoints approach limits.

Specifically, an improper integral is a limit of the form:

$$\lim_{b\to \infty} \int_{a}^{b} f(x) \ dx \,,\ \lim_{a \to -\infty} \int_{a}^{b} f(x) \ dx$$ or of the form $$\lim_{c \to b^{-}} \int_{a}^{c} f(x) \ dx \,,\ \lim_{c \to a^{+}} \int_{c}^{b} f(x) \ dx$$

in which one takes a limit in one or the other (or sometimes both) endpoints.

Often, we can compute values for improper integrals, even when the function cannot be integrated in the conventional sense (as a Riemann integral, for instance), because of a singularity in the function or because one of the bounds of integration is infinite.

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Rewrite $\int\limits_{x=0}^\infty{2\sqrt{a -\frac{b}{x}}{K_1}({2\sqrt{a-\frac{b}{x}}}){x^{M-1}}\exp({-\frac{x}{c}})dx}$ as non-elementary function?

Is it possible to rewrite this integral $I=\int\limits_{x = 0}^\infty {2\sqrt {a - \frac{b}{x}} {K_1}\left( {2\sqrt {a - \frac{b}{x}} } \right){x^{M - 1}}\exp \left( { - \frac{x}{c}} \right)dx}$ as non elementary function (For exaple $Ei(x)$,…
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What does identity between convergent integral and principal values of integrals mean?

Recently I took a quiz at my school, but the sentence I saw in the quiz really confused me. This is the problem that confused me (True or False) So, I can prove that integral of sin(x)/x from 0 to infinity and -infinity to 0 are convergent with the…
john
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Comparison test for $\displaystyle \int_{1}^{\infty} x^3 \cdot e^{-x} \ dx$

I'm trying to solve a improper integral exercise. It follows: Using the comparison test determine whether the following integral converges or diverges $$\displaystyle \int_{1}^{\infty} x^3 \cdot e^{-x} \ dx$$ Given that the answer is convergent, I…
bru1987
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calculate a generalized integral

I want to calculate a generalized integral: $$\int^1_0\frac{dx}{\sqrt{1-x}}$$ I have a theorem : if $f(x)$ is continuous over $[a,b[$ then: $$\int^b_af(x).dx = \lim_{c\to b⁻}\int^c_af(x).dx$$ if $f(x)$ is continuous over $]a,b]$…
Croviajo
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Values of $p$ for an improper integral to converge

I am trying to find values of $p \in \mathbb{R}$ such that $\displaystyle\int_0^{+\infty} x^p\sin(e^x)$ converges. All I have managed doing is using reduction formulas but I couldn't reach a result. Any ideas?
Nikos127
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Integral $\int_{0}^{1}{\frac{\exp(-rx)}{\sqrt{1-x}}dx}$ converges for $r\geq{1}$

How do you prove that $\int_{0}^{1}{\frac{\exp(-rx)}{\sqrt{1-x}}dx}$ converges for $r\geq{1}$ ? N.B. : I forgot everything about improper integrals, so please be very explicit :)
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Improper integral of $|x|^{-\alpha} |y|^{-\beta}$ in $\mathbf R^n \times \mathbf R^m$

I am looking for a higher-dimensional analogue of the convergence of the improper integral $\int_{x \geq 1} x^{-\alpha}dx$. To be more precise, I want to understand under what conditions on $\alpha, \beta > 0$, the integral $$\int_{\mathbf R^{n+m} …
QA Ngô
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finding convergence of integral having exponential and cosine terms

Finding whether the series $$\int^{\infty}_{1}e^{x}\cos (x)\cdot x^{-\frac{1}{2}}dx$$ converges or diverges. What i try:: $$I=\int^{\infty}_{1}e^{x}\cos(x)\cdot x^{-\frac{1}{2}}dx\leq \int^{\infty}_{1}e^{x}\cdot x^{-\frac{1}{2}}dx$$ Now put…
jacky
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Improper integral convergance and absolute convergance

I have this integral $$ \int_{0}^{1}f(t)dt $$ where $$f(t)=(-1)^n \cdot n$$ for $$\frac{1}{n+1}< t\leq \frac{1}{n}, n\epsilon \mathbb{N}$$ I have to show that is converges but does not converge absolutely. I started like this $$D=\left \{ t:0<…
Awerde
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the convergence of$\int_{0}^1 \frac{(1-x^2)^{\alpha}}{\sqrt{x}} dx$

I have to analyse the convergence of the improper integral, for different values of $\alpha$: $\int_{0}^1 \frac{(1-x^2)^{\alpha}}{\sqrt{x}} dx$ I think that when $\alpha$ is bigger or equal to $0$, the improper integral is convergent, but when…
User160
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How to prove that the improper integral $\int_0^{+\infty}\sin(\frac{\cos(x)}{\sqrt{x}})dx$ is convergent.

The integral $$\int_0^{+\infty}\sin(\frac{\cos(x)}{\sqrt{x}})dx$$ is convergent near $ 0$ since the integrand is bounded. But near $+\infty $, i cannot use comparison test, as the sign is changing. Thanks in advance for any idea.
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how to show $\int_{1}^{\infty}\frac{(\log x)^a}{x^p}\,dx$ is improper integrable

how to show $\int_{1}^{\infty}\frac{(\log x)^a}{x^p}dx$, if $p \gt 1$ and $a \gt 0$???. I can show this is not improper integrable in case $p \lt 1 $, but I was stuck in showing the other case. Could you let me know how to handle it??
fivestar
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evaluation of real $k$ for which Integral Converges

Finding real value of $k$ for which the integral $$\int^{\infty}_{0}3^{(3+3k)x}dx$$ converges and finding its value, is What i try $\bullet$ If $3+3k=0$. Then $$I =\int^{\infty}_{0}1\cdot dx\rightarrow \infty(\text{Diverge})$$ $\bullet$ If…
jacky
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Improper integral: $\int_0^{+\infty} \frac{\sin x \log|x- \pi|}{x(x-1)}dx$

Can I get help determining the nature of this improper integral? (¿Podrían ayudarme a determinar el carácter de está integral impropia?) $$\int_0^{+\infty} \frac{\sin x \log|x- \pi|}{x(x-1)}$$
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Does $\int_0^0 |f(x)|\mathrm{d}(x)=0$ hold for this improper integral?

Let $f$ be Riemann integrable on $[\epsilon,b)$ for each $0<\epsilon